TEST BANK For Fundamentals of Physics 10th Edition By Resnick, Walker and Halliday Chapters 1 - 44 

TEST BANK For Fundamentals of Physics
10th Edition By Resnick, Walker and Halliday
Chapters 1 - 44

,Chapter 1 cv




1. VariouscvgeometriccvformulascvarecvgivencvincvAppendixcvE.

(a) ExpressingcvthecvradiuscvofcvthecvEarthcvas

Rc v c v 6.37c v cv106c v m103c v kmc v mcv c v 6.37c v cv103c v km,

itscvcircumferencecvisc v scvcv2cvRc v cv2cv(6.37cvcv103c v km)cvcv4.00cv104c v km.

(b) ThecvsurfacecvareacvofcvEarthcviscvAcvcv4 c v 4cv 6.37cvcv103cvcvk c v 5.10cv cv1 km2.
cvR2 08
m
2




4cvcv 3 4c v
 6.37cvcv103cvcvkm  cv1.08cvcv1012cvcvkm3.
3cvcvcv
(c)cvThecvvolumecvofcvEarthcviscv Vc v c v R cvcvcvcv
3 3

2. Thec v conversionc v factorsc v are:cv1cvgrycvcv1/10 c v line cv,cv 1cvline cvcv1/12 c v inch cvandc v 1c v po
intc v =c v 1/72civnch.cvThecvfactorscvimplycvthat

1cvgrycv=cv(1/10)(1/12)(72cvpoints)cv=cv0.60cvpoint.

Thus,c v 1c v gry2c v =c v (0.60c v point)2c v =c v 0.36c v point2,c v whichc v meansc v thatcv0.50 c v gry 2 cv=c v 0.18 c v point 2 cv.

3. Thecvmetriccvprefixescv (micro,cvpico,cv nano,cv …)cv arecv givencv forcv readycv referencecvoncv t
hecvinsidecvfrontcvcovercvofcvthecvtextbookcv(seecvalsocvTablecv1–2).

(a)cvSincecv1cvkmcv=cv1cvcv103cvmcvandcv1cvmcv=cv1cvcv106cvm,

1kmc v cv 103c v mc v c v 103cv m cvmc v mcvcv1 m.

106 09


Thec v givenc v measurementc v isc v 1.0c v kmc v (twoc v significantc v figures),c v whichc v implies
v houldcvbecvwrittencvascv1.0cvcv10 cvm.
9
c v ourc v resultcs



(b)cvWecvcalculatecvthecvnumbercvofcvmicronscvincv1cvcentimeter.cvSincecv1cvcmcv=cv102cvm,

1cmc v =c v 102c v m c v =c v 102m106c v cvmc v m m.

 cv c v 104

Wecvconcludecvthatcvthecvfractioncvofcvonecvcentimetercvequalcvtocv1.0cvmcviscv1.0cv

,cv104.cv(c)cvSincecv1cvydcv=cv(3cvft)(0.3048cvm/ft)cv=cv0.9144cvm,


1

, 2 CHAPTERcv
1


1.0cvydc v =c v 0.91m106cv cvmc v mcvc v 9.1c m.
vcv10
5



4. (a)c v Usingc v thec v conversionc v factorsc v 1c v inchc v =c v 2.54c v cmc v exactlyc v andc v 6c v picasc v =c v
1c v inch,c v wecvobtain cv6c v picascvc v
0.80c v cmcv =c v 0.80c v c 1cvinc cv1.9c v picas.
mcv  cv h  c v
2.54c v cmcv 1cvinchc v 

   
(b)cvWithcv12cvpointscv=cv1cvpica,cvwecv
have


 cvcmcv=c v 0.80cvcm 1cvinc  cv6c v picascv cv12c v pointscvc v c v 23c v points.
0.80
cv  cv  c v
2.54cvhcmcv 1cvinchc v
 cvc v
1cvpica


   


5. Givencvthatcv1cvfurlo c v 201.168cvmcv,cv 1cvrodcvcv5.029 andcv1cvchaincvcv20.117cv mcv,cvwecvfind
ng 2cvm
thecvrelevantcvconversioncvfactorscvtocvbe
1cvrod
1.0cv furlongc v cv201.168cvmcvcv(201.168c c v 40c v rods,
vmcv)
5.0292 m

and
1cvchain
1.0c v furlongc v cv201.168c v mc v cv (201.16 10c v chainscv.
8c v mcv) 20.117cv
m
Notec v thec v cancellationc v ofc v mc v (meters),c v thec v unwantedc v unit.c v Usingc v thec v given
c v conversioncfv actors,cvwecvfind



(a) thecvdistancecvdcvincvrodscvtocvbe
40cv
dc v c v 4.0cvfurlongsc v 4.0cvfurlongsc v cv160c v rods,
rods
1cvfurlong

(b) andcvthatcvdistancecvincvchainscvtocvbe

10cvchainsc v
dc v c v 4.0cv furlongsc v 4.0cvfurlongs c v 40cvchains.
1cvfurlong

6. WecvmakecvusecvofcvTablecv1-6.

(a) Wecvlookcvatcvthecvfirstcv(“cahiz”)cvcolumn:cv1cvfanegacviscvequivalentcvtocvwhatcvamountcvo
fcvcahiz?W
cv ecvnotecvfromcvthecvalreadycvcompletedcvpartcvofcvthecvtablecvthatcv1cvcahizcvequalscv

Thus,cv1cvfanegacv=c v 1c v cahiz,cvorcv8.33cvcv102cvcahiz.c v Similarly,cv“1cv
acvdozencvfanega.cv12
cahizcv=cv48cvcuartilla”cv(incvthe
cvorcv2.08cvc v 10 c v cahiz.cv
alreadycvcompletedcvpart)cvimpliescvthatcv1cvcuartillacv= 1
cv
cvcahiz, 2
48
Continuingc v inc v thisc v way,c v thec v remainingc v entriesc v inc v thec v firstc v columnc v arec v 6.94