ENGINEERING DEPARTMENT
R 1400 Exam 1 2026/2027 With Completed Solutions. 2026/2
ENGINEERING · Official Exam 2026/2027
75 75% CERTIFIED
QUESTIONS PASSING SCORE RECERTIFICATION
TABLE OF CONTENTS
Section 1 Engineering Problem Solving & Mathematics Q1-15
Section 2 Engineering Graphics & Technical Communication Q16-30
Section 3 Materials Science & Manufacturing Processes Q31-45
Section 4 Electrical & Electronic Fundamentals Q46-60
Section 5 Engineering Ethics, Safety & Professional Conduct Q61-75
Instructions: Select the single best answer for each question. This exam is designed for EGR 1400 Exam 1
preparation. Passing score: 75% (56 questions correct).
, SECTION 1 | Engineering Problem Solving & Mathematics | Q1-Q15 | EGR 1400 Exam 1 2026/2027 With Completed Solutions. 2026/2027 2026/2027
Q1 Question 1 of 75
A civil engineer is designing a stormwater drainage system that must handle a peak flow rate
of 12.5 cubic meters per second. The channel has a rectangular cross-section with a width of
3.0 meters and a water depth of 1.5 meters. What is the flow velocity in the channel?
A. 2.78 m/s
B. 3.33 m/s
C. 4.17 m/s
D. 1.67 m/s
Correct Answer: A
Rationale:
Flow velocity is calculated as Q/A = 12.5 / (3.0 x 1.5) = 12..5 = 2.78 m/s. Option B is incorrect because
it uses only width without multiplying by depth to get the cross-sectional area.
Q2 Question 2 of 75
An engineering team measures the tensile stress in a steel rod to be 145 MPa under a load
of 58 kN. The rod has a circular cross-section. What is the diameter of the rod?
A. 15.2 mm
B. 22.6 mm
C. 18.4 mm
D. 25.0 mm
Correct Answer: B
Rationale:
Stress = Force/Area, so Area = Force/Stress = 58000/145e6 = 4.0e-4 m^2. For a circle, A = pi*r^2, giving r
= 0.0113 m, so diameter = 0.0226 m = 22.6 mm. Option A incorrectly uses diameter instead of radius in the
area formula.
EGR 1400 Exam 1 2026/2027 With Completed Solutions. 2026/2027 -- 2026/2027 | Passing Score: 75% | Page 2 of 9999
, SECTION 1 | Engineering Problem Solving & Mathematics | Q1-Q15 | EGR 1400 Exam 1 2026/2027 With Completed Solutions. 2026/2027 2026/2027
Q3 Question 3 of 75
A mechanical engineer needs to convert a shaft speed of 2400 revolutions per minute into
radians per second for a dynamics calculation. What is the correct conversion?
A. 150.8 rad/s
B. 376.9 rad/s
C. 251.3 rad/s
D. 125.7 rad/s
Correct Answer: C
Rationale:
The conversion is 2400 rev/min x (2*pi rad/rev) x (1 min/60 s) = 2400 x 2 x 3. = 251.3 rad/s.
Option A forgets to multiply by 2*pi, and option B forgets to divide by 60.
Q4 Question 4 of 75
A structural beam is subjected to a bending moment of 8500 N-m. The beam has a
rectangular cross-section of 120 mm by 60 mm. What is the maximum bending stress if the
beam is oriented with the 120 mm dimension vertical?
A. 88.5 MPa
B. 44.3 MPa
C. 29.5 MPa
D. 59.0 MPa
Correct Answer: D
Rationale:
The section modulus S = bh^2/6 = (0.06 x 0.12^2)/6 = 1.44e-4 m^3. Maximum bending stress = M/S =
8500/1.44e-4 = 59.0 MPa. Option A incorrectly uses h^3 instead of bh^2/6 in the section modulus.
EGR 1400 Exam 1 2026/2027 With Completed Solutions. 2026/2027 -- 2026/2027 | Passing Score: 75% | Page 3 of 9999
, SECTION 1 | Engineering Problem Solving & Mathematics | Q1-Q15 | EGR 1400 Exam 1 2026/2027 With Completed Solutions. 2026/2027 2026/2027
Q5 Question 5 of 75
A chemical process operates at a temperature of 350 degrees Fahrenheit. The plant control
system requires the temperature input in Kelvin. What is the equivalent temperature in
Kelvin?
A. 449.8 K
B. 422.0 K
C. 177.4 K
D. 623.2 K
Correct Answer: A
Rationale:
First convert F to C: (350 - 32) x 5/9 = 176.7 C. Then convert C to K: 176.7 + 273.15 = 449.8 K. Option B
adds only 245 instead of 273.15 to the Celsius value. Option D incorrectly adds 273.15 directly to the
Fahrenheit value.
Q6 Question 6 of 75
A manufacturing line produces 850 parts per shift with a defect rate of 4.2%. Quality control
wants to know how many acceptable parts are produced per shift on average.
A. 832 parts
B. 814 parts
C. 798 parts
D. 822 parts
Correct Answer: B
Rationale:
Acceptable parts = 850 x (1 - 0.042) = 850 x 0.958 = 814.3, rounded to 814 parts. Option A uses the defect
rate as 2.0% instead of 4.2%. Option C subtracts 4.2% of 1000 instead of 850.
EGR 1400 Exam 1 2026/2027 With Completed Solutions. 2026/2027 -- 2026/2027 | Passing Score: 75% | Page 4 of 9999