100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached 4.6 TrustPilot
logo-home
Exam (elaborations)

MAT2615 Assignment 3 2026 - DUE 2026 [COMPLETE ANSWERS];100% TRUSTED WORKING

Rating
-
Sold
-
Pages
14
Grade
A+
Uploaded on
02-02-2026
Written in
2025/2026

MAT2615 Assignment 3 2026 - DUE 2026 [COMPLETE ANSWERS];100% TRUSTED WORKINGS.1. (Sections 10.1, 10.2) Consider the R 2 − R function f defined by f (x, y) = x 2 − 6x + 3y 2 − y 3 . (a) Find all the critical points of f. (The function has two critical points.) (5) (b) Use Theorem 10.2.9 to determine the local extreme values and minimax values of f. Also determine (by inspection) whether any of the local extrema are global extrema. (5) [10] 2. (Sections 2.6, and Chapter 10) Let L be the line with equation y = x − 1. Find the minimum distance between L and the point (4, 5) by using (a) Theorem 10.2.4 (5) (b) The Method of Lagrange. (5) Hints. • Minimize the square of the distance between the point (x, y) and the point (4, 5), under the constraint that the point (x, y) lies on the line L. (The required distance is a minimum at the same point where its square is a minimum.) • In order to use Theorem 10.2.4 you need to write the function that you wish to minimize as a function of x alone. (Eliminate y by using the given constraint.) • In order to use the Method of Lagrange, write the function that you need to minimize as a function of x and y and also define an R 2 − R function g such that the given constraint is equivalent to the equation g (x, y) =

Show more Read less
Institution
Course

Content preview

lOMoARcPSD|44389878

, lOMoARcPSD|44389878




MAT2615 Assignment 3 2026 - DUE June 2026 [COMPLETE ANSWERS]



Question 1

Function:

f ( x , y )=x 2−6 x +3 y 2− y 3



(a) Find all critical points of f

Critical points occur when the gradient ∇ f (x , y)=0. Compute the partial derivatives:

∂f ∂f 2
f x= =2 x−6 f y = =6 y−3 y
∂x ∂y

Set each partial derivative to zero:

1. f x =0 ⟹ 2 x−6=0 ⟹ x=3

2. f y =0 ⟹ 6 y −3 y 2=0 ⟹ 3 y (2− y )=0 ⟹ y =0 or y=2

✅ So the critical points are:

¿



(b) Classify the critical points using Theorem 10.2.9 (Second Derivative Test)

Compute the second partial derivatives:

∂2 f ∂2 f 2
∂ f
f xx = 2
=2f yy = 2
=6−6 y f xy = =0
∂x ∂y ∂x∂ y

The Hessian determinant D( x , y)is:

D( x , y)=f xx f yy −¿



Check each critical point

1. At ( 3,0 ) :

D=12−12(0)=12>0 , f xx =2> 0

✅ Local minimum.
2
f (3,0)=3 −6(3)+3 ¿

Connected book

Written for

Institution
Course

Document information

Uploaded on
February 2, 2026
Number of pages
14
Written in
2025/2026
Type
Exam (elaborations)
Contains
Questions & answers

Subjects

Get to know the seller

Seller avatar
Reputation scores are based on the amount of documents a seller has sold for a fee and the reviews they have received for those documents. There are three levels: Bronze, Silver and Gold. The better the reputation, the more your can rely on the quality of the sellers work.
THEBLAZE1 Chamberlain College Nursing
Follow You need to be logged in order to follow users or courses
Sold
701
Member since
1 year
Number of followers
173
Documents
1069
Last sold
18 hours ago

3.6

109 reviews

5
47
4
16
3
21
2
9
1
16

Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their tests and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can instantly pick a different document that better fits what you're looking for.

Pay as you like, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Frequently asked questions