, MAT1581 Assignment 3
Semester 2 2025
DUE 5 August 2025
Use this document as a guide and for references to answer your assignment
Question 1
Determine the following limits: (1.1) lim (3) x→−1 x3 − 2 x4 + 4x − 3 (1.2) lim (3)
x→3 x3 − 8 x2 − 4
Step 1: Plug in x=−1x = -1x=−1
Check if the limit can be evaluated directly:
Numerator:
(−1)3−2=−1−2=−3(-1)^3 - 2 = -1 - 2 = -3(−1)3−2=−1−2=−3
Denominator:
(−1)^4+4(−1)−3=1−4−3=−6
= =1/2
✅Final Answer (1.1):
Semester 2 2025
DUE 5 August 2025
Use this document as a guide and for references to answer your assignment
Question 1
Determine the following limits: (1.1) lim (3) x→−1 x3 − 2 x4 + 4x − 3 (1.2) lim (3)
x→3 x3 − 8 x2 − 4
Step 1: Plug in x=−1x = -1x=−1
Check if the limit can be evaluated directly:
Numerator:
(−1)3−2=−1−2=−3(-1)^3 - 2 = -1 - 2 = -3(−1)3−2=−1−2=−3
Denominator:
(−1)^4+4(−1)−3=1−4−3=−6
= =1/2
✅Final Answer (1.1):
