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A First Course in Probability – Seventh Edition by Sheldon Ross | Complete Solutions Manual Chapters 1–10

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This document provides the complete solutions manual for A First Course in Probability (Seventh Edition) by Sheldon Ross, published by Prentice Hall, Upper Saddle River, covering Chapters 1 through 10. It includes clear, step-by-step solutions and explanations for probability theory topics such as sample spaces, random variables, distributions, expectation, conditional probability, and limit theorems. The guide is ideal for exam preparation, assignments, and building a strong foundation in probability.

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Solutions Manual

IntroductionExams serve as a fundamental tool in evaluating a student's understanding of a subject, particularly in fields as diverse as business, law, and mathematics. These disciplines not only have distinct
areas of focus but also require unique approaches to assessment, with each exam testing different cognitive abilities, analytical skills, and subject-specific

A First Course in


PROBABILITY Seventh Edition




Sheldon Ross

Prentice Hall, Upper Saddle River NJ 07458

, Table of Contents
IntroductionExams serve as a fundamental tool in evaluating a student's understanding of a subject, particularly in fields as diverse as business, law, and mathematics. These disciplines not only have distinct
areas of focus but also require unique approaches to assessment, with each exam testing different cognitive abilities, analytical skills, and subject-specific




Chapter 1............................................................................... 1

Chapter 2............................................................................... 10

Chapter 3............................................................................... 20

Chapter 4............................................................................... 46

Chapter 5............................................................................... 64

Chapter 6............................................................................... 77

Chapter 7............................................................................... 98

Chapter 8............................................................................... 133

Chapter 9............................................................................... 139

Chapter 10............................................................................. 141

, Chapter 1
IntroductionExams serve as a fundamental tool in evaluating a student's understanding of a subject, particularly in fields as diverse as business, law, and mathematics. These disciplines not only have distinct
areas of focus but also require unique approaches to assessment, with each exam testing different cognitive abilities, analytical skills, and subject-specific

Problems
1. (a) By the generalized basic principle of counting there are
26  26  10  10  10  10  10 = 67,600,000
(b) 26  25  10  9  8  7  6 = 19,656,000

2. 64 = 1296

3. An assignment is a sequence i1, …, i20 where ij is the job to which person j is assigned. Since
only one person can be assigned to a job, it follows that the sequence is a permutation of the
numbers 1, …, 20 and so there are 20! different possible assignments.

4. There are 4! possible arrangements. By assigning instruments to Jay, Jack, John and Jim, in
that order, we see by the generalized basic principle that there are 2  1  2  1 = 4 possibilities.

5. There were 8  2  9 = 144 possible codes. There were 1  2  9 = 18 that started with a 4.

6. Each kitten can be identified by a code number i, j, k, l where each of i, j, k, l is any of the
numbers from 1 to 7. The number i represents which wife is carrying the kitten, j then
represents which of that wife’s 7 sacks contain the kitten; k represents which of the 7 cats in
sack j of wife i is the mother of the kitten; and l represents the number of the kitten of cat k in
sack j of wife i. By the generalized principle there are thus 7  7  7  7 = 2401 kittens

7. (a) 6! = 720
(b) 2  3!  3! = 72
(c) 4!3! = 144
(d) 6  3  2  2  1  1 = 72

8. (a) 5! = 120
7!
(b) = 1260
2!2!
11!
(c) = 34,650
4!4!2!
7!
(d) = 1260
2!2!

(12)!
9. = 27,720
6!4!

10. (a) 8! = 40,320
(b) 2  7! = 10,080
(c) 5!4! = 2,880
(d) 4!24 = 384


Chapter 1 1

, 11. (a) 6!
(b) 3!2!3!
(c) 3!4!

12. (a) 305
(b) 30  29  28  27  26

 20 
13.
 
2
 


52 
14.
 
5
 

1012
15. There are   possible choices of the 5 men and 5 women. They can then be paired up
5 5
  
in 5! ways, since if we arbitrarily order the men then the first man can be paired with any of
1012
the 5 women, the next with any of the remaining 4, and so on. Hence, there are
5!  
5 5
  
possible results.
IntroductionExams serve as a fundamental tool in evaluating a student's understanding of a subject, particularly in fields as diverse as business, law, and mathematics. These disciplines not
only have distinct areas of focus but also require unique approaches to assessment, with each exam testing different cognitive abilities, analytical skills, and subject-specific



 6  7   4
16. (a)   = 42 possibilities.
     
2 2 2
     
(b) There are 6  7 choices of a math and a science book, 6  4 choices of a math and an
economics book, and 7  4 choices of a science and an economics book. Hence, there are
94 possible choices.

17. The first gift can go to any of the 10 children, the second to any of the remaining 9 children,
and so on. Hence, there are 10  9  8    5  4 = 604,800 possibilities.

 5  6 4
18. = 600
   
 2 2 3 

8 4 8 2 4
19. (a) There are  = 896 possible committees.
      
 3  3  3  1  2
 8  4  8  2  4
There are that do not contain either of the 2 men, and there are that
      
3
  3  6 6 
(b) There are 
contain exactly 1 of them. 2 6 6
= 1000
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