Solutions Manual
To Accompany
Power System Analysis And Design
Seventh Edition
J. Duncan Glover
Mulukutla S. Sarma
Thomas J. Overbye
, contents
chapter 2 1
chapter 3 27
chapter 4 71
chapter 5 95
chapter 6 137
chapter 7 175
chapter 8 195
chapter 9 231
chapter 10 303
chapter 11 323
chapter 12 339
chapter 13 353
chapter 14 379
,chapter 2
fundamentals
answers to multiple-choice type questions
2.1 b 2.19 a
2.2 a 2.20 a. c
2.3 c b. a
2.4 a c. b
2.5 b 2.21 a
2.6 c 2.22 a
2.7 a 2.23 b
2.8 c 2.24 a
2.9 a 2.25 a
2.10 c 2.26 b
2.11 a 2.27 a
2.12 b 2.28 b
2.13 b 2.29 a
2.14 c 2.30 (i) c
2.15 a (ii) b
2.16 b (iii) a
2.17 a. a (iv) d
b. b 2.31 a
c. a 2.32 a
2.18 c
1
© 2012 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
, 2.1 (a a1 = 530 = 5cos30 + j sin 30= 4.33 + j 2.5
)
−1 4
(b) a = −3 + j4 tan = 5126.87 = 5ej126.87
9 + 16
2
= −3
(c) a3 = (4.33 + j2.5) + (−3 + j4) = 1.33+ j 6.5 = 6.63578.44
(d) a4 = (530)(5126.87) = 25156.87 = −22.99 + j9.821
(e)
a5 = (530) / (5 −126.87) = 1156.87 = 1ej156.87
2.2 (a i = 400 − 30 = 346.4 − j200
)
(b) i(t) = 5sin(t + 15) = 5cos(t + 15 − 90) = 5cos(t − 75)
( 2 ) − 75 = 3.536 − 75 = 0.9151− j3.415
i = 5
(c) i = (4 2 ) − 30 + 5 − 75 = (2.449 − j1.414) + (1.294 − j4.83)
= 3.743 − j 6.244 = 7.28 − 59.06
2.3 (a vmax = 359.3 v; imax = 100 a
)
(b) v = 359.3 2 = 254.1v; i = 100 2 = 70.71a
(c) v = 254.115v; i = 70.71 − 85a
− j6 6 − 90
i = 100 = 10 = 7.5 − 90a
2.4 (a
8 + j6 − j6
1
) 8
i2 = i − i1 = 100 − 7.3 − 90 = 10 + j7.5 = 12.536.87a
v = i2 (− j6) = (12.536.87) (6 − 90) = 75 − 53.13v
(b)
2.5 (a) (t) = 277 2 cos(t + 30) = 391.7cos(t + 30)v
(b) i = v / 20 = 13.8530a
i(t) = 19.58cos(t + 30)a
2
© 2012 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
To Accompany
Power System Analysis And Design
Seventh Edition
J. Duncan Glover
Mulukutla S. Sarma
Thomas J. Overbye
, contents
chapter 2 1
chapter 3 27
chapter 4 71
chapter 5 95
chapter 6 137
chapter 7 175
chapter 8 195
chapter 9 231
chapter 10 303
chapter 11 323
chapter 12 339
chapter 13 353
chapter 14 379
,chapter 2
fundamentals
answers to multiple-choice type questions
2.1 b 2.19 a
2.2 a 2.20 a. c
2.3 c b. a
2.4 a c. b
2.5 b 2.21 a
2.6 c 2.22 a
2.7 a 2.23 b
2.8 c 2.24 a
2.9 a 2.25 a
2.10 c 2.26 b
2.11 a 2.27 a
2.12 b 2.28 b
2.13 b 2.29 a
2.14 c 2.30 (i) c
2.15 a (ii) b
2.16 b (iii) a
2.17 a. a (iv) d
b. b 2.31 a
c. a 2.32 a
2.18 c
1
© 2012 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
, 2.1 (a a1 = 530 = 5cos30 + j sin 30= 4.33 + j 2.5
)
−1 4
(b) a = −3 + j4 tan = 5126.87 = 5ej126.87
9 + 16
2
= −3
(c) a3 = (4.33 + j2.5) + (−3 + j4) = 1.33+ j 6.5 = 6.63578.44
(d) a4 = (530)(5126.87) = 25156.87 = −22.99 + j9.821
(e)
a5 = (530) / (5 −126.87) = 1156.87 = 1ej156.87
2.2 (a i = 400 − 30 = 346.4 − j200
)
(b) i(t) = 5sin(t + 15) = 5cos(t + 15 − 90) = 5cos(t − 75)
( 2 ) − 75 = 3.536 − 75 = 0.9151− j3.415
i = 5
(c) i = (4 2 ) − 30 + 5 − 75 = (2.449 − j1.414) + (1.294 − j4.83)
= 3.743 − j 6.244 = 7.28 − 59.06
2.3 (a vmax = 359.3 v; imax = 100 a
)
(b) v = 359.3 2 = 254.1v; i = 100 2 = 70.71a
(c) v = 254.115v; i = 70.71 − 85a
− j6 6 − 90
i = 100 = 10 = 7.5 − 90a
2.4 (a
8 + j6 − j6
1
) 8
i2 = i − i1 = 100 − 7.3 − 90 = 10 + j7.5 = 12.536.87a
v = i2 (− j6) = (12.536.87) (6 − 90) = 75 − 53.13v
(b)
2.5 (a) (t) = 277 2 cos(t + 30) = 391.7cos(t + 30)v
(b) i = v / 20 = 13.8530a
i(t) = 19.58cos(t + 30)a
2
© 2012 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.