Written by students who passed Immediately available after payment Read online or as PDF Wrong document? Swap it for free 4.6 TrustPilot
logo-home
Exam (elaborations)

MAT272 Test3A SP19 KEY.

Rating
-
Sold
-
Pages
6
Grade
A+
Uploaded on
28-05-2022
Written in
2020/2021

MAT272 Test3A SP19 KEY. MAT272 Test3A SP19 KEY. MAT272 Test3A SP19 KEY.

Institution
Maths
Module
Maths

Content preview

Math 272 Test 3A Spring 2019 Name: KEY

Clearly indicate your method of solution for full credit. Clearly indicate your final answers. Time limit is 100 minutes.
Non-graphing calculators allowed. (8 points)
1. Complete the following table, using DNE (does not exist) as necessary.
Sequence Increasing, Decreasing or Bounds lim 𝑎𝑛
𝑛→∞
Neither?
 1
n 1 Neither Upper: 0
an  n
, n 1 1/2 (or larger)
2


Lower:
-1/4 (or smaller)



n Increasing Upper: 1
an  , n 1 1 (or larger)
n3



Lower:
1/4 (or smaller)




2. Find the explicit formula for the 𝑛𝑡ℎ term of the sequence below.
2 4 8 16 32 
 ,  , ,  , ... (4 points)
 7 12 17 22 27 



(−𝟏)𝒏+𝟏 𝟐𝒏
𝒂𝒏 =
𝟐 + 𝟓𝒏




This study source was downloaded by 100000845196002 from CourseHero.com on 05-26-2022 14:00:48 GMT -05:00


https://www.coursehero.com/file/40300117/MAT272-Test3A-SP19-KEYpdf/

, 3. Use a convergence test of your choice to determine whether the following series converges absolutely, converges
conditionally or diverges. State the test you used and show all work. (7 points)
 1
k


k 2 ln k


Test for absolute convergence:
(−𝟏)𝒌 𝟏 𝟏
Comparison Test: |
𝒍𝒏 𝒌
| = 𝒍𝒏 𝒌 > 𝒌 (diverges)

The series does not converge absolutely.

Test for conditional convergence:

Alternating Series Test:
𝟏 𝟏 𝟏
1) 𝐥𝐧 𝒌
is decreasing since 𝐥𝐧(𝒌+𝟏) < 𝐥𝐧 𝒌
𝟏
2) 𝐥𝐢𝐦 𝐥𝐧 𝒌 = 𝟎
𝒌→∞

The series does converge conditionally.



Therefore the series converges conditionally (but not absolutely).



4. Calculate and write the partial sum of the first four non-zero terms of the Taylor Series representation of
f ( x)  e3 x centered at a  2 . (8 points)



𝒏 𝒇(𝒏) (𝒙) 𝒇(𝒏) (𝟐)
0 𝒆𝟑𝒙 𝒆𝟔
1 𝟑𝒆𝟑𝒙 𝟑𝒆𝟔
2 𝟗𝒆𝟑𝒙 𝟗𝒆𝟔
3 𝟐𝟕𝒆𝟑𝒙 𝟐𝟕𝒆𝟔


𝒆𝟔 𝟑𝒆𝟔 𝟗𝒆𝟔 𝟐𝟕𝒆𝟔
𝑻𝟑 (𝒙) = (𝒙 − 𝟐)𝟎 + (𝒙 − 𝟐)𝟏 + (𝒙 − 𝟐)𝟐 + (𝒙 − 𝟐)𝟑
𝟎! 𝟏! 𝟐! 𝟑!
𝟗 𝟗
𝑻𝟑 (𝒙) = 𝒆𝟔 + 𝟑𝒆𝟔 (𝒙 − 𝟐) + 𝟐 𝒆𝟔 (𝒙 − 𝟐)𝟐 + 𝟐 𝒆𝟔 (𝒙 − 𝟐)𝟑




This study source was downloaded by 100000845196002 from CourseHero.com on 05-26-2022 14:00:48 GMT -05:00


https://www.coursehero.com/file/40300117/MAT272-Test3A-SP19-KEYpdf/

Document information

Uploaded on
May 28, 2022
Number of pages
6
Written in
2020/2021
Type
Exam (elaborations)
Contains
Questions & answers

Subjects

£7.99
Get access to the full document:

Wrong document? Swap it for free Within 14 days of purchase and before downloading, you can choose a different document. You can simply spend the amount again.
Written by students who passed
Immediately available after payment
Read online or as PDF

Get to know the seller
Seller avatar
royalmarsden
3.0
(2)

Get to know the seller

Seller avatar
royalmarsden American InterContinental University
View profile
Follow You need to be logged in order to follow users or courses
Sold
11
Member since
3 year
Number of followers
7
Documents
375
Last sold
3 year ago

3.0

2 reviews

5
1
4
0
3
0
2
0
1
1

Trending documents

Recently viewed by you

Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their exams and reviewed by others who've used these revision notes.

Didn't get what you expected? Choose another document

No problem! You can straightaway pick a different document that better suits what you're after.

Pay as you like, start learning straight away

No subscription, no commitments. Pay the way you're used to via credit card and download your PDF document instantly.

Student with book image

“Bought, downloaded, and smashed it. It really can be that simple.”

Alisha Student

Frequently asked questions