UTA Math 2326 Exam 2 Questions with Correct Answers | Updated (100% Correct Answers)UTA Math 2326 Exam 2 Questions with Correct Answers | Updated (100% Correct Answers)

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UTA Math 2326 Exam 2 Questions with
Correct Answers | Updated (100% Correct
Answers)
What is the procedure for locating absolute maximum and
minimum values on a closed bounded domain R? Answer:
Determine the values of the function at all critical points in R. Then
find the maximum and minimum values on the boundary of R. The
greatest of these values is the absolute maximum on R, and the
least of these is the absolute minimum.

How to numerically find the critical points of function f(x,y) Answer:
You take fx(x,y) and fy(x,y) and set them to 0 to find what x and y
needs for that to work

How to find if there is a local maximum, local minimum, or saddle
point and what that point is. Answer: Find D(x,y)=fxx(x,y)fyy(x,y) -
(fxy(x,y))^2 at the critical point (a,b)

if D(a,b)>0 and fxx(a,b)<0 then there is a local max at (a,b)

if D(a,b)>0 and fxx(a,b)>0 then there is a local minimum at (a,b)

if D(a,b)<0 then f has a saddle point at (a,b)

if D(a,b)=0 then the result is inconclusive



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