Correct Answers with Complete Solutions | Human Anatomy
& Physiology I & II | Comprehensive Final | Clinical
Correlations | Pass Guaranteed - A+ Graded
Domain 1: Basic Chemistry & Biochemistry (8 Questions)
Q1: A patient with metabolic acidosis has a blood pH of 7.25. Which of the following
best describes the hydrogen ion concentration relative to normal pH 7.4?
A. Decreased by 2 times (incorrect direction)
B. Decreased by 10 times (incorrect direction)
C. Increased by approximately 1.5 times (correct: pH = -log[H⁺], each 0.1 pH unit change
≈ 1.26× [H⁺] change; 7.4 to 7.25 = 0.15 difference, [H⁺] increases ~1.4×, closest to 1.5×)
[CORRECT]
D. Increased by 100 times (would be 2 full pH units)
Correct Answer: C
Rationale: The pH scale is logarithmic (base 10): pH = -log[H⁺]. A decrease of 1 pH unit
means 10× increase in [H⁺]. From pH 7.4 to 7.25 is a 0.15 unit decrease. Using the
formula: [H⁺] = 10^(-pH). Ratio = 10^(-7.25)/10^(-7.4) = 10^(0.15) ≈ 1.41. Thus [H⁺]
increases ~1.4-1.5 times. This modest change significantly impacts protein function
and enzyme activity. Option A and B suggest decreased acidity; Option D would
represent a change to pH 5.4, which is incompatible with life.
Q2: Which type of chemical bond involves the sharing of electron pairs between atoms,
forming the strongest bonds in biological molecules?
A. Ionic bond (electrostatic attraction, weaker in aqueous environments)
,B. Hydrogen bond (intermolecular, weak, important for water and DNA structure)
C. Covalent bond (correct: electron sharing, strong, forms backbone of organic
molecules, can be polar or nonpolar) [CORRECT]
D. Van der Waals forces (transient dipoles, very weak)
Correct Answer: C
Rationale: Covalent bonds involve electron sharing between atoms, with bond energies
of 80-400 kJ/mol. They form the stable backbone of biological macromolecules: C-C
and C-H bonds in lipids, peptide bonds in proteins, phosphodiester bonds in nucleic
acids, and glycosidic bonds in carbohydrates. Single bonds allow rotation; double bonds
are rigid. Ionic bonds (A) are strong in vacuum but weaken in water (dielectric constant
~80); hydrogen bonds (B) stabilize secondary structures but are individually weak; van
der Waals forces (D) are transient attractions.
Q3: Which organic compound is the primary energy source for cellular metabolism and
is classified as a monosaccharide with the formula C₆H₁₂O₆?
A. Glycogen (polysaccharide, storage form, not a monosaccharide)
B. Glucose (correct: hexose monosaccharide, primary cellular fuel, blood sugar,
glycolysis substrate, C₆H₁₂O₆) [CORRECT]
C. Starch (polysaccharide, plant storage)
D. Cellulose (polysaccharide, structural, indigestible by humans)
Correct Answer: B
Rationale: Glucose is a six-carbon aldohexose, the central molecule in energy
metabolism. It enters cells via GLUT transporters (insulin-dependent or independent)
and undergoes glycolysis → pyruvate → Krebs cycle → oxidative phosphorylation,
yielding ~30-32 ATP. Blood glucose is tightly regulated (70-100 mg/dL fasting) by
insulin (lowers) and glucagon (raises). Glycogen (A) is the storage polymer; starch (C) is
,plant storage; cellulose (D) is β-1,4-linked structural polysaccharide humans cannot
digest.
Q4: Which property of water is most important for its role as a biological solvent and
temperature regulator?
A. Low heat capacity (incorrect, water has high heat capacity)
B. Nonpolar nature (incorrect, water is polar)
C. High heat capacity and polarity (correct: hydrogen bonding creates high specific heat
(4.18 J/g°C), high heat of vaporization, and polar nature enables dissolution of ions and
polar molecules) [CORRECT]
D. Ability to form covalent bonds with solutes (water interacts via hydrogen bonds and
ion-dipole, not covalent)
Correct Answer: C
Rationale: Water's unique properties stem from its polar covalent bonds and hydrogen
bonding: 1) High specific heat—absorbs much heat before temperature rises, stabilizing
body temperature; 2) High heat of vaporization—evaporative cooling (sweating); 3)
Excellent solvent—hydration shells around ions (ion-dipole) and hydrogen bonds with
polar molecules; 4) Cohesion and adhesion—surface tension, capillary action, transport.
These properties are essential for life. Options A and B are incorrect properties; Option
D describes incorrect chemistry.
Q5: Which class of organic compounds consists of glycerol and three fatty acids,
serving as long-term energy storage and insulation?
A. Phospholipids (two fatty acids, phosphate head, membrane components)
B. Triglycerides (triacylglycerols) (correct: esterified glycerol + 3 fatty acids,
hydrophobic, energy-dense (9 kcal/g), stored in adipose tissue, insulation, protection)
[CORRECT]
C. Steroids (four fused rings, cholesterol, hormones, not glycerol-based)
, D. Prostaglandins (eicosanoids, short-range signaling, derived from fatty acids)
Correct Answer: B
Rationale: Triglycerides are the main storage lipids. Esterification of glycerol's three
hydroxyl groups with fatty acids creates hydrophobic molecules that coalesce into lipid
droplets. Fatty acids can be saturated (no double bonds, solid at room temperature) or
unsaturated (cis double bonds, liquid). Triglycerides provide: 1) energy reserve (efficient,
anhydrous storage), 2) thermal insulation, 3) mechanical protection. Phospholipids (A)
form bilayers; steroids (C) have ring structures; prostaglandins (D) are signaling
molecules.
Q6: Which characteristic defines an enzyme's specificity for its substrate?
A. Enzyme denaturation at high temperature (general property, not specificity)
B. Induced fit and geometric/ chemical complementarity at active site (correct:
lock-and-key or induced fit models, specific amino acid arrangement creates unique
microenvironment for substrate binding and catalysis) [CORRECT]
C. Ability to catalyze all reactions in a metabolic pathway (enzymes are specific, not
universal)
D. Consumption of enzyme in the reaction (enzymes are catalysts, not consumed)
Correct Answer: B
Rationale: Enzyme specificity arises from the unique three-dimensional conformation of
the active site, where amino acid side chains create: 1) geometric complementarity
(shape matching substrate), 2) chemical complementarity (appropriate charges,
hydrophobic/hydrophilic regions), and 3) induced fit (conformational change upon
binding). This specificity allows precise metabolic regulation. Enzymes lower activation
energy but are not consumed (D). They are specific for substrates, not universal (C).
Temperature affects all enzymes (A), not specificity.