Solutions Manual Precalculus 11th Edition By Ron Larson

Solutions Manual for
Precalculus 11th Edition By Ron
Larson
(All Chapters 1-10, 100%
Original Verified, A+ Grade)
This is The Only Original and
Complete Solutions Manual for
11th Edition, All Other Files in
The Market are Fake/Old/Wrong
Edition.
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Link is Added at The End of PDF.

,The Textbook This Document Fully Covers
(Chapters 1-10)



Precalculus 11th Edition By Ron Larson


ISBN-13: 9780357457207
ISBN-13: 9780357750865
ISBN-13: 9798214413563
ISBN-13: 9780357711576
ISBN-13: 9780357456996

, Table Of Contents
• 1. Functions and Their Graphs
• 2. Polynomial and Rational Functions
• 3. Exponential and Logarithmic
Functions
• 4. Trigonometry
• 5. Analytic Trigonometry
• 6. Additional Topics in Trigonometry
• 7. Systems of Equations and
Inequalities
• 8. Matrices and Determinants
• 9. Sequences, Series, and Probability
• 10. Topics in Analytic Geometry

,C H A P T E R 1
Functions and Their Graphs
Section 1.1 Rectangular Coordinates
1. Cartesian 16. x < 0 and y < 0 in Quadrant III.

2. Midpoint Formula 17. x = − 4 and y > 0 in Quadrant II.

3. The x-axis is the horizontal real number line. 18. x < 0 and y = 7 in Quadrant II.
Matches (c).
19. x + y = 0, x ≠ 0, y ≠ 0 means
4. The y-axis is the vertical real number line. x = − y or y = − x. This occurs in Quadrant II or IV.
Matches (f).

5. The origin is the point of intersection of the vertical
20. ( x, y ), xy > 0 means x and y have the same signs.
and horizontal axes. This occurs in Quadrant I or III.
Matches (a).
21.
6. The quadrants are four regions of the coordinate plane.
Matches (d).

7. An x-coordinate is the directed distance from the
y-axis. Matches (e).

8. A y-coordinate is the directed distance from the x-axis.
Matches (b).

9. A: ( 2, 6), B: ( −6, − 2), C: ( 4, − 4), D: ( −3, 2)
22.

10. A: ( 32 , − 4); B: (0, − 2); C: (−3, 52 ); D: (−6, 0)
11.




( x2 − x1 ) + ( y2 − y1 )
2 2
23. d =

(3 − (−2))
2
+ ( −6 − 6)
2
=

12. = (5)
2
+ ( −12)
2


= 25 + 144
= 13 units


( x2 − x1 ) + ( y2 − y1 )
2 2
24. d =

= (0 − 8)2 + ( 20 − 5)
2



(−8) + (15)
2 2
=
13. ( − 3, 4)
= 64 + 225
14. ( −12, 0) = 289

15. x > 0 and y < 0 in Quadrant IV. = 17 units



2

, Section 1.1 Rectangular Coordinates 3


30. (a) The distance between ( −1, 1) and (9, 1) is 10.
25. d = ( x2 − x1 ) + ( y2 − y1 )
2 2


The distance between (9, 1) and (9, 4) is 3.
(−5 − 1) + ( −1 − 4)
2 2
=
The distance between ( −1, 1) and (9, 4) is
(−6) + ( −5)
2 2
=
(9 − (−1))
2
+ ( 4 − 1)
2
= 36 + 25 = 100 + 9 = 109.

=
( )
2
61 units (b) 10 2 + 32 = 109 = 109

26. d = ( x2 − x1 ) + ( y2 − y1 )
2 2

(4 − 2) + (0 − 1)
2 2
31. d1 = = 4+1 = 5
(3 − 1) + ( −2 − 3)
2 2
=
( ) ( )
2 2
d2 25 + 25
(2) + ( −5)
2 2
=
(2 + 1) + (1 + 5)
2 2
d3 = = 9 + 36 = 45
= 4 + 25
( 5) ( ) ( )
2 2 2
+ 45 = 50
= 29 units


(3 − (−1))
2
+ (5 − 3) =
2
27. d = ( x2 − x1 ) + ( y2 − y1 )
2 2
32. d1 = 16 + 4 = 20

(5 − 3) + (1 − 5) =
2 2 2 2
 1  4 d2 = 4 + 16 = 20
=  2 −  +  −1 − 
 2  3
(5 − (−1))
2
+ (1 − 3)
2
d3 36 + 4 40
2 2
3  7
=   + − 
( ) ( ) ( )
2 2 2
 
2  3 20 + 20 = 40
9 49
= +
(1 3) ( 2)
2 2
4 9 33. d1 3 4 + 25 29
277
(3 + 2) + ( 2 − 4)
2 2
= d2 = = 25 + 4 = 29
36
(1 + 2) + ( −3 − 4)
2 2
277 d3 = = 9 + 49 = 58
= units
6 d1 = d 2

28. d = ( x2 − x1 ) + ( y2 − y1 )
2 2
34. d1 = ( 4 − 2)
2
+ (9 − 3) =
2
4 + 36 = 40
− 9.5) + (8.2 − ( −2.6))
2
(−3.9
2
= d2 = ( −2 − 4 )
2
+ ( 7 − 9) =
2
36 + 4 = 40

(−13.4) + (10.8)
2 2
= d3 = ( 2 − ( −2 ) )
2
+ (3 − 7 ) =
2
16 + 16 = 32
= 179.56 + 116.64 d1 = d 2
= 296.2
35. (a)
29. (a) (1, 0), (13, 5)

Distance = (13 − 1)2 + (5 − 0)
2


2 2
= + = 169 =
(13, 5), (13, 0)
Distance = 5 − 0 = 5 = 5

(1, 0), (13, 0) (b) d = (5 − (−3)) 2 + (6 − 6)2 = 64 = 8
Distance = 1 − 13 = −12 = 12  6 + 6 5 + (−3) 
(c)  ,  = (6, 1)
 2 2 
(b) 52 + 122 = 25 + 144 = 169 = 132

,4 Chapter 1 Functions and Their Graphs


36. (a) 40. (a)




(b) d = (4 − 4) 2 + (8 − 1)2 = 49 = 7
(2 − 10) + (10 − 2)
2 2
(b) d =
1 + 8 4 + 4  9 
(c)  ,  =  , 4 = 64 + 64 = 8 2
 2 2  2 
 2 + 10 10 + 2 
37. (a)
(c)  ,  = (6, 6)
 2 2 

41. (a)




(9 − 1) + (7 − 1)
2 2
(b) d = = 64 + 36 = 10

 9 + 1 7 + 1 (b) d = (−16.8 − 5.6)
2
+ (12.3 − 4.9)
2
(c)  ,  = (5, 4)
 2 2 
= 501.76 + 54.76 = 556.52
38. (a)  −16.8 + 5.6 12.3 + 4.9 
(c)  ,  = ( −5.6, 8.6)
 2 2 

42. (a)




(1 − 6) + (12 − 0) =
2 2
(b) d = 25 + 144 = 13

 1 + 6 12 + 0  7 
(c)  ,  =  , 6 2 2
 2 2  2  1 5  4
(b) d =  +  + 1 − 
2 2  3
39. (a)
1 82
= 9+ =
9 3
 −(5 2) + (1 2) ( 4 3) + 1   7
(c)  ,  =  −1, 
 2 2   6




(5 + 1) + ( 4 − 2) + =
2 2
(b) d = 36 + 4 = 2 10

 −1 + 5 2 + 4 
(c)  ,  = ( 2, 3)
 2 2 