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MGSC 291 - EXAM 3 STUDY GUIDE

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MGSC 291 - EXAM 3 STUDY GUIDE

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MGSC 291
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MGSC 291

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MGSC 291 - EXAM 3 STUDY GUIDE

covariates - Answers -x - vector of inputs
bike ex: sunny, 65, etc

independent variable affected by covariate

coefficients (including the intercept) - Answers -β is your vector

constant variable affected by covariate

f( ) - Answers -link function

linear regression 𝑓(𝑥 ′𝛽) - Answers -= 𝑥 ′𝛽

logistic regression 𝑓(𝑥 ′𝛽) - Answers -= 𝑒^ 𝑥′𝛽 / (1 + 𝑒^ 𝑥′𝛽)

models a BINARY response
(y is either 0/1 or T/F)

E[Y|x] - Answers -linear regression

expected value (average/conditional mean)
value of Y given x

SLR(simple linear regression) - Answers -only 1 input of (x)

= 𝛽0 + 𝛽1x1

P(Y=1|x) - Answers -logistic regression

probability that Y is equal to 1 given x
(y=1 is the outcome of interest)

when do you use a logistic regression model - Answers -when the response has only 2
options

fit a logistic regression model - Answers -logsiticFit<-
glm(y~var1+var2...data=myData,family="binomial")

make interpretations with a logistic regression model - Answers -fit<-
glm(y~var1+var2...,data=myData,family="binomial")

predict logistic function - Answers -predict(fit,newdata,type="response")

, odds ratio (𝑒^βj) - Answers -𝑒^βj = odds(x+1) / odds(x)

tells us how the odds of success change (multiplicatively) when we increase x by 1odds
of success for our outcome of interest* know how to get this in R and how to interpret

linear model - Answers -y = β0 + β1x1

Y changes by β units for every 1 unit increase in x

log-log model - Answers -log(y) = β0 + β1*log(x1)

y changes by β% for every 1% increase in x
- β is an elasticity

log-linear model - Answers -Y changes by 100*(exp(β) - 1)% in response to 1 unit
increase in X

log(y) = β0 + β1x1
ex: log(y) = 4 + 0.31(x)
exterm-18p(0.31) = 1.3634 - 1 = 0.3634*100 = 36% increase for every 1 unit increase in
x

exp(predict( , ))

uncertainty quantification - Answers -tools needed to be able to quantify the uncertainty
in our point estimates

goal with statistical analysis: not to eliminate uncertainty, but to REDUCE and
QUANTIFY it

frequentist approach - Answers -repeatedly drawing samples of data and counting the
frequency with which an event happens
- frequency = mean of that sample
- each frequency value is calculated, and varies from sample to sample = sampling
variability

sampling distribution of means (frequencies)

different from bootstrapping bc bootstrapping resamples the original sample set of data

sample variability - Answers -different sample means values are calculated, and these
means vary from sample to sample

sampling distribution of a sample mean - Answers -the distribution of all possible
sample means (frequencies) of size n from the same population

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