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Summary Lecture Notes Vibrations and Signals | Elastic Continua | Universiteit Gent | 2025/26

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Summary chapter 8-9: elastic continua + energy method

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Course

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Part ElasticContinua
from shaft machine
Rotating
#I : :
-




Chapter 8 : Vibrations
of elastic continua


8 11 Vibrations
.




Longitudinal
↳ ocial
deformation :
g(x ,
El



↳ assumed consection I to
remains
plain ,
x-axis

has
body I corup.
a
and
eigenfree
↳ a DOF

mode shapes


2 ~
ext .


force per unit
The law newton PJX tdX
length
,

P(x
, El





JAkd =
S + -Sp SVx)
π
A 세
* 5+
:d +




mass


acc.
+
PA (x )d

Uning Hooks' law : S = Alo = AE ∞





PArA 1 = AA ) d +录 1 ← P 1x , t )




↳ assume Akx1 = A



=
PA = AE t
PS + ,ε 1




も 崎器

+




s
a



I =


propagation speed) Right traveling waves

>
-
if no load
p(x ,
) = 0-broutin is umb
of g

Left traveling waves


t) + 1
g(x g(x a
= +
,



=>
equation of motion is solved
for undamped ,
unloaded
body
natural form
of the body's
In me

free vib .
modes
,
may
take :




t) Y(x) Jai lin we bic wt)
g (x
= +
,




referred to as
eigen function

represents mode shaps
of the
body corresp .
To wi
Subst gr t im
,
wave
eg
(
.




a[yx)(ainimwt





T4Ma ; nimwt
+ bicatl) =
+ Gicawt))
-
ω㎡ 4( x ) =
@
2 *

1 +

4t 1 = 0

, = Y(x) =

Pein(x) +
& c( * x) - 3 unknowns.*
follow frm BCI

* example :
fer- fier shaft 9( ,
t) =
Y/X) (a ; nimwt + bi Cawt


- has no kinematic restrictions on BS such that no acid load S :


SA , t ) = AE =
AE SQisinwtt GiCswt )
S 10 E= SIe, )= mo oct .ocios
BC : I
force
)

0
, t


to keep it in
place I Mode y
_






앱 ] × (e ) = = 0


0 Ci 紫
= 0
= <i = 0


with
h htt =- Cider Com ex- diffline-
" hersel =o -
didline = ·




= sin 器 e = 0 =>
wid = i π




= wi
=
te ℃= §; i =
a.

= fundamental





elastic
eigenfrg. £
= Wi

not i
rigidmod
=
=
0



e
↳ ans
eigenfunctin T: (x) corup .
To
every Wi ?
Y, /) =
di Carlix) =
di
3
ca
(
just scoling <t


X






, &
example :

fixed-free
end
shaft 튿 e
x





B new read :
g10 ,
t = 0
=0 = 0 = di = 0 ㅇ




9 (x ,
t) =
Mala;limwt + b; cut)
Sleit 1 =① AE
19 = 0


)
Yor ) = Cisin { + 1 tdiCos (袋 +


β

내윙 = 0




← Ci 器 (≈ e 1 =
0
=→ ae = (2 i + u1 是

= Wi = 12 iti ) =
2i + t 花, i - 02 …




-
→ φ/A ) =
Cisin ( ( 2 i + 11 花 + )

-91, +) = limex : niMWit + : Co WE


&
example Complicated :
BI




at x 0 :
fixed 910 )
=
=> = 0
,


→ ψ10 | = 0 => di = 0




EA φ=µ
nnn
of = : SIe , GH-

eking
e A t 1 4IA ) ( Q : AIn oot tGi COWt )
9
t -
.




fra di Cos
M) =

Cinim x +




器 ( @☆ tt bi owt ]


| At
* φ (x , t) = Ain + sin ω




v [ ai un Go ω t ] ' Cas sinwt ott wa ε ]
*
器 bǒ )= nin to
ω




- t+ - +




& Et/sinwtcw) =

-Mein Freiwi

Es
EAC =
Mweinksin
AEW W =MW-klein horto be solved
numerically
to cale
eigenvals
E k
now
analyse following case : = o s no
spring
= ,
A Co = Mwanin 路 = AEE
a
=µ WI ton 路
→ =
n 路 ton 路

5
C ,
02 =




"

e
=
waton



es
n
m mae
_

e






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