DSC1520
ASSIGNMENT 1 SEMESTER
1 2025
DETAILED SOLUTIONS,
WORKINGS &
EXPLANATIONS
UNIQUE NUMBER: 158619
[Document subtitle]
Abstract
[Draw your reader in with an engaging abstract. It is typically a short summary of the
document.
When you’re ready to add your content, just click here and start typing.]
Laudabletask1
[Email address]
,M = (Y2 - Y1) / (X2 - X1)
M = (70 - 40) / (20 - 10)
M =
M=3
.
, Now That We Have The Slope, We Can Use One Of The Points And The Slope To
Solve For The Y-Intercept (B). Let's Use The Point (10, 40):
40 = 3(10) + B
40 = 30 + B
B = 40 - 30
B = 10
So The Equation For The Linear Relationship Between C And
Q Is: C = 3Q + 10
Now We Can Find The Cost Of Producing 35
Units: C = 3(35) + 10
C = 105 + 10
C = 115
Therefore, The Cost Of Producing 35 Items Is R115.
ASSIGNMENT 1 SEMESTER
1 2025
DETAILED SOLUTIONS,
WORKINGS &
EXPLANATIONS
UNIQUE NUMBER: 158619
[Document subtitle]
Abstract
[Draw your reader in with an engaging abstract. It is typically a short summary of the
document.
When you’re ready to add your content, just click here and start typing.]
Laudabletask1
[Email address]
,M = (Y2 - Y1) / (X2 - X1)
M = (70 - 40) / (20 - 10)
M =
M=3
.
, Now That We Have The Slope, We Can Use One Of The Points And The Slope To
Solve For The Y-Intercept (B). Let's Use The Point (10, 40):
40 = 3(10) + B
40 = 30 + B
B = 40 - 30
B = 10
So The Equation For The Linear Relationship Between C And
Q Is: C = 3Q + 10
Now We Can Find The Cost Of Producing 35
Units: C = 3(35) + 10
C = 105 + 10
C = 115
Therefore, The Cost Of Producing 35 Items Is R115.
