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CS 430 Midterm #2 Study Guide Solutions

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CS 430 Midterm #2 Study Guide Solutions Axioms, or rules of inference, provide a simpler technique for reasoning about functional dependencies. - ANSWERTrue If a relation r is legal under a set F of functional dependencies, we say that r satisfies F. - ANSWERTrue Some functional dependencies are said to be BLANK because they are satisfied by all relations. - ANSWERtrivial It is always possible to decompose a relation into 3NF form that is both lossless join and dependency preserving. - ANSWERTrue If we wish to constrain ourselves to relations on schema R that satisfy a set F of functional dependencies, we say that F BLANK on R. - ANSWERholds In general, the goal of a relational database design is to generate a set of relation schemas that allows us to store information without unnecessary redundancy and yet allows us to retrieve information easily. - ANSWERTrue ©EMILLECT 2024/2025 ACADEMIC YEAR. ALL RIGHTS RESERVED FIRST PUBLISH OCTOBER 2024 Page 2/61 A relation schema R is in third normal form with respect to set F of functional dependencies, if for all functional dependencies in F+ of the form A - B where A is a subset of R, B is an attribute of R, and at least on e of the following holds: * A - B is a trivial functional dependency * A is a superkey for R. * B is part of a key for R. * B is a superkey for R. * A is part of a key for R. - ANSWERA - B is a trivial functional dependency A is a superkey for R. B is part of a key for R. A functional dependency is a form of an integrity constraint. - ANSWERTrue Consider the following relation. Check all the answers

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©EMILLECT 2024/2025 ACADEMIC YEAR. ALL RIGHTS RESERVED

FIRST PUBLISH OCTOBER 2024




CS 430 Midterm #2 Study Guide Solutions


Axioms, or rules of inference, provide a simpler technique for reasoning about functional dependencies.

- ANSWER✔✔True


If a relation r is legal under a set F of functional dependencies, we say that r satisfies F. -

ANSWER✔✔True


Some functional dependencies are said to be BLANK because they are satisfied by all relations. -

ANSWER✔✔trivial


It is always possible to decompose a relation into 3NF form that is both lossless join and dependency

preserving. - ANSWER✔✔True


If we wish to constrain ourselves to relations on schema R that satisfy a set F of functional dependencies,

we say that F BLANK on R. - ANSWER✔✔holds


In general, the goal of a relational database design is to generate a set of relation schemas that allows us

to store information without unnecessary redundancy and yet allows us to retrieve information easily. -

ANSWER✔✔True




Page 1/61

, ©EMILLECT 2024/2025 ACADEMIC YEAR. ALL RIGHTS RESERVED

FIRST PUBLISH OCTOBER 2024




A relation schema R is in third normal form with respect to set F of functional dependencies, if for all

functional dependencies in F+ of the form A -> B where A is a subset of R, B is an attribute of R, and at

least on e of the following holds:




* A -> B is a trivial functional dependency


* A is a superkey for R.


* B is part of a key for R.


* B is a superkey for R.


* A is part of a key for R. - ANSWER✔✔A -> B is a trivial functional dependency


A is a superkey for R.


B is part of a key for R.


A functional dependency is a form of an integrity constraint. - ANSWER✔✔True


Consider the following relation. Check all the answers below that hold for this table.




A|B|C|D


Page 2/61

, ©EMILLECT 2024/2025 ACADEMIC YEAR. ALL RIGHTS RESERVED

FIRST PUBLISH OCTOBER 2024




a1 | b1 | c1 | d1


a2 | b3 | c1 | d2


a3 | b1 | c1 | d3


a2 | b7 | c1 | d5




* ABD -> C


* D -> ABC


* AB -> D


* AB -> CD


* B -> A


* A -> BC


* BC -> AD - ANSWER✔✔ABD -> C


D -> ABC


AB -> D




Page 3/61

, ©EMILLECT 2024/2025 ACADEMIC YEAR. ALL RIGHTS RESERVED

FIRST PUBLISH OCTOBER 2024




AB -> CD


Consider the relation R with attributes: A, B, C, D, E, and F. Let S be a set of functional dependencies in R

such that S = { A -> B, CD -> E, C -> D}. Which of these attributes are in the closure of {A, C, F}+?




A


B


C


D


E


F - ANSWER✔✔A


B


C


D


E


F

Page 4/61

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