BUS-S 305 MIDTERM QUESTIONS WITH VERIFIED
ANSWERS
application layer - Answers - the software you use - HTTP/HTTPS
Transport Layer - Answers - 1.)linking to app
2.) segmenting
3.) session management
TCP segment
Network Layer - Answers - 1.) addressing
2.) routing
IP
Data-Link layer - Answers - 1.) error control
2.) decides when to send media
3.) message formatting
ethernet frame
Physical Layer - Answers - hardware
Analog transmission of Digital Data - Answers - FM
AM
PM
symbol set 0 and 1 and modem reads the sound wave
64-QAM - Answers - 6 mbps
256-QAM - Answers - 8 mbps
Digital transmission of analog data - Answers - codec will sample the sound waves and
break it into bits
these bits are made as binary numbers
second codec will transmit the binary numbers as voice
unipolar - Answers - digital transmission digital data
a 1 would be 5 volt current
0 would be 0 volts
, Bipolar NRZ - Answers - digital transmission digital data
1 = 5 volts sent through
0 = -5 volts sent
Bipolar RZ - Answers - digital transmission digital data
1 = 5 volts
0 = -5 volts
between each impulse there will be a very short moment where it return to zero.
used with higher symbol rates
Media access control (MAC) - Answers - decides when to transmit
Data-link layer
control access - Answers - one device decides
contention - Answers - one device talks while the other waits
sources of network errors - Answers - design problems
impulse noise on wires (ie. thunderstorms, too close to other wires
CRC-32 - Answers - error detection
treats message as long binary number and divides by a set amount
remainder is used as check code
ARQ (Stop-And-Wait) (error correction) - Answers - sender will send message and wait
for an ACK for receiver to indicate successful reception
cannot send another message until ACK is sent back from receiver
ARQ Continuous (error correction) - Answers - window size indicates the amount of
messages that can be sent without receiving an ACK
once window size is filled, messages stop being sent until ACK is sent from receiver
then it can continue
efficiency formula - Answers - efficiency = user data/ user data + overhead
ASYNC transmission - Answers - Data-link protocol
ANSWERS
application layer - Answers - the software you use - HTTP/HTTPS
Transport Layer - Answers - 1.)linking to app
2.) segmenting
3.) session management
TCP segment
Network Layer - Answers - 1.) addressing
2.) routing
IP
Data-Link layer - Answers - 1.) error control
2.) decides when to send media
3.) message formatting
ethernet frame
Physical Layer - Answers - hardware
Analog transmission of Digital Data - Answers - FM
AM
PM
symbol set 0 and 1 and modem reads the sound wave
64-QAM - Answers - 6 mbps
256-QAM - Answers - 8 mbps
Digital transmission of analog data - Answers - codec will sample the sound waves and
break it into bits
these bits are made as binary numbers
second codec will transmit the binary numbers as voice
unipolar - Answers - digital transmission digital data
a 1 would be 5 volt current
0 would be 0 volts
, Bipolar NRZ - Answers - digital transmission digital data
1 = 5 volts sent through
0 = -5 volts sent
Bipolar RZ - Answers - digital transmission digital data
1 = 5 volts
0 = -5 volts
between each impulse there will be a very short moment where it return to zero.
used with higher symbol rates
Media access control (MAC) - Answers - decides when to transmit
Data-link layer
control access - Answers - one device decides
contention - Answers - one device talks while the other waits
sources of network errors - Answers - design problems
impulse noise on wires (ie. thunderstorms, too close to other wires
CRC-32 - Answers - error detection
treats message as long binary number and divides by a set amount
remainder is used as check code
ARQ (Stop-And-Wait) (error correction) - Answers - sender will send message and wait
for an ACK for receiver to indicate successful reception
cannot send another message until ACK is sent back from receiver
ARQ Continuous (error correction) - Answers - window size indicates the amount of
messages that can be sent without receiving an ACK
once window size is filled, messages stop being sent until ACK is sent from receiver
then it can continue
efficiency formula - Answers - efficiency = user data/ user data + overhead
ASYNC transmission - Answers - Data-link protocol
