Biomechanica Oefeningen | Locomotorisch stelsel | UGent | 2024/2025

BIOMECHANICA




REEKS 1


oef 1
. 75
kg en 1 80.
m




HAND


m(hand) 017
0
=
75 64 k
.
=
· .
.
0




· 2(schouder-hand) =
2 Jelleboog-hand) =
10 .
6220-0 .
4313) . 1 80
.




=
0 . 34m



·

y(schouder-hand) 2)schouder-elleboog) = = (0 .
8116 -

0 .
62201 .
1 80
.




=
0 .
34m

ONDERARM
m(0 arm) 042 75
Leg
0
·
.
=
.
: 1 . 58
2


· 2(schouder-0 arm) .
=

2) elleboog -
0 .
arm) =
(0 . 6220 -
0 .
5533) ·
1 80 .
= 0 . 12 m



·
(schouder-o arm) =

2.)schouder-elleboog) =
34
g . 0 .
m




BOVENARM

%66
0
m(b arm)
.




75 2 48
beg
· = . =
. .




·
2(schouder-barm) =

yo(schouder-barm) =
o




·
(schouder-barm) = zo(schouder-barm) = (0 8116-0 7179) 1 80 =
0 17 m
y
.
. . . .




↓

, MASSACENTRUM


mChand) .
Chandl + m(o arm) .
.
<(0 . arm) + m(b arm) .
.
2(b arm) -


: =


y-as yo m/handl + m/o arm) . + m(b arm) .




0 .
64 -
0 .
34 + 1 . 58 .
0 .
12 + 2 .
48 .
0

=

0 .
64 + 1 . 58 + 2 .
48


=
0 .
087m of 8 7 .
cm




m(hand) Chandl + m(o arm) (0 arm) + m(b arm) y(b arm)
y y
- -
. .
. . .


=
X -
as Xcm
m/handl + m/o arm) . + m(b arm) .




48 .

3415834+
0 .
64 -
0 .
2 .




=




=
0 . 250 m of 25 . 0 cm




oef 2
.


0 .
5 . 80 + 3 . 40 + 4 .
10

-
X(m = = 26 .
67 cm
3 0 . 5 + 3 + 4
4
kg
10 3

1




60
0 .
5 .
20 + 3 .
10 + 4 . 60
0 5
by = = 37 33 cm
3kg y(m
.
.



0 5 + 3 + 4
0
.


- 7
1
80

40
20

-v V


*
①




oef 3
.



5 5
.
.
24 + 2 .
(1 . 9 .
36 + 1 .
1 .
62 + 0 .
5 .
80) + 40 -
28 + 2 .
(6 .
7 .
34 + 3 2
.
.
58 + 1 .
1 . 66)
X(m I
.5
5 + 2(1 . 9 + 1 1 + . 0 .
5) + 40 + 2(6 7 . + 3 2 . + 1 .
1)


= 34 .
6 cm




5 5
.
. 110 + 2 .
(1 . 9 .
92 + 1 .
1 .
95 + 0 .
5 .
98) + 40 -
52 + 2 .
(6 .
7 .
48 + 3 2
.
.
32 + 1 .
1 . 4)
Yam
=
.5
5 + 2(1 . 9 + 1 1 + . 0 .
5) + 40 + 2(6 7 . + 3 2 . + 1 .
1)


= 56 .
4 cm