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Uday 2025
Physics
DPP: 1
Gravitation
Q1 Gravitational force between two masses at a (D) 6.675 × 10 −8 newton
distance d apart is 6 N . If these masses are taken
Q6 Two sphere of mass m and M are situated in air
to moon and kept at same separation, then the
and the gravitational force between them is F .
force between them will become:
The space around the masses is now filled with a
(A) 1N
liquid of specific gravity 3 . The gravitational
(B) 16 N
force will now be
(C) 36N
(A) F
(D) 6N
(B) F3
Q2 The value of universal gravitational constant G (C) F9
depends upon: (D) 3F
(A) Nature of material of two bodies
Q7 Three equal masses of 1 kg each are placed at
(B) Heat constant of two bodies
the vertices of an equilateral triangle PQR and
(C) Acceleration of two bodies
a mass of 2 kg is placed at the centroid O of the
(D) None of these –
triangle which is at a distance of √2 m from
Q3 If the distance between the centres of earth and each of the vertices of the triangle. The
moon is D and mass of earth is 81 times that of gravitational force, in newton, acting on the mass
moon. At what distance from the centre of earth of 2 kg is:-
–
gravitational field will be zero (A) 2 (B) √2
(A) D
2 (C) 1 (D) Zero
2D
(B) 3
4D Q8 The value of g reduces to half of its value at
(C) 5
9D surface of earth at a height h , then -
(D) 10 (A) h = R
Q4 Gravitation is the phenomenon of interaction (B) h = 2R
–
between (C) h = (√2 + 1)R
–
(A) Point masses only (D) h = (√2 − 1)R
(B) Any arbitrary shaped masses
Q9 Two planets have the same average density but
(C) Planets only
their radii are R1 and R2 . If acceleration due to
(D) None of these
gravity on these planets be g1 and g2
Q5 The gravitational force between two stones of respectively, then
g R
mass 1 kg each separated by a distance of 1 (A) g1 = 1
2 R2
g1
metre in vacuum is (B) g = R2
2 R1
(A) Zero 2
(C) g1 = R1
(B) 6.675 × 10 −5 newton g 2 2
R2
−11 (D) g1 R31
(C) 6.675 × 10 newton g2
=
R32
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Uday 2025
Physics
DPP: 1
Gravitation
Q1 Gravitational force between two masses at a (D) 6.675 × 10 −8 newton
distance d apart is 6 N . If these masses are taken
Q6 Two sphere of mass m and M are situated in air
to moon and kept at same separation, then the
and the gravitational force between them is F .
force between them will become:
The space around the masses is now filled with a
(A) 1N
liquid of specific gravity 3 . The gravitational
(B) 16 N
force will now be
(C) 36N
(A) F
(D) 6N
(B) F3
Q2 The value of universal gravitational constant G (C) F9
depends upon: (D) 3F
(A) Nature of material of two bodies
Q7 Three equal masses of 1 kg each are placed at
(B) Heat constant of two bodies
the vertices of an equilateral triangle PQR and
(C) Acceleration of two bodies
a mass of 2 kg is placed at the centroid O of the
(D) None of these –
triangle which is at a distance of √2 m from
Q3 If the distance between the centres of earth and each of the vertices of the triangle. The
moon is D and mass of earth is 81 times that of gravitational force, in newton, acting on the mass
moon. At what distance from the centre of earth of 2 kg is:-
–
gravitational field will be zero (A) 2 (B) √2
(A) D
2 (C) 1 (D) Zero
2D
(B) 3
4D Q8 The value of g reduces to half of its value at
(C) 5
9D surface of earth at a height h , then -
(D) 10 (A) h = R
Q4 Gravitation is the phenomenon of interaction (B) h = 2R
–
between (C) h = (√2 + 1)R
–
(A) Point masses only (D) h = (√2 − 1)R
(B) Any arbitrary shaped masses
Q9 Two planets have the same average density but
(C) Planets only
their radii are R1 and R2 . If acceleration due to
(D) None of these
gravity on these planets be g1 and g2
Q5 The gravitational force between two stones of respectively, then
g R
mass 1 kg each separated by a distance of 1 (A) g1 = 1
2 R2
g1
metre in vacuum is (B) g = R2
2 R1
(A) Zero 2
(C) g1 = R1
(B) 6.675 × 10 −5 newton g 2 2
R2
−11 (D) g1 R31
(C) 6.675 × 10 newton g2
=
R32
Android App | iOS App | PW Website
