WGU C784 Applied Healthcare Statistics OA
Exam – Complete Actual Exam Questions
with Verified Detailed Answers, Already
Graded A+
Official Exam Overview:
The WGU C784 OA evaluates learners’ ability to apply statistical and quantitative reasoning in
healthcare. The exam emphasizes arithmetic, order of operations, descriptive and inferential
statistics, and data interpretation for clinical and administrative decision-making.
Exam Coverage Areas:
• Order of operations and arithmetic rules
• Descriptive statistics (mean, median, mode, range)
• Probability, percentages, and distributions
• Correlation, regression, and data analysis
• Applied quantitative reasoning in healthcare contexts
QUESTION 1:
Using the rule that multiplication and division are performed left to right, solve: 64 ÷ 2 × 3
A) 32
B) 96 ✅
C) 48
D) 64
Rationale:
• Left to right: 64 ÷ 2 = 32
• Then multiply: 32 × 3 = 96
• Correct answer = B. 96
QUESTION 2:
Solve: 50 ÷ 5 × 4 using left-to-right order for multiplication/division.
A) 10
B) 40
C) 50 ✅
D) 100
,Rationale:
• Left to right: 50 ÷ 5 = 10
• Multiply: 10 × 4 = 40 ✅ Correction: Yes, 10 × 4 = 40
• Correct answer = B. 40
QUESTION 3:
If a problem only contains addition and subtraction, work from left to right. Solve: 20 − 5 + 10
A) 25 ✅
B) 15
C) 30
D) 20
Rationale:
• Left to right: 20 − 5 = 15
• Add 10: 15 + 10 = 25
• Correct answer = A. 25
QUESTION 4:
Solve using proper left-to-right rule: 100 ÷ 4 ÷ 5
A) 5 ✅
B) 20
C) 25
D) 10
Rationale:
• Left to right: 100 ÷ 4 = 25
• Then 25 ÷ 5 = 5
• Correct answer = A. 5
QUESTION 5:
Simplify: 8 × 2 ÷ 4 × 3 using left-to-right multiplication/division rules.
A) 12 ✅
B) 24
C) 10
D) 18
Rationale:
• Left to right: 8 × 2 = 16
• 16 ÷ 4 = 4
• 4 × 3 = 12
, • Correct answer = A. 12
If a problem only contains multiplication and division they are considered equal and you work
from left to right (same when the problem only contains addition and subtraction -- work it
left to right)
So: 64 divided 2 * 3 = Work it Left to right 64 divided by 2 = 32 x 3 = 96
A ??? is a positive integer with exactly two positive factors*, 11 and itself; it cannot be
divided evenly by any other two integers. For example, the only positive numbers that divide
33 are 11 and 33. Therefore, 33 is a prime number. Prime numbers play an important role in
factoring, which we will explore later in this module.
prime number
prime numbers, only 1 and itself like 29
It is a prime number. Prime numbers are always odd
Composite number
15--can divide by 1, 3, 5 so it is composite
2, 3, 5, 7 are all what type of numbers
Prime
Prime factorization
Breaking down a composite number until all of the factors are prime (like 9 is 3 and 9 )
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Mean values
The mean* is one of the most useful measures of central tendency. The mean, also known as
the average, is a single value that represents the center of a set of data values. Mean can be
substantially influenced by one or more extreme values in a data set (think skewed data), so
mean is only used when the data is symmetric. Therefore, we say that the mean is not a
resistant measure of center. So if you have 6+3+8+4 the numerical summary is 21. The "mean"
value is so 5.25 (the sum divided by however many numbers you have.
Median value
The second measure of central tendency is the median*. The median is the "halfway" point of a
set of values; an equal number of values will fall above and below the median of a data set.
Unlike the mean, the median is not overly influenced by extreme values in the data set, so we
can use the median when the data is skewed. Therefore, we say that the median is a resistant
measure of center. To properly find the median, values must be first sorted from smallest to
largest.
A union of two sets is a collection of the elements listed in both of the sets. True or False?
This is a false statement. A union of two sets is a collection of all of the elements listed in the
sets.
C={2,4,6}C={2,4,6}D={1,3,5}D={1,3,5}The union of CC and DD is {1,2,3,4,5,6}{1,2,3,4,5,6}, as
those are all of the elements that appear in the sets.
The intersection* of two sets is a collection of the elements listed in both of the sets.
For example:
E={0,10,100}E={0,10,100}F={−2,−1,0,1,2}F={-2,-1,0,1,2}The intersection of EE and FF is {0}{0}, as
00 is the only element that appears in both sets.
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