ASSIGNMENT 1
Question 1
Prove that
Proof:
A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C)
We prove the equality by showing mutual inclusion.
(⊆) Show that
A ∪ (B ∩ C) ⊆ (A ∪ B) ∩ (A ∪ C)
Let x ∈ A ∪ (B ∩ C).
Then either:
1. x ∈ A, or
2. x ∈ B ∩ C.
Case 1: If x ∈ A, then clearly:
x ∈ A ∪ B, and
x ∈ A ∪ C.
, Thus x ∈ (A ∪ B) ∩ (A ∪ C).
Case 2: If x ∈ B ∩ C , then:
x ∈ B and
x ∈ C.
Therefore:
x ∈ A ∪ B, and
x ∈ A ∪ C.
Thus again x ∈ (A ∪ B) ∩ (A ∪ C).
Hence,
A ∪ (B ∩ C) ⊆ (A ∪ B) ∩ (A ∪ C)
(⊇) Show that
(A ∪ B) ∩ (A ∪ C) ⊆ A ∪ (B ∩ C)
Let x ∈ (A ∪ B) ∩ (A ∪ C).
Then:
x ∈ A ∪ B, and
x ∈ A ∪ C.
Thus:
x ∈ A or x ∈ B,
x ∈ A or x ∈ C.
If x ∈ A, then clearly x ∈ A ∪ (B ∩ C).
If x ∈
/ A, then:
x ∈ B, and
x ∈ C.
Hence x∈ B ∩ C , so
x ∈ A ∪ (B ∩ C).