, ChapterV1: MEASUREMENT
1. TheVSIVstandardVofVtimeVisVbasedVon:
A. theVdailyVrotationVofVtheVearth
B. theVfrequencyVofVlightVemittedVbyVKr86
C. theVyearlyVrevolutionVofVtheVearthVaboutVtheVsun
D. aVprecisionVpendulumVclock
E. noneVofVthes
eVAns:V E
2. AVnanosecondVis:
A. 109Vs
B. 10−9Vs
C. 10−10Vs
D. 10−10Vs
E. 10−12
Ans:V B
3. TheVSIVstandardVofVlengthVisVbasedVon:
A. theVdistanceVfromVtheVnorthVpoleVtoVtheVequatorValongVaVmeridianVpassingVthroughVPari
s
B. wavelengthVofVlightVemittedVbyVHg198
C. wavelengthVofVlightVemittedVbyVKr86
D. aVprecisionVmeterVstickVinVParis
E. theVspeedVofVlig
htVAns:V E
4. InV1866,VtheVU.VS.VCongressVdefinedVtheVU.VS.VyardVasVexactlyV3600/3937V internationalVm
eter.VThisVwasVdoneVprimarilyVbecause:
A. lengthVcanVbeVmeasuredVmoreVaccuratelyVinVmetersVthanVinVyards
B. theVmeterVisVmoreVstableVthanVtheVyard
C. thisVdefinitionVrelatesVtheVcommonVU.VS.VlengthVunitsVtoVaVmoreVwidelyVusedVsystem
D. thereVareVmoreVwavelengthsVinVaVyardVthanVinVaVmeter
E. theVmembersVofVthisVCongressVwereVexceptionallyVintelli
gentVAns:V C
5. WhichVofVtheVfollowingVisVclosestVtoVaVyardVinVlength?
A. 0.01Vm
B. 0.1m
C. 1Vm
D. 100Vm
E. 1000Vm
Ans:V C
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, 6. ThereVisVnoVSIVbaseVunitVforVareaVbecause:
A. anVareaVhasVnoVthickness;VhenceVnoVphysicalVstandardVcanVbeVbuilt
B. weVliveVinVaVthreeV(notVaVtwo)VdimensionalVworld
C. itVisVimpossibleVtoVexpressVsquareVfeetVinVtermsVofVmeters
D. areaVcanVbeVexpressedVinVtermsVofVsquareVmeters
E. areaVisVnotVanVimportantVphysicalVquan
tityVAns:V D
7. TheVSIVbaseVunitVforVmassVis:
A. gram
B. pound
C. kilogram
D. ounce
E. kilopound
VAns:V C
8. AV gramV is:
A. 10−6V kg
B. 10−3V kg
C. 1V kg
D. 103Vkg
E. 106Vkg
Ans:V B
9. WhichVofVtheVfollowingVweighsVaboutVaVpound?
A. 0.05Vkg
B. 0.5Vkg
C. 5V kg
D. 50Vkg
E. 500Vkg
Ans:V D
10.V(5.0V×V104)V×V(3.0V×V106)V=
A. 1.5V×V109
B. 1.5V×V1010
C. 1.5V×V1011
D. 1.5V×V1012
E. 1.5V×V1013
Ans:V C
11.V (5.0V×V104)V×V(3.0V×V10−6)V=
A. 1.5V×V10−3
B. 1.5V×V10−1
C. 1.5V×V101
D. 1.5V×V103
E. 1.5V×V105
Ans:V B
ChapterV1: MEASUREMENT 3
, 12.V5.0V×V105V+V3.0V×V106V=
A. 8.0V×V105
B. 8.0V×V106
C. 5.3V×V105
D. 3.5V×V105
E. 3.5V×V106
Ans:V E
13.V (7.0V×V106)/(2.0V×V10−6V)V=
A. 3.5V×V10−12
B. 3.5V×V10−6
C. 3.5
D. 3.5V×V106
E. 3.5V×V1012
Ans:V E
14. TheVnumberVofVsignificantVfiguresVinV0.00150V is:
A.V V 2
B.V V 3
C.V V 4
D.V V 5
E.V V 6
Ans:V B
15. TheVnumberVofVsignificantVfiguresVinV15.0Vis:
A.V V 1
B.V V 2
C.V V 3
D.V V 4
E.V V 5
Ans:V C
16. 3.2V×V2.7V=
A. 9
B. 8
C. 8.6
D. 8.64
E. 8.640
Ans:V C
4 ChapterV1:V V MEASUREMEN
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