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Voorbeeld 4 van de 42 pagina's
Samenvatting

Summary - Genome Technology and Applications | 1 Ma Biomedical sciences | | Antwerp University

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Voorbeeld 4 van de 42 pagina's

Summary of the slides and explanation during the lectures of Genome Technology and Application. It covers every lecture given during the year, the self-study and the peer-presentations about sequencing technologies with additional research done by me. By studying this summary I got a 16/20 on this exam.

Voorbeeld van de inhoud

Genome technology and applications
Cell-based DNA cloning:
1. In vitro construction of a recombinant DNA molecule:
Requirements:
 Restriction endonucleases (“scissors”)
 DNA ligase (“glue”)
 Replicon: DNA that makes independent DNA replication possible
o Often vectors used (in this case plasmids)
o Replicons are specific per host



Restriction endonuclease:
Restriction endonucleases: bacteria’s defence mechanism against bacteriophages
 Contains a recognition sequence: this same sequence is methylated in the bacterium so
won’t be cut , viral DNA will be cleaved
o 4-8 bp palindrome

Bacteriophages: viruses infecting bacteria with a linear/circular genome

Recognition sequence: size of cleavage product increases with increased length of the recognition sequence
because it is more rare in the genome bv AluI has AGTC so expected size is 300bp (short)
 If sequence has GC also longer expected sequence due to CpG methylation sites

Cleavage: can cause blunt ends(cut on symmetry axis) or sticky ends that can form base pairs

MboI and BamHI: produce the same overhanging ends
= Isoschizomeres

 Compatible products so can be ligated



Nomenclature: 1 letter genus, 2 letter species, number bv HaeIII = 3rd restriction enzyme of Hemophilus aegypticus

Avoid recircularization:
2 restriction enzymes: cut both the vector and insertion with different 2 RE so it
cannot ligate with itself


Dephosphorylation: alkaine phosphatase removes the 5’ phosphate so the vector cannot
recircularize (DNA ligase needs 5’ phosphate group and 3’ OH-group)
 DNA insert still has phosphate group so can ligate with the vector

,DNA ligase:
DNA ligase: restores covalent bond in a DNA molecule
 Sticky ends: are unstable if only hybridized together so DNA ligase will stabilize these
 Hydrogen bonds in double helix facilitate DNA ligase

Ligation products: are either
 Intermolecular target-target concatemers
 Intramolecular vector cyclization
 Intermolecular vector-target recombinant DNA

Concatemer: several different fragments ligated together

Cyclisation: intramolecular ligation

Vectors:
Origin of replication: allows replication independent of the host chromosome
 needed for purification of the recombinant molecule

Plasmid: small circular bacterial DNA molecule
 Multiple copy number ORI’s
 Contains only a few genes
 Supercoiled: additional twists cause molecule to coil up
 Vertical transmission from parent to daughter cells / horizontal via conjugation to another bacterium

2. Transformation:
Transformation: uptake of DNA in the cell
 Inefficient process in bacteria

Increase uptake efficiency:
 Ca2+-buffer: makes competent cells that can take up DNA (better when combined with heat shock)
 Electric shock: brief high voltage pulse makes holes in bacterial cell-wall and membrane (electroporation)
 Circular DNA more easily transformed than linear

Host cell:
 Eukaryotic cell: used in expression studies
 Bacterium/ yeast: used for the preparation work for the expression study
o Easy to grow
o Fast reproduction




3. Selective propagation of clones:
1. Cells plated on agar
2. Cells grow and form colonies (all cells in 1 colony are identical (from same ancestor))
3. 1 colony isolated and grown in liquid medium (secondary amplification)




Recombinant screening:

,Recombinant screening: make sure bacteria contains the plasmid by only allowing it to grow if
plasmid is inserted

Antibiotic resistance: vector contains antibiotic resistance gene so when plating the bacteria on an
antibiotic coated agar plate only those containing vectors can grow

