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BIOD210 GENETICS | PORTAGE LEARNING | COMPLETE EXAM PACKAGE 2026/2027 Exams | Actual Questions & Verified Answers | Comprehensive Genetics Assessment | Pass Guarantee

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BIOD210 GENETICS | PORTAGE LEARNING | COMPLETE EXAM PACKAGE 2026/2027 Exams | Actual Questions & Verified Answers | Comprehensive Genetics Assessment | Pass Guarantee

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BIOD210 GENETICS | PORTAGE LEARNING | COMPLETE
EXAM PACKAGE 2026/2027 Exams | Actual Questions &
Verified Answers | Comprehensive Genetics Assessment |
Pass Guarantee




BIOD210 Exam 1: Mendelian Foundations

35 Questions | Monohybrid/Dihybrid Crosses, Probability, Pedigree Basics,
Chromosomal Inheritance



1. In garden peas, tall (T) is dominant to dwarf (t). If a heterozygous tall plant is crossed
with a dwarf plant, what is the expected phenotypic ratio of the offspring?

●​ A. All tall
●​ B. 3 tall : 1 dwarf
●​ C. 1 tall : 1 dwarf
●​ D. All dwarf

Correct Answer: C

Rationale: This is a test cross. The heterozygous tall parent (Tt) produces gametes T
and t in equal proportions (1:1). The dwarf parent (tt) produces only t gametes. The
Punnett square yields: Tt (tall) and tt (dwarf) in 1:1 ratio. Option A would result from TT
× tt; B from Tt × Tt; D from tt × tt.

,2. A true-breeding purple-flowered pea plant is crossed with a true-breeding
white-flowered plant. All F₁ offspring are purple. When F₁ plants are self-fertilized, what
proportion of F₂ plants will be true-breeding?

●​ A. 1/4
●​ B. 1/2
●​ C. 3/4
●​ D. All of them

Correct Answer: B

Rationale: P: PP × pp → F₁: all Pp. F₁ self-cross: Pp × Pp → F₂: 1 PP : 2 Pp : 1 pp.
True-breeding genotypes are PP and pp = 1/4 + 1/4 = 1/2. The 2/4 Pp are not
true-breeding.



3. In humans, the ability to taste PTC (T) is dominant to non-tasting (t). If two
heterozygous tasters have four children, what is the probability that exactly three will be
tasters?

●​ A. 3/4
●​ B. 27/64
●​ C. 9/64
●​ D. 27/256

Correct Answer: B

Rationale: Use binomial expansion: probability of taster = 3/4, non-taster = 1/4. For
exactly 3 tasters in 4 children: C(4,3) × (3/4)³ × (1/4)¹ = 4 × 27/64 × 1/4 = 108/256 =
27/64.



4. In summer squash, white fruit (W) is dominant to yellow (w), and disk-shaped (D) is
dominant to sphere-shaped (d). A WwDd plant is crossed with a wwdd plant. What
proportion of offspring will be white and sphere-shaped?

, ●​ A. 1/4
●​ B. 1/8
●​ C. 3/8
●​ D. 1/2

Correct Answer: A

Rationale: This is a test cross for two genes. WwDd produces gametes: WD, Wd, wD, wd
(1:1:1:1). wwdd produces only wd. Offspring: WwDd (white, disk), Wwdd (white, sphere),
wwDd (yellow, disk), wwdd (yellow, sphere) in 1:1:1:1 ratio. White, sphere = 1/4.



5. The probability of event A is 0.3 and event B is 0.4. If A and B are independent, what is
P(A and B)?

●​ A. 0.7
●​ B. 0.12
●​ C. 0.1
●​ D. Cannot be determined

Correct Answer: B

Rationale: For independent events, P(A and B) = P(A) × P(B) = 0.3 × 0.4 = 0.12. Option A
adds probabilities (wrong for "and"); C subtracts; D is incorrect because independence is
stated.



6. In a monohybrid cross with complete dominance, the F₂ phenotypic ratio is 3:1. What
is the expected genotypic ratio?

●​ A. 1:2:1
●​ B. 3:1
●​ C. 9:3:3:1
●​ D. 1:1:1:1

Correct Answer: A

, Rationale: F₁: Aa × Aa → F₂: 1 AA : 2 Aa : 1 aa. This is the genotypic ratio. Phenotypic 3:1
combines AA and Aa as dominant phenotype. C is dihybrid phenotypic; D is test cross
result.



7. A couple both have type A blood. Their first child has type O blood. What is the
probability their second child will also have type O blood?

●​ A. 0%
●​ B. 25%
●​ C. 50%
●​ D. 75%

Correct Answer: B

Rationale: Type A parents with type O child must both be heterozygous Iᴬi. Cross: Iᴬi × Iᴬi
→ 1 IᴬIᴬ : 2 Iᴬi : 1 ii. Each child has independent 25% chance of type O. Previous child's
blood type doesn't affect next (independent events).



8. In Drosophila, red eyes (w⁺) are dominant to white eyes (w). Which cross would
definitively determine if a red-eyed male is heterozygous or homozygous?

●​ A. Cross with red-eyed female
●​ B. Cross with white-eyed female
●​ C. Cross with heterozygous female
●​ D. Self-fertilization

Correct Answer: B

Rationale: This is a test cross. Crossing with homozygous recessive (white-eyed female,
w/w) reveals the male's genotype: if all offspring red-eyed, male is w⁺/w⁺; if 1:1 ratio,
male is w⁺/w. Other crosses give ambiguous results.

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