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ESC2C5 problem set 2 answers

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This is a comprehensive and detailed practice material on problem set 2 answers for ESC2C5. An Essential Study resource just for YOU!!










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ES2B0 ‐ Fluid Mechanics
Model Answers to Example Questions (Set II)

Question 1: Dimensional Analysis

Use dimensional analysis to determine the period t for small oscillations of a simple
pendulum (Fig. 1) of length l . Assume that the period depends on the length of the
pendulum, the mass of the oscillating body and the gravitational acceleration of the Earth.
(N.B.: You will find that the correct answer to the question will imply that the period must in
fact be independent of the mass of the oscillating body.)




Figure 1: Sketch of Pendulum Geometry

SOLUTION

Quantities involved in the problem are:
QUANTITY UNITS DIMENSIONS
t: period of oscillation [s] T

l: length of pendulum [m] L
m: mass of oscillating body [kg] M
g: gravitational  m  = [ m s 2 ] L T 2
acceleration  s 2 


Assume:
t  l   m   g
thus

, 2


 T  1   L    M     L  T 2  



such that
L0  M 0  T 1  L  M   L  T 2
and hence
L0  M 0  T 1  L   M   T 2

compare exponents to obtain:
From ‘ M ‘one gets :   0

1
From ’ T ‘ one gets : 2  1 and thus   
2

1
From ’ L ’ one gets : 0     and thus    
2

The final result is thus
1 1

t  l 2  m0  g 2


such that
l
t  const 
g

The (non‐dimensional !) constant can in principle be determined from one single experiment
or one can obtain it from some other theoretical considerations. It turns out that it has a
value of const  2  6.28

N.B.: Dimensional analysis yields the result that the period of oscillation must be
independent of the mass!



Question 2: Dynamic Similarity

The flow around an airship with a diameter d  3 m and a length l  20 m needs to be
studied in a wind tunnel. The airspeed range to be investigated is at the docking end of its
range, a maximum of v p  2 ms‐1. Calculate the mean model wind tunnel speed if the model
is made to 1/10 scale. Assume the same air pressure and temperature for model and
prototype.

SOLUTION

Dynamic similarity requires that the Reynolds number of model and prototype need to be
the same. This gives

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