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TSI Math Test Preparation Questions with Correct Solutions

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Janet makes homemade dolls. Currently, she produces 23 dolls per month. If she increased her production by 18%, how many dolls would Janet produce each month? - ANSWER -First, calculate 18% of 23. 23 × 0.18 = 4.14 Then, add this value (the increase) to the original value of 23. 23 + 4.14 = 27.14 Rounding off, we get 27. What is the formula for Area? - ANSWER -Area = L*W Bill's new porch is rectangular, with an area of 50 square feet. If the length of the porch is two times the width, what is the perimeter of the porch? - ANSWER -The formula for the area of a rectangle: A = Width * Length From the question we know that L = 2W and that A = 50. So we can plug thes

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TSI Math Test Preparation Questions with Correct Solutions
Janet makes homemade dolls. Currently, she produces 23 dolls
per month. If she increased her production by 18%, how many
dolls would Janet produce each month? - ANSWER -First, The yard behind Cindy's house is rectangular in shape and has
calculate 18% of 23. a perimeter of 72 feet. If the length L of the yard is 18 feet longer
23 × 0.18 = 4.14 than the width W of the yard, what is the area of the yard, in
Then, add this value (the increase) to the original value of 23. square feet? - ANSWER -Area= L*W
23 + 4.14 = 27.14 Perimeter= 2l + 2w
Rounding off, we get 27. L = W + 18 = 9+ 18 = 27

72 = 2 ( W+18) = 2w
72 = 2w+ 36+ 2w
What is the formula for Area? - ANSWER -Area = L*W 72 = 4w + 36
36/4 = 4w/4 ----> 9= W
27* 9 = 243
The answer is 243
Bill's new porch is rectangular, with an area of 50 square feet. If
the length of the porch is two times the width, what is the
perimeter of the porch? - ANSWER -The formula for the
area of a rectangle: There are 20 children in the cast of a class play, and 8 of the
children are boys. Of the boys, 4 have a speaking part in the
A = Width * Length play, and of the girls, 8 do not have a speaking part in the play.
If a child from the cast of the play is chosen at random, what is
From the question we know that L = 2W and that A = 50. So we the probability that the child has a speaking part? -
can plug these values into our equation and solve for W: ANSWER -Boys + girls = 20 8 of the children are boys +
12 girls = 20 the boys have 4 speaking parts and 4 do NOT
50 = W * L have a speaking part. And of the girls 4 have a speaking part,
50 = W * 2W but 8 of the girls do NOT have a speaking part. all of that added
50 = 2W² up should give you 20. 8 out of 20 have a speaking part, so we
W² = 25 write that in a fraction form reduce it down which gives you the
W=5 answer: 2/5

We know that L = 2W, so L = 10
Perimeter = 2L + 2W
Perimeter = 2 * 10 + 2 * 5 There are 20 children in the cast of a class play, and 8 of the
Perimeter = 30 children are boys. Of the boys, 4 have a speaking part in the
play, and of the girls, 8 do not have a speaking part in the play.
If a child from the cast of the play is chosen at random, what is
the probability that the child has a speaking part? -
Diego's current age is five times Martina's age ten years ago. If ANSWER -Boys + girls = 20 8 of the children are boys +
Martina is currently m years old, what is Diego's current age in 12 girls = 20 the boys have 4 speaking parts and 4 do NOT
terms of m? - ANSWER -Martina's age ten years ago is: have a speaking part. And of the girls 4 have a speaking part,
m − 10 but 8 of the girl do NOT have a speaking part. all of that added
up should give you 20. 8 out of 20 have a speaking part, so we
So Diego's age is: write that in a fraction form reduce it down which gives you the
5(m − 10) answer: 2/5
= 5m − 50


A ball was kicked into the air from a balcony 20 feet above the
The variables x and y are directly proportional, and y = 2 when x ground, and the ball's height above the ground, in feet, t
= 3. What is the value of y when x = 9? - ANSWER -Y= seconds after the ball was kicked was h(t) = 20 − 16t2 + 32t.
K*X What was the maximum height, in feet, of the ball above the
2= K*3 ground after it was kicked? - ANSWER -h(t) = 20-16t^2 +
2/3 = K*3 /3 32t
K = 2/3 h(t) = -16t^2 +32+20
Plug in K for the second formula
Y=2/3(9) x= -b /2a = -(32)/2(-16) = -32/-32 = 1
Y = 2*3 = 6 Plug one in the original equation.
The correct answer is 6 h(1) = -16(1)^2 +32+20
= -16+32+20

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