CHEM 219 Module 1 problem
set with correct questions and
answers
usr
[COMPANY NAME] [Company address]
, 1. On a piece of scratch paper, write out the Lewis Dot Diagram for each
of the indicated elements and determine the following for each Answer:
a) The number of Lone Pairs the atom possesses in its valence shell.b)
The number of Unpaired Electrons the atom possesses in its valence
shell.c) The number of bonds the atom will form.
Oxygen
Carbon
Hydroge
n
Nitrogen Answer: Oxygen - a) 2 b) 2 c) 2
Carbon - a) 0 b) 4 c) 4
Hydrogen- a) 0 b) 1 c) 1
Nitrogen - a) 1 b) 3 c) 3
2. Classify the bonding between the given pairs of atoms as ionic,
covalent, or polar covalent. Use the table of electronegativities shown
below to help with the classification.
a. Br and Br
b. K and Cl
c. P and Cl
d. C and O
e. Na and Br Answer: a. Br-Br Answer: Electronegativity ditterence () = 0 = COVALENT (or pure
covalent)
b. K-Cl Answer: () = 2.2 = IONIC
c. P-Cl Answer: ()= 0.9 = POLAR COVALENT
d. C-O Answer: ()= 1.0 = POLAR COVALENT
e. Na-Br Answer: () = 1.8 = POLAR COVALENT
3. Define the term constitutional isomer. Answer: Two (or more) ditterent chemical
compounds with the same molecular formula but ditterent connectivity between the atoms in their
structural formulae.
4. Explain (using specific evidence) what makes the following two
compounds constitutional isomers of one another Answer: Answer: Both
compounds have a MF of C3H6O - same MF. Compound "a" has a 3-carbon chain with a
C=O in the middle. No H atom connected to C of C=O.
Compound "b" has a 3-carbon chain with a C=O at the end. There is an H attached to the C of the C=O.
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8
set with correct questions and
answers
usr
[COMPANY NAME] [Company address]
, 1. On a piece of scratch paper, write out the Lewis Dot Diagram for each
of the indicated elements and determine the following for each Answer:
a) The number of Lone Pairs the atom possesses in its valence shell.b)
The number of Unpaired Electrons the atom possesses in its valence
shell.c) The number of bonds the atom will form.
Oxygen
Carbon
Hydroge
n
Nitrogen Answer: Oxygen - a) 2 b) 2 c) 2
Carbon - a) 0 b) 4 c) 4
Hydrogen- a) 0 b) 1 c) 1
Nitrogen - a) 1 b) 3 c) 3
2. Classify the bonding between the given pairs of atoms as ionic,
covalent, or polar covalent. Use the table of electronegativities shown
below to help with the classification.
a. Br and Br
b. K and Cl
c. P and Cl
d. C and O
e. Na and Br Answer: a. Br-Br Answer: Electronegativity ditterence () = 0 = COVALENT (or pure
covalent)
b. K-Cl Answer: () = 2.2 = IONIC
c. P-Cl Answer: ()= 0.9 = POLAR COVALENT
d. C-O Answer: ()= 1.0 = POLAR COVALENT
e. Na-Br Answer: () = 1.8 = POLAR COVALENT
3. Define the term constitutional isomer. Answer: Two (or more) ditterent chemical
compounds with the same molecular formula but ditterent connectivity between the atoms in their
structural formulae.
4. Explain (using specific evidence) what makes the following two
compounds constitutional isomers of one another Answer: Answer: Both
compounds have a MF of C3H6O - same MF. Compound "a" has a 3-carbon chain with a
C=O in the middle. No H atom connected to C of C=O.
Compound "b" has a 3-carbon chain with a C=O at the end. There is an H attached to the C of the C=O.
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