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Digital download I have achieved a first-class in Math by taking these notes. First-year uni math notes in SMA for those who struggle through the course or for uni applications interview. Hope can help you pass the exam Cheers

Instelling
Vak

Voorbeeld van de inhoud

, Topic I
1. 1 Real numbers ,
Algebraic manipulations
Number field :




Real numbers ,
IR : All numbers I e.
go.li
2 it , } ,
- I - . .

I




Integers , 2 : positive ,
negative integers
and zero f- . .
-3 ,
-2 ,
-1
,
a , I ,
2,3 - . .


}

Non -



negative integers , IN :
positive integers
and zero
f o
,
I , 2,3 . - .




}
Operations :





Add att defined for
- subtract a- to all red a and I

at
Multiply





-

Division £ defined for all real a and b- ,
except
tota


Comparisons :




acts a > hi , ast A7T att
, , ,




shorthand :


"


a = a. a -
a - . .
a for all real a
,
HE IN and N 70
-
n times


. [ =/ for a f- 0

X x-

y
As when a -_ a
I = a

a× f- is undefined .




Ix I
?
=



× '
i. do is undefined yet

-




i. = a =
I


Summations
I -2
, proof by induction

Summations :



¥2 nlhtll 12h41 )
'

j =


Mtn ) 1+2+3-1 .tn ? ,
i. = . .

6

M In ) = 1+2+3-1 . . . th n
hlhtl )
I
Mint htlh 1) 1- In -21 -1 + I j =

2
j= ,
= -
.
. .




a. Min) = Intl ) -14+111-4+1 ) + . . . -1 ( htt )

n times

hlhtl )
i. Min ) =

2



z
Summation Notation :


II
.




flk )

fill + f- 121 + f- 13 ) + . . .
+ flkl is written as ,



.
More
generally we define , for a ,t integer acts

II. aflkl =
flat + flat 't + . .
.
+ fitt

properties
• :



of label
Independent
:
1




eflkl =
IIe till =
¥Ea f- I

' '

k l called
, , is a
dummy
hmm
index


② off
peel terms :




II.afoot =
flkl + fitt

=
flat -1 . .
.
+ fib -
It

3 We can shift the label :




II. f- 1kt =
II ,
fit - thi ) =
f Im -
a) = final + flattest . . .




+ f- latte -
a)
= flat -14111 . - .
=
f- 155-55) + fltb-551
+ f- 114 f- . -

tf 165-55)

, 22
j⇐
' '


't
'


Example pin ) I + + t n
j
=
• : = o . . .




works for
only
Proof by induction :
integers

Suppose we want to
prove that same result is true for all +
integers ,
h .
If it can be shown that the



result holds for n=I and also that ,
for all N71 , if the result is true for n = N , then it must also


be true for n = Ntl , then follows that the result is true for all
positive n



Inland )
:=€=a for
'
Qin )
k equal Intl )
negative integer
=

Prove that pin ) is to :
any non n
Question
-
.

:




i. = stands for a
definition
0
' z


when n =
0 pie) = [ok = a = a



Q a) =
to 1410+1110-11 ) = 0 i. 1710 ) =
Q lol i . True for h= 0


i. Pll) = QU )


True for h =/

Assume it is true for n=N

i. PIN ) = QIN )

when n= Ntl when u = Ntl

PINHI = ET bi
① 1µg =
LNHI 121*1+11 IN -11+1 )
k= I
'
6
= FINI t Will =
to IN -11 ) 12N -13 ) IN -14
'

=
QINI + IN -111
2

=
IN IZNHIINH ) 1- IN -111 i. PINT ) = QI Ntl)

= '
Ntl ) ( IN lsNH ) + IN-111 ) since true for n=o ,
then it is t ru e for all IN

=
INH ) I NL2N-1II -161N -111 )
=
to INH ) I ZN2-1TN -16 )
= to IN -11112 # 3) IN -12 )


General template
:



all E IN
Claim f- In )= gin ) for n



proof : .
show f- lot =
gio )
-

show that for n
any
i




if f- In ) =
gun) ,
then final =
glntl )



1.3 Binomial theorem

Binaural coefficients :




i.
Definition Factorial function : n ! = 1×2×3 × . . . X In 2)
-
X In -
1) X h ,
h E IN
ht
0 ! =
I In -11 ! =
n i . It -11 ! = = I = 0 !


Factorial function is
only defined for -heintegemm






Factorial function is never zero




Binomial coefficient
2.
Definition :



For all h .
k E IN , h 7k ,

-
h

(1) with)
I


Ck
'

n choose k =

!
=




> .
Pascal 's triangle :




.to/--lnn/-- I

n!
proof :
(2) =
d. in -4 ! =
I
h !
(1) =

h ! In -
n ) !
=
I

i. 141=111






properties of Pascal 's
triangle
:





symmetry :
121=11 )

, h !
proof :
II ) =

k :( n -
KI !


(Ik )
n !
=

i. in -
ntkl !
=

4-kl ! k !
= II )

② I 1) = III ) + 1hL ) ,
For all in > k -
the number is the sum of two numbers above

k > o


In-1 ) ! In-11 !

Proof :
RHS =

µ -11 ! In -1 htt ) !
-
X k ! In -
I -
kl !


In -11 ! In -

1) !
As In k ) ! (n k-11 ! In k )
=
+
-
-
=
1k -11 ! 1h kl ! k ! In tkl !
-


- -




In -11 ! In -11 !
= +

1k -11 ! In -
tell ! Intel klk-11 ! In k -11 ! -




kin -11 ! + In-11 ! In k ) -


=



klk-11 ! In k -11 !
-
In - k)

= h In -11 !

talk-11 ! In -
k -
1) ! In k -
)

!
%)
n
=

In )
=
I box hand
k ! - k
II
-
The little on the
right
'
of proof
'
side means end



Binaural Theorem :




i. Binaural Theorem :
For any non -


negative integer IN
, nza


-1121
"
171 't -111)a" th
"

't
" " " ' "

(att ) =
a + a a + . . .
t . .
. + to

=
If (1) a
"-
kfk
-
Binaural coefficient

Question :
Express (text 't IHX 15 as a
polynomial in ×

'
HX15 5) 1+5×+10×2 -110×7+5×4 -1×5 )
'

4- X ) + I =
(I -5×+10×2 - lax -15×4 -
+ + I


= 21 It 10×2+5×4 )

induction
proof by
:
:
a.




• when n = 0
,




II. "kt_
'


4th ) =
I
,
IL) a 111111111=1

True for h = 0



Just to be sure
,




when u =/


(att )
'
= att ,
LEO 1k ) atktk =
4) a
'

b-
°

+ 11 )a°t
'




=
att

i. True for n= I


Assume it is true for h=n


¥
k
1k ) and
"
i. lattt =

.
b-


sub n = h t I
n
""

(att ) = late ) ( att )
=
4th ) ¥411)a"ktk expand the bracket
get
¥4111 ⇐ 111 antebkti
"'
th
"
-




+

+In-n+IfI
= a



k
an "tk
k
>
LEO (1) 12,1 "zk
"
-
-
=
+
a
-
shift the variables

the same

€ 1L) and € 11,1 and"zk+
"" " k htt
↳ > =
a + b- + b-
,
2 ,
"'

EI,[ (1) II ) )
""
*
= a
"'
+ + ,
an thet

property ②
111=1111 -11nF )

) and"zk
'

£2
htt
= and +
,
I + b-


II 1h11 anti kzk
-


=

Gekoppeld boek

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