All Solutions for Gasturbine Performance

Gasturbines
performance Questions

,Week 3 Turbojet

OQ 8. 2.1



I =
15°C = 288 A. Vs .
A, =
f- Vz -




Az
V, = 315 mis 4,5 =
Pa -

Vz Az .




Pz = 1.35bar Pz

Vz =
46 mis Pz =
=




Ín =
4,5kg IS VI -
VI 3152 -
462
Tz Is
=
288 -1 336,313
9/1 Kg t
-

=
( K)
-




p = 1005 .
=
2. (p 2- 1005
R
287911kg K)
= '




g. =
1135.1051-2
B-
.
R
=

336,313.287
=
1,398647
in 4,5
Az =
0.6994
-




= =
-




B. Vz 1398647 .

46
1 -




d =
Wto =

0,298 m




OQ 8. 2.2 .




17=0.80 bar W= -

Dho = -
Dh -


DER

Tr = 10 °C =
283K

Pz = 5,5bar W= -
ni ( .
( Tr -
Tr ) -
E ni .
VI -

f- ni .
V,
'

p
.




Tz = 300°C =
573k zin =
f- Vs -
Az
V, 155 MIS
0,8 -105
=
p,
A
'
Pr =
0.8077 Kg/m
}

0,0090M
= =

¥0
=




Vz = 240 MIS

K) DI 0,8077
(v =
700 Jllkg = 155 0,0090=1,1267 Kg Is
.
- .




R = 350 ) / ( kg -

r ) (p = R -

(~ = 350 +700 = 1050




I. Iri
'
DER =
vi. ui -
-
k =



E- 111267.2402 -
} 1,1267-
. 1552 =
18914 , 47625


✓ = -


1,1267 -

1050 .
(573 -

283 ) -




18914,47625
=
362007)
-

, OQ 8. 3. 1. a .




[ = 325 K Rs = (
p
-

(v

7th = 34% Cv =
71831kg -
K)

In
410kGBP
=



= 80MW f =
In =
1,4

op = 1005
JURG -
r)


PEP
1
4,28
Rs 287 Itr k)
=
= 0,34=1 -




OQ 8. 3. 1. b .




1

Pff 4,5165
t
1-2=280
=
k 0,35=1 -




7th = 35 % =
0,35

zin

350KGBP
=


""
= 70MW Tos =
( 4.5165 ) . . . .
°
280 = 430,77
(p = 1005
JURG r ) 7

Ja
-




70
R =
287911kg r) -
tho =
=
5 =

2,00 -108 ING
(v =
718911kg .rs Sho
✓ 14
Jllkg r) Ton -103 999k
=
= .
=




OQ 8. 7.1


TAS = 310 MIS DER = I. in .

ik
'
-
I. ni .kz
(j = 1050 MIS = I. 95 -

1050
'
-
I 95 - -
310
'




ni =
95kg Is Q =
(42000-103)-2,4 =


Ff
2,4kg Is t.95-1058-%95.rs
=




0,47g
42000
Rhg ga
=
Hoe = =
=

( 42000.103) -2,4




ij
ij