Stat 6.1 Study Guide Test 2024.

Stat 6.1 Study Guide Test 2024. A normal distribution is informally described as a probability distribution that is "bell-shaped" when graphed. Draw a rough sketch of a curve having the bell shape that is characteristic of a normal distribution. - CORRECT ANSWER What requirements are necessary for a normal probability distribution to be a standard normal probability distribution? - CORRECT ANSWER The mean and standard deviation have the values of u=0 and o=1. standard normal distribution - CORRECT ANSWER A normal distribution with a mean of 0 and a standard deviation of 1, and the total area under its density curve is 1. What does the notation z Subscript alpha indicate? - CORRECT ANSWER The expression z Subscript alpha denotes the z score with an area of alpha to its right. Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. - CORRECT ANSWER =.8554 Use DISTR button on calculator-- normalcdf(lower boundry, upper boundry, mean, stadnard deviation) Normalcdf(-1.06, 99999, 0, 1) Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. - CORRECT ANSWER normalcdf(-.82,1.22,0,1) = .6827 Finding standard normal distribution with the area - CORRECT ANSWER The total area under the curve is equal to 1. Use invnorm in calc with the percentage shown on the graph Find the indicated z score. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. - CORRECT ANSWER invrNorm(.7823)= .78 Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is less than negative 0.78 and draw a sketch of the region. - CORRECT ANSWER normalcdf(-99999,-.78,0,1)= .2177 Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find Upper P 5, the 5 th percentile. This is the bone density score separating the bottom 5 % from the top 95 %. - CORRECT ANSWER : p5 =z point where the area is shaded to the left invNorm(.05,0,1)= -1.64 Find the indicated critical value. Z(.06) - CORRECT ANSWER Za denotes a Z score with an area to its right invnorm (.06,0,1) = 1.55