Radiographic Imaging Midterm Exam
with Complete Solutions
Incident electrons - ANSWER-Electrons traveling from the cathode filament to the
anode are called:
Added - ANSWER-The collimator device is considered part of the ____ filtration.
Focal spot - ANSWER-The exact point on the anode where the x-ray beam emanates is
the:
2 - ANSWER-The K shell can hold a maximum of ____ electrons.
Direct square law - ANSWER-The exposure maintenance formula is a:
Increases - ANSWER-As the angle of the anode increases and the incident electron
beam size remains the same, the effective focal spot size:
C.) Beam quality - ANSWER-Milliamperage-second (mAs) directly affects all of the
following EXCEPT
A.) Beam quantity.
B.) Beam intensity.
C.) Beam quality.
D.) X-ray output.
Compensation filter - ANSWER-The problem of unequal subject radiographic exposure
is solved by a:
Motion - ANSWER-The length of the exposure time (S) for a radiograph, is used to
primarily control:
Inherent; added - ANSWER-Total beam filtration is equal to the sum of ____ and ____
filtration.
The force field around the nucleus - ANSWER-Bremsstrahlung interactions may occur
only when the incident electron interacts with:
s= 0.025 - ANSWER-Given 5 mAs and a milliamperage of 200, calculate the exposure
time.
200 x s = 5 mAs
, mAs= 25 - ANSWER-Given 50 mA and an exposure time of 0.50 second, calculate the
mAs.
50 x 0.50 = ?
2n2 - ANSWER-The maximum number of electrons found in any energy level (shell) at
any point in time is calculated by the formula:
Half value layer - ANSWER-The amount of material that will reduce the intensity of the
primary beam to one-half its original value is the:
Doubling - ANSWER-An increase in kVp by 15 percent will cause an approximate ____
in the exposure.
Cause the electrons to travel faster from cathode to anode. - ANSWER-Increasing the
kVp for an exposure will
Outermost - ANSWER-At the end of the characteristic cascade, the ____ shell is
missing an electron.
Inverse square law - ANSWER-The relationship between the intensity of radiation and
distance is the:
High atomic number - ANSWER-Tungsten is the metal of choice for the source of x-ray
photons because of its:
Aluminum - ANSWER-The most common diagnostic x-ray beam filter material is:
D.) All of the above - ANSWER-The emission spectrum of an x-ray beam from a
tungsten anode consists of:
A.) A characteristic spike at 69 keV.
B.) A significant portion due to bremsstrahlung interactions.
C.) A mixture of brems and characteristic interactions.
D.) All of the above
Heat - ANSWER-Almost all of the kinetic energy of the incident electrons is converted
to:
Increases - ANSWER-As the actual focal spot size increases, the effective focal spot
size:
Decreased radiographic contrast - ANSWER-If the mAs of a radiograph is increased
from 10 to 20, the resulting radiograph will exhibit:
Ion - ANSWER-If an electron is gained or lost from an atom, that atom becomes an:
Anode - ANSWER-X-ray photon production occurs at the:
with Complete Solutions
Incident electrons - ANSWER-Electrons traveling from the cathode filament to the
anode are called:
Added - ANSWER-The collimator device is considered part of the ____ filtration.
Focal spot - ANSWER-The exact point on the anode where the x-ray beam emanates is
the:
2 - ANSWER-The K shell can hold a maximum of ____ electrons.
Direct square law - ANSWER-The exposure maintenance formula is a:
Increases - ANSWER-As the angle of the anode increases and the incident electron
beam size remains the same, the effective focal spot size:
C.) Beam quality - ANSWER-Milliamperage-second (mAs) directly affects all of the
following EXCEPT
A.) Beam quantity.
B.) Beam intensity.
C.) Beam quality.
D.) X-ray output.
Compensation filter - ANSWER-The problem of unequal subject radiographic exposure
is solved by a:
Motion - ANSWER-The length of the exposure time (S) for a radiograph, is used to
primarily control:
Inherent; added - ANSWER-Total beam filtration is equal to the sum of ____ and ____
filtration.
The force field around the nucleus - ANSWER-Bremsstrahlung interactions may occur
only when the incident electron interacts with:
s= 0.025 - ANSWER-Given 5 mAs and a milliamperage of 200, calculate the exposure
time.
200 x s = 5 mAs
, mAs= 25 - ANSWER-Given 50 mA and an exposure time of 0.50 second, calculate the
mAs.
50 x 0.50 = ?
2n2 - ANSWER-The maximum number of electrons found in any energy level (shell) at
any point in time is calculated by the formula:
Half value layer - ANSWER-The amount of material that will reduce the intensity of the
primary beam to one-half its original value is the:
Doubling - ANSWER-An increase in kVp by 15 percent will cause an approximate ____
in the exposure.
Cause the electrons to travel faster from cathode to anode. - ANSWER-Increasing the
kVp for an exposure will
Outermost - ANSWER-At the end of the characteristic cascade, the ____ shell is
missing an electron.
Inverse square law - ANSWER-The relationship between the intensity of radiation and
distance is the:
High atomic number - ANSWER-Tungsten is the metal of choice for the source of x-ray
photons because of its:
Aluminum - ANSWER-The most common diagnostic x-ray beam filter material is:
D.) All of the above - ANSWER-The emission spectrum of an x-ray beam from a
tungsten anode consists of:
A.) A characteristic spike at 69 keV.
B.) A significant portion due to bremsstrahlung interactions.
C.) A mixture of brems and characteristic interactions.
D.) All of the above
Heat - ANSWER-Almost all of the kinetic energy of the incident electrons is converted
to:
Increases - ANSWER-As the actual focal spot size increases, the effective focal spot
size:
Decreased radiographic contrast - ANSWER-If the mAs of a radiograph is increased
from 10 to 20, the resulting radiograph will exhibit:
Ion - ANSWER-If an electron is gained or lost from an atom, that atom becomes an:
Anode - ANSWER-X-ray photon production occurs at the:
