Questions and Answers
ISOTOPES – answer ATOMS OF THE SAME ELEMENT WITH DIFFERENT
NUMBERS OF NEUTRONS
ATOMIC (PROTON) NUMBER – answer NUMBER OF PROTONS IN THE NUCLEUS
MASS (NUCLEON) NUMBER – answer NUMBER OF PARTICLES (PROTONS &
NEUTRONS) IN THE NUCLEUS
ION – answer A POSITIVELY OR NEGATIVELY CHARGED ATOM OR (COVALENTLY
BONDED) GROUP OF ATOMS
RELATIVE ISOTOPIC MASS – answer THE MASS OF AN ISOTOPE COMPARED
WITH ON TWELTH OF THE MASS OF AN ATOM OFCARBON 12
RELATIVE ATOMIC MASS – answer THE WEIGHTED MEAN MASS OF AN ATOM OF
AN ELEMENT COMPARED WITH ONE TWELTH OF THE MASS OF AN ATOM OF
CARBON 12.
AMOUNT OF SUBSTANCE – answer THE QUANTITY OF WHOSE UNIT IS THE
MOLE. CHEMISTS USE 'AMOUNT OF SUBSTANCE' AS A MEANS OF COUNTING
ATOMS
AVOGADRO CONSTANT (NA OR L) – answer THE NUMBER OF ATOMS PER MOLE
OF THE CARBON 12 ISOTOPES (6.02x10^23 mol^-1)
MOLE – answer THE AMOUNT OF ANY SUBSTANCE CONTAINING AS MANY
PARTICLES AS THERE ARE CARBON ATOMS IN EXACTLY 12g OF THE CARBON
12 ISOTOPE
MOLAR MASS (Mr) – answer THE MASS PER MOLE OF A SUBSTANCE. THE UNITS
= g mol^-1
MOLECULE – answer A SMALL GROUP OF ATOMS HELD TOGETHER BY
COVALENT BONDS
MOLAR VOLUME – answer THE VOLUME PER MOLE OF A GAS. UNITS = dm^3
mol^-1. AT ROOM TEMPERATURE & PRESSURE, THE MOLAR VOLUME IS
APPROXIMATELY 24.0 dm^3 mol^-1
, CONCENTRATION OF A SOLUTION - answerTHE AMOUNT OF SOLUTE (IN MOL)
DISSOLVED PER 1dm^3 OF SOLUTION
STANDARD SOLUTION - answerA SOLUTION OF KNOWN CONCENTRATION.
STANDARD SOLUTIONS ARE NORMALLY USED IN TITRATIONS TO DETERMINE
UNKNOWN INFORMATION ABOUT ANOTHER SUBSTANCE.
SPECIES - answerANY TYPE OF PARTICLE THAT TAKES PLACE IN A CHEMICAL
REACTION
STOCHIOMETRY - answerTHE MOLAR RELATIONSHIP BETWEEN THE RELATIVE
QUANTITIES OF SUBSTANCES TAKING PART IN A REACTION
HYDRATED - answerREFERS TO A CRYSTALLINE COMPOUND CONTAINING
WATER MOLECULES
ANHYDROUS - answerREFERS TO A SUBSTANCE THAT CONTAINS NO WATER
MOLECULES
WATER OF CRYSTALLISATION - answerREFERS TO WATER MOLECULE THAT
FORM AN ESSENTIAL PART OF THE CRYSTALLINE STRUCTURE OF A
COMPOUND
R.A.M - answer(%MASS 1 + %MASS 2 + %MASS 3) / 100%
MOLES, n - answern = m/Mr
GAS MOLES, n - answern = V(dm3)/ 24 OR V(cm3)/24000
CONC & VOL MOLES, n - answern = c x V (in dm3)
IDEAL GAS EQUATION - answerpV = nRT (R=8.31 J K^-1 mol^-1)
% YIELD - answer100 X (actual amount in mol of product)/(theoretical amount in mol of
product)
% ATOM ECONOMY - answer100 X (molecular mass of the desired product)/(sum of
molecular masses of all products)
ACID - answerPROTON DONOR
BASE - answerPROTON ACCPETOR
ALKALI - answerTYPE OF BASE THAT DISSOLVES IN WATER FORMING OH- IONS