Alkene reactions Study guides, Class notes & Summaries
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CHEM 210 Reactions Test Questions and Answers All Correct
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CHEM 210 Reactions Test Questions and Answers All Correct 
Describe the mechanism for the electrophilic addition of a strong acid. - Answer-Step 1) An alkene grabs a hydrogen off of a strong acid, forming a carbocation intermediate. 
Step 2) The conjugate base of the acid (an anion now) bonds to the open shell carbocation 
 
What is the regioselectivity of electrophilic addition reactions? - Answer-Markovnikov 
 
What is Markovnikov regioselectivity? - Answer-States that the major product is det...
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Chem 210 – Reactions Questions 100% Answered!!
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Chem 210 – Reactions Questions 100% Answered!! 
Reagent = Nucleophile Only - ANSWER1° = Sn2 
2° = Sn2 
3° = Sn1 + E1 (polar medium necessary) 
 
Reagent = Strong Nucleophile & Strong Base - ANSWER1° = Sn2 
2° = E2 
3° = E2 
 
Reagent = Weak Nucleophile and Weak Base - ANSWER1°/2° = No Reaction 
3°/resonance stabilized carbocation = Sn1 + E1 (polar medium necessry 
 
Reagent = Base Only - ANSWER1° = E2 or Sn2 (if unhindered and no beta-hydrogen with unhindered base) 
2° = E2 
3° = E...
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chem 210 exam 3 with all questions correctly answered
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less 
the more s character a carbocation has, the _____stable it is 
 
 
 
the same as 
when looking at an epoxide, the orientation around the oxygen is _________ the orientation around the double bond in the reactant 
 
 
 
BrOH 
when added with base makes an epoxide 
 
 
 
Br2 
adds 2 Brs in anti conformation 
 
 
 
lindlar catalyst 
produces a Z alkene from an alkyne (adds 2 Hs in syn) 
 
 
 
add more electronegative atom, add pi bond 
2 ways of producing an oxidation reaction 
 
 
 
remove e...
![Test Bank for Organic Chemistry 4th Edition by David R. Klein | 9781119659594 |2021-2022 |Chapter 1-27 | All Chapters with Answers and Rationals](/docpics/3786676/654a3a89caf74_3786676_121_171.jpeg)
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Test Bank for Organic Chemistry 4th Edition by David R. Klein | 9781119659594 |2021-2022 |Chapter 1-27 | All Chapters with Answers and Rationals
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Test Bank for Organic Chemistry 4e 4th Edition by David R. Klein. ISBN-13: 9594 Full chapters test bank PDF TABLE OF CONTENTS 1 A Review of General Chemistry: Electrons, Bonds, and Molecular Properties 1 1.1 Introduction to Organic Chemistry 2 1.2 The Structural Theory of Matter 3 1.3 Electrons, Bonds, and Lewis Structures 4 1.4 Identifying Formal Charges 7 1.5 Induction and Polar Covalent Bonds 8 1.6 Reading Bond-Line Structures 11 1.7 Atomic Orbitals 14 1.8 Valence Bond Theory 17 1.9 Molecular...
![A LEVEL CHEMISTRY EXAM WITH COMPLETE SOLUTIONS alkali - A type of base that dissolves in water forming hydroxide ions, OH- (aq) ions. alkanes - The homologous series with the general formula: CnH2n+2. alkyl group - An alkane with a hydrogen atom](/docpics/4976998/6618041e13c11_4976998_121_171.jpeg)
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A LEVEL CHEMISTRY EXAM WITH COMPLETE SOLUTIONS alkali - A type of base that dissolves in water forming hydroxide ions, OH- (aq) ions. alkanes - The homologous series with the general formula: CnH2n+2. alkyl group - An alkane with a hydrogen atom
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A LEVEL CHEMISTRY EXAM WITH COMPLETE SOLUTIONS 
 
 
 
alkali - A type of base that dissolves in water forming hydroxide ions, OH- (aq) ions. 
 
