MIP1501
ASSIGNMENT 3
DUE DATE: 30 JULY 2025
,MIP1501 Assignment 3 2025
Due 30 July 2025
Question 1 (31)
1.1. A tractor travels 90 kilometers on 18 liters of fuel. How much fuel will it need
to travel 130 kilometers?
Round off your answer to 2 decimal places.
Fuel consumption rate
90 km18 L= 0.2 L/km
For 130 km:
130×0.2= 26.0 L
26.00 L
1.2. 7 kg of tomatoes cost R 56,63. How much are you going to pay for 10 kg of
tomatoes?
Unit price
7 kg R56.63≈R8.09 /kg
For 10 10×8.09
= R80.90kg
, 1.3. If 30 men can build a wall of a shopping centre in 20 days, how long will it
take 25 men to build the exact same wall?
Total work = 30 men × 20 days = 600 man-days
At 25 men:
25 men600 man-days
= 24 days
1.4. John is the catering manager at a lodge. He usually uses the following meat
ration in a week when he has 6 guests staying at the lodge:
Meat Base Scale factor Weekly Over 3 weeks (kg)
type weekly to 18 guests amount
amount (÷6×18=×3) for 18
for 6 guests
guests (kg)
Rump 1 kg ×3 3 kg 3 kg × 3 weeks = 9 kg
steak
ASSIGNMENT 3
DUE DATE: 30 JULY 2025
,MIP1501 Assignment 3 2025
Due 30 July 2025
Question 1 (31)
1.1. A tractor travels 90 kilometers on 18 liters of fuel. How much fuel will it need
to travel 130 kilometers?
Round off your answer to 2 decimal places.
Fuel consumption rate
90 km18 L= 0.2 L/km
For 130 km:
130×0.2= 26.0 L
26.00 L
1.2. 7 kg of tomatoes cost R 56,63. How much are you going to pay for 10 kg of
tomatoes?
Unit price
7 kg R56.63≈R8.09 /kg
For 10 10×8.09
= R80.90kg
, 1.3. If 30 men can build a wall of a shopping centre in 20 days, how long will it
take 25 men to build the exact same wall?
Total work = 30 men × 20 days = 600 man-days
At 25 men:
25 men600 man-days
= 24 days
1.4. John is the catering manager at a lodge. He usually uses the following meat
ration in a week when he has 6 guests staying at the lodge:
Meat Base Scale factor Weekly Over 3 weeks (kg)
type weekly to 18 guests amount
amount (÷6×18=×3) for 18
for 6 guests
guests (kg)
Rump 1 kg ×3 3 kg 3 kg × 3 weeks = 9 kg
steak
