Python Final UPDATED Exam Questions and CORRECT Answers

Python Final UPDATED Exam Questions
and CORRECT Answers
Which of the following code blocks produces the output given below?['odd', 'even', 'odd',
'even'] - CORRECT ANSWER✔✔- new_list = [3, 4, 5, 6]
for i in range(len(new_list)):
if new_list[i] % 2 == 0:
new_list[i] = 'even'
else:
new_list[i] = 'odd'
print(new_list)


Select the output generated by the following code:


new_list = [10, 10, 20, 20, 30, 40]
for i in range(3):
print(new_list[i])

new_value = new_list.pop(0) - CORRECT ANSWER✔✔- 10
20
30


What is output?


new_list = [10, 20, 30, 40]
for i in new_list[:]:
print(i)

new_value = new_list.pop(0) - CORRECT ANSWER✔✔- 10
20
30
40

,What is output?


b1 = [7, 5, 9, 6]
b1 = sorted(b1)
b2 = b1
b2.append(2)

print(b1, b2) - CORRECT ANSWER✔✔- [5, 6, 7, 9, 2] [5, 6, 7, 9, 2]


What is output?


b1 = [7, 5, 9, 6]
b1.sort()
b2 = b1.copy()
b1.append(10)
b2 = b2[::-1]

print(b1, b2) - CORRECT ANSWER✔✔- [5, 6, 7, 9, 10] [9, 7, 6, 5]


What is output?


b1 = [[7, 5, 9], [3, 2, 1]]
b1.sort()
b2 = b1[:]
print(b1, b2)
for elem in b2:
elem.sort()

print(b1, b2) - CORRECT ANSWER✔✔- [[3, 2, 1], [7, 5, 9]] [[3, 2, 1], [7, 5, 9]]
[[1, 2, 3], [5, 7, 9]] [[1, 2, 3], [5, 7, 9]]


Which of the following options can sort the list in descending order?

,i. list_name.sort(reverse=True)
ii. sorted(list_name, reverse=True)
iii. sorted(list_name)[::-1]

iv. sorted(list_name) - CORRECT ANSWER✔✔- i, ii, iii


What will be the date type for type(list_name.sort())

and type(sorted(list_name))? - CORRECT ANSWER✔✔- < class 'NoneType'>, < class 'list'>


Which of the following statements is incorrect for python dictionaries? - CORRECT
ANSWER✔✔- Dictionaries cannot contain objects of arbitrary type


What is the length of the dictionary my_dict = {'Country':'India', 'State': {'City':'Delhi',
'Temperature':40}}? - CORRECT ANSWER✔✔- 2


After the program runs, what is the value of y?


def print_sum(num1, num2)print(num1 + num2)y = print_sum(4, 5) - CORRECT
ANSWER✔✔- 9


Select the option to get the value of temperature from the dictionary my_dict =
{'Country':'India', 'State': {'City':'Delhi', 'Temperature':40}} - CORRECT ANSWER✔✔-
my_dict['State']['Temperature']


What is output?


my_dict = {'AA':3, 'BB': 2, 'CC':1, 'DD':0}
v1 = list(my_dict.keys())[list(my_dict.values()).index(1)]
v2 = {v:k for k, v in my_dict.items()}[0]

print(v1,v2) - CORRECT ANSWER✔✔- CC DD


What is output?

, dict = {1: 'X', 2: 'Y', 3: 'Z'}print(dict.get(2, 'A')) - CORRECT ANSWER✔✔- Y


What is output?


objects = {}objects['a'] = 'Chair'objects['b'] = 'Table'objects['c'] =
'Sofa'objects.clear()print(objects) - CORRECT ANSWER✔✔- {}


What is output?


dict1 = {1: 'Hi', 2: 'Bye'}dict2 = {2: 'Yes'}dict1.update(dict2)dict3 = {3:
'No'}dict1.update(dict3)print(dict1) - CORRECT ANSWER✔✔- {1: 'Hi', 2: 'Yes', 3: 'No'}


What is the value of rgb_a?


colors = {1: 'red', 2: 'green', 3: 'blue', 4: 'yellow'}popped_item = colors.pop(4)colors.update({
4: 'alpha'})rgb_a = {}rgb_a['items'] = colors - CORRECT ANSWER✔✔- { 'items': { 1: 'red',
2: 'green', 3: 'blue', 4: 'alpha'}}


Identify the error in the program given below.


my_dict = {'A' : 1, 'B' : 2, 'C' : 3, 'D' : 4, 'E' : 5}_popped = my_dict.pop('B', 6)print('Value
popped: ' + str(_popped))my_dict['F'] = 0_popped = my_dict.pop('F', 0)_popped =
my_dict.pop('B')print('Value popped: ' + str(_popped)) - CORRECT ANSWER✔✔-
my_dict.pop('B') causes error


How do you obtain a list of tuples of key-value pairs in a dictionary dict? - CORRECT
ANSWER✔✔- dict.items()


What is output?


mydict = {x: x*x for x in range(0, 5)}for data in mydict.values():print(data, end=' ') -
CORRECT ANSWER✔✔- 0 1 4 9 16