Solution Manual for Fundamentals of Electric Circuits (7th Edition) by Alexander and Sadiku – Full 19 Chapters Solutions

Chapter 1, Solution 1

SOLUTION MANUAL FOR FUNDAMENTALS OF
ELECTRIC CIRCUITS 7TH EDITION BY
ALEXANDER

,Chapter 1, Solution 2



(a) q = 6.482x1017 x [-1.602x10-19 C] = –103.84 mC

(b) q = 1. 24x1018 x [-1.602x10-19 C] = –198.65 mC

(c) q = 2.46x1019 x [-1.602x10-19 C] = –3.941 C

(d) q = 1.628x1020 x [-1.602x10-19 C] = –26.08 C


(a) i = dq/dt = 3 mA
(b) i = dq/dt = (16t + 4) A
(c) i = dq/dt = (-3e-t + 10e-2t) nA
(d) i=dq/dt = 1200 cos120 t pA
(e) i =dq/dt = − e−4t (80 cos50t + 1000 sin 50t)  A

,Chapter 1, Solution 3

(a) q(t) =  i(t)dt + q(0) = (3t + 1) C

(b) q(t) =  (2t + s) dt + q(v) = (t 2 + 5t) mC
(c) q(t) =  20 cos (10t +  / 6) + q(0) = (2sin(10t +  / 6) +1)C

10e -30t
q(t) = 10e -30t sin 40t + q(0) = (−30 sin 40t - 40 cos t)
(d) 900 + 1600
= − e - 30t (0.16cos40 t + 0.12 sin 40t) C

, Chapter 1, Solution 4

q = it = 7.4 x 20 = 148 C