Vectors without inserts: differentiate between colonies with empty vectors and with inserts
 β -galactosidase gene complementation
 Supressor tRNA genes

β -galactosidase gene complementation:
β -galactosidase gene:
 Host cell: contains an incomplete β -galactosidase gene missing the amino-terminal part
 Vector: contains the amino-terminal part (LacZ gene)
 2 protein fragments will form a functional protein

X-gal: colorless product converted into blue dye by β -galactosidase
 Colonies containing the vector will turn blue

Insertional inactivation: in the LacZ gene there is a multiple cloning site that normally does not
disturb the gene (limited bases , multiple of 3)
 Large insert: will interrupt the MCS and interrupt the LacZ gene
 Colonies with an insertion are colorless

Supressor tRNA genes:
Supressor tRNA: tRNA with a mutation in the anticodon that causes it to recognise a stop-codon and
fill in an AA  protein doesn’t get truncated

Host cell: is mutant for a premature stopcodon Recognisable bv color due to accumulation of a product
Vector: contains supressor tRNA with the multiple cloning site in the middle
 No vector: coloured due to premature stopcodon mutation
 Empty vector: white because intact supressor tRNA will insert AA at premature stopcodon site
 Vector + insert: coloured due to supressor tRNA inactivation

4. Isolation of recombinant DNA clones:
DNA isolation: by cell lysis and purification to only isolate the plasmid containing the DNA sequence




Plasmid preparation in E. Coli:
E. Coli: has circular genome of 4,6Mb and plasmid of a few kb
1. Cell lysis: apply lysozyme to break cell wall
2. Chromosome gets broken in linear pieces during lysis , plasmid remains circular
3. Denature and renature DNA: increase pH to 12 and back to neutral
o Linear pieces: cannot renature quickly
o Circular pieces: renature perfectly because complementary strands remain close
together due to supercoil
4. Denatured DNA + proteins precipitate during the fast renaturation
5. Remaining solution is pure plasmid

, Cloning in bacteriophage lambda:
Bacteriophage lambda: linear dsDNA genome of 50kb packed in protein coat and tail

Cohesive sites: 5’ overhangs of 12bp that facilitate the transition of linear in the phage head to
circular in the cell (hybridises with itself to circularize)
 Critical sequence for DNA packaging in phage heads



Lytic cycle: formation of virus particles
1. DNA replication
2. Synthesis of coat proteins
3. Packaging of phage DNA in coat proteins
4. Host cell lysis

Lysogenic cycle: viral DNA integrates in bacterial genome = provirus
by recombination at the att sequence

 After a few generations of bacteria virus particles will be made
from the provirus




Lambda genome:
 Integration and recombination genes: non-essential because lysogenic pathway not used in cloning
= stuffer fragment

In vitro lambda packaging:
Protein mix: packages lambda DNA in phage particles and consists of bacterial strains containing
lysogenic phages that are blocked in different steps of the packaging process
o 1 strain doesn’t have E protein (major capsid protein for preheads)
o 1 has protein E but misses protein D (for assembly)
1. Lyse both bacteria and mixing the lysates
2. Add DNA with cohesive sites
3. DNA will be packaged in the phages (if cos sites are 50kb apart)

Lambda cloning vectors:
Replacement vectors: stuffer fragment replaced by insert (max 20kb)
 will only be long enough to package in phage heads with insert present (total DNA 37-50kb)
 Used for genomic DNA

Insertion vectors: short vector with DNA of max 10kb
 Used for cDNA

Cosmid vectors: hybrid between plasmid and phages by cloning a cos sequence in a plasmid
1. MboI cuts plasmid , BamHI cuts insert to create the same overhanging ends
2. Insert (max 30-45kb) ligated in the plasmid (use in vitro packaging mix)
3. Vector put in phase head using the cos sites
 Combines plasmid convenience with phage efficiency

Fosmid: cosmid based on the F plasmid of E. Coli (lower copy number ORI – less DNA but more stable)

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