 
 
alkanes - The homologous series with the general formula: CnH2n+2. 
 
 
 
alkyl group - An alkane with a hydrogen atom removed, e.g. CH3, C2H5; alkyl groups are often shown as 'R'. 
 
 
 
amount of substance - The quantity whose unit of the mole. Chemists use 'amount of substance' as a means of counting atoms. 
 
 
 
anhydrous - A substance tha...
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chem 210 exam 3 Questions and Correct Answers, Complete Solution 2024.
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chem 210 exam 3 Questions and Correct Answers, Complete Solution 2024. 
 
less 
the more s character a carbocation has, the _____stable it is 
the same as 
when looking at an epoxide, the orientation around the oxygen is _________ the orientation around the double bond in the reactant 
BrOH 
when added with base makes an epoxide 
Br2 
adds 2 Brs in anti conformation 
lindlar catalyst 
produces a Z alkene from an alkyne (adds 2 Hs in syn) 
add more electronegative atom, add pi bond 
2 ways of pro...
![CHEM 210 Final Exam Study Guide Exam 1 Final Review Questions with Answers](/docpics/3516567/6515402dbe3e9_3516567_121_171.jpeg)
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CHEM 210 Final Exam Study Guide Exam 1 Final Review Questions with Answers
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What are the differences between aliphatic (including alkanes, alkenes,alkynes and cyclic compounds) aromatic hydrocarbons are. - ALIPHATIC Hydrocarbon: Non-aromatic 
-Alkanes & CycloAlkanes:single bonds; saturated:Contain only carbon and hydrogen & C-C & C-H single bonds 
-Alkenes:double bond(s) 
-Alkynes: triple bond(s) 
*alkenes and alkynes are unsaturated: at least one C-C double or triple bond(s) 
AROMATIC Hydrocarbon: benzene ring 
 
What is the trend in solubility and boiling point/mel...
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13.3 Elimination Reactions in Halogenoalkanes Questions with complete solution 2023/2024
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13.3 Elimination Reactions in Halogenoalkanes Questions with complete solution 2023/2024How do halogenoalkanes typically react? - correct answer By nucleophilic substitution 
 
How do halogenoalkanes react under different conditions? - correct answer By elimination 
 
How does elimination reactions occur? - correct answer A hydrogen halide is eliminated from the molecule, leaving a double bond in its place so that an alkene is formed 
 
What is the OH- ion from aqueous sodium or potassium hydrox...
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BCH 462 Exam 4 Questions With 100% Correct Answers
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BCH 462 Exam 4 Questions With 100% 
Correct Answers 
Fatty Acid Synthesis - answerFatty acids are built in several passes, processing 
one acetate unit at a time. 
The acetate is coming from activated malonate in 
the form of malonyl-CoA. 
Each pass involves reduction of a carbonyl carbon to a methylene carbon. 
Overall, repeating four-step sequence that elongates the fatty acyl chain by two carbons at each 
step, uses NADPH as the electron donor. 
Two enzyme-bound -SH groups serve as activating...
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Chem 210 – Reactions Questions 100% Answered!
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Reagent = Nucleophile Only - ANSWER1° = Sn2 
2° = Sn2 
3° = Sn1 + E1 (polar medium necessary) 
 
Reagent = Strong Nucleophile & Strong Base - ANSWER1° = Sn2 
2° = E2 
3° = E2 
 
Reagent = Weak Nucleophile and Weak Base - ANSWER1°/2° = No Reaction 
3°/resonance stabilized carbocation = Sn1 + E1 (polar medium necessry 
 
Reagent = Base Only - ANSWER1° = E2 or Sn2 (if unhindered and no beta-hydrogen with unhindered base) 
2° = E2 
3° = E2 
 
Examples of Only Nucleophiles - ANSWERCl⁻, ...
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