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alternating current notes

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Detailed alternating currents notes with definitions, text, images, and additional info from 9702 past papers I have completed from , all variants

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Alternating currents
 Alternating current – current which changes in magnitude and direction
 Alternating current has sine wave characteristics




 Sine wave y-axis may represent voltage or current





 Peak to peak value – the difference between two peak values
 I = I 0sinωt where I = value of current at any time t; I 0 = Current at amplitude; and ω =
angular frequency in rad/s
 V = V 0 sinωt where V = value of voltage at any time t; V 0 = voltage at amplitude; and ω =
angular frequency in rad/s
 Cathode ray oscilloscope:
 Time base control – controls x axis, moving the waves closer of further apart
- 0.5ms/cm or 0.5ms/division
 Y gain control – controls the y axis and hence the amplitude of the waves
- 5V/cm or 5V/division
 Example –

Y- gain = 2V/cm and Time base = 5ms/cm
1. Time taken for one cycle. 5 x 4 = 20ms
2. Max voltage = 2 x 2 = 4V
3. Frequency = 1/T = 1/0.02 = 50Hz
Remember to always take exact points off the graph

,  Root mean square value of an alternating current (or voltage) is the equivalent to its direct
current value that produces the same power as the alternating current (or voltage).
 r.m.s. value gives the dc value
 the d.c voltage (or current) is about 70% of V 0 or I 0 of alternating current






I 2 always has a positive value and is much
greater than I (green dotted lines)




I2 I2
 Mean value will be , therefore r.m.s will be the root of the mean square ( ¿ so,
2 2

I = I
2
r.m.s =
√ 2 √2
 Mean value of a.c. is zero. Heating occurs in a resistor connected to a.c because heating
depends on I 2 which is always positive.
 Power, voltage, and current all vary with the mains supply (a.c.)
V2
 Power (P) = IR = I 2 R =
R
 P (a.c) = V rms x I rms
V peak I peak
= x
√2 √2
Advantage disadvantage
a.c. can be transformed to high voltages Lines must be suspended high above
so current flowing is reduced and lower ground and high-quality insulators are
power losses are incurred needed
As current flows it loses power because
of resistance and wire becomes warm

p peak
=
2

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