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Uday 2025
Physics
DPP: 3
Gravitation
Q1 The ratio of radii of two satellites is p and the Four particles each of mass M , are located at
ratio of their acceleration due to gravity is q . The the vertices of a square with side L. The
ratio of their escape velocities will be gravitational potential due to this at the centre of
1/2
(A) the square is
( p)
q
−−
(A) −√32 GM
1/2 L
(B)
(q)
p −−
(B) −√64 GM
2
L
(C) pq (C) Zero
(D) √−−
pq −−
(D) √32 GM
L
Q2 Escape velocity of a body from earth is 11.2 Q6 An artificial satellite moving in a circular orbit
km/s. Escape velocity, when thrown at an angle around the earth has a total (kinetic + potential)
of 45∘ from horizontal will be:- energy E0 . Its potential energy is
(A) 11.2 km/s (A) −E0 (B) E0
(B) 22.4 km/s (C) −2E0 (D) 2E0
–
(C) 11.2/√2 km/s
– Q7 The orbital velocity of an artificial satellite in a
(D) 11.2√2 km/s
circular orbit just above the earth's surface is v.
Q3 The escape velocity from the earth is 11.2 km/s. For a satellite orbiting at an altitude of half of the
The mass of another planet is 100 times of mass earth's radius, the orbital velocity is
of earth and its radius is 4 times the radius of (A) 32 v
−
−
earth. The escape velocity for the planet is (B) √ 3 v
2
(A) 56.0 km/s −−
(C) √ 2 v
(B) 280 km/s 3
(C) 112 km/s (D) 23 v
(D) 11.2 km/s
Q8 The time period of a satellite of earth is 5 hours.
Q4 Binding energy of moon and earth is: If the separation between the earth and the.
(A) GMe Mm
rem satellite is increased to four times the previous
(B) GMe Mm value, the new time period will become
2rem
(C) − GMe Mm (A) 20 hours (B) 10 hours
rem
(D) − GMe Mm (C) 80 hours (D) 40 hours
2rem
Q9 The period of a satellite in a circular orbit of
Q5
radius R is T , the period of another satellite in a
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circular orbit of radius 4R is
(A) 4T (B) T /4
(C) 8T (D) T /8
Q10 The earth E moves in an elliptical orbit with the
sun S at one of the foci as shown in figure. Its
speed of motion will be maximum at the point
(A) C
(B) A
(C) B
(D) D
Q11 If orbital velocity of planet is given by v =
GaMbRc, then
(A) a = 1/3, b = 1/3, c = −1/3
(B) a = 1/2, b = 1/2, c = −1/2
(C) a = 1/2, b = −1/2, c = 1/2
(D) a = 1/2, b = −1/2, c = −1/2
Q12 Kepler’s second law is a consequence of:-
(A) conservation of kinetic energy
(B) conservation of linear momentum
(C) conservation of angular momentum
(D) conservation of speed
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Uday 2025
Physics
DPP: 3
Gravitation
Q1 The ratio of radii of two satellites is p and the Four particles each of mass M , are located at
ratio of their acceleration due to gravity is q . The the vertices of a square with side L. The
ratio of their escape velocities will be gravitational potential due to this at the centre of
1/2
(A) the square is
( p)
q
−−
(A) −√32 GM
1/2 L
(B)
(q)
p −−
(B) −√64 GM
2
L
(C) pq (C) Zero
(D) √−−
pq −−
(D) √32 GM
L
Q2 Escape velocity of a body from earth is 11.2 Q6 An artificial satellite moving in a circular orbit
km/s. Escape velocity, when thrown at an angle around the earth has a total (kinetic + potential)
of 45∘ from horizontal will be:- energy E0 . Its potential energy is
(A) 11.2 km/s (A) −E0 (B) E0
(B) 22.4 km/s (C) −2E0 (D) 2E0
–
(C) 11.2/√2 km/s
– Q7 The orbital velocity of an artificial satellite in a
(D) 11.2√2 km/s
circular orbit just above the earth's surface is v.
Q3 The escape velocity from the earth is 11.2 km/s. For a satellite orbiting at an altitude of half of the
The mass of another planet is 100 times of mass earth's radius, the orbital velocity is
of earth and its radius is 4 times the radius of (A) 32 v
−
−
earth. The escape velocity for the planet is (B) √ 3 v
2
(A) 56.0 km/s −−
(C) √ 2 v
(B) 280 km/s 3
(C) 112 km/s (D) 23 v
(D) 11.2 km/s
Q8 The time period of a satellite of earth is 5 hours.
Q4 Binding energy of moon and earth is: If the separation between the earth and the.
(A) GMe Mm
rem satellite is increased to four times the previous
(B) GMe Mm value, the new time period will become
2rem
(C) − GMe Mm (A) 20 hours (B) 10 hours
rem
(D) − GMe Mm (C) 80 hours (D) 40 hours
2rem
Q9 The period of a satellite in a circular orbit of
Q5
radius R is T , the period of another satellite in a
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circular orbit of radius 4R is
(A) 4T (B) T /4
(C) 8T (D) T /8
Q10 The earth E moves in an elliptical orbit with the
sun S at one of the foci as shown in figure. Its
speed of motion will be maximum at the point
(A) C
(B) A
(C) B
(D) D
Q11 If orbital velocity of planet is given by v =
GaMbRc, then
(A) a = 1/3, b = 1/3, c = −1/3
(B) a = 1/2, b = 1/2, c = −1/2
(C) a = 1/2, b = −1/2, c = 1/2
(D) a = 1/2, b = −1/2, c = −1/2
Q12 Kepler’s second law is a consequence of:-
(A) conservation of kinetic energy
(B) conservation of linear momentum
(C) conservation of angular momentum
(D) conservation of speed
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