11/11/2020 Southern New Hampshire University - 3-3 Problem Set: Module Three
[PRINT]
MAT-136-T2129 20EW2 Intro to Quantitative Analysis, 3-3 Problem Set: Module Three
Angie Mann, 11/11/20 at 3:28:44 PM EST
Question1: Score 3/3
Solve the inequality.
3x − 6 ≤ 9
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U. For example, to enter (−∞, 100] , type (-infinity,
100].
Your response Correct response
(-infinity,5] (-infinity, 5]
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
3x − 6 ≤ 9
3x ≤ 15
(
1
)3x ≤ 15 (
1
) Multiply by 1
.
3 3 3
x ≤ 5
Express the inequality in interval notation.
(−∞, 5]
Question2: Score 3/3
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,11/11/2020 Southern New Hampshire University - 3-3 Problem Set: Module Three
Solve the compound inequality.
3x + 2 > 2x − 3 > x − 13
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U. For example, to enter (−∞, 99) ∪ [101, ∞) , enter (-
infinity, 99) U ([101, infinity).
Your response Correct response
(-5,infinity) (-5, infinity)
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
Write two inequalities:
3x + 2 > 2x − 3 and 2x − 3 > x − 13
x + 2 > −3 x − 3 > −13
x > −5 x > −10
Therefore, the solution set is x > −5 or in interval notation (−5, ∞).
Question3: Score 3/3
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, 11/11/2020 Southern New Hampshire University - 3-3 Problem Set: Module Three
A basic cellular package costs $30/month for 60 minutes of calling with an additional charge of
$0.40 /minute beyond that time. The cost function C (x) for using x minutes would be
If you used 60 minutes or less, i.e. if if x ≤ 60, then C (x) = 30 (the base charge).
If you used more than 60 minutes, i.e. (x − 60) minutes more than the plan came with, you
would pay an additional $0.40 for each of those (x − 60) minutes. Your total bill would be
C (x) = 30 + 0.40 (x − 60) .
If you want to keep your bill at $50 or lower for the month, what is the maximum number of
calling minutes you can use?
The maximum calling minutes you can use is
Your response Correct response
110 110
Auto graded Grade: 1/1.0
minutes.
Total grade: 1.0×1/1 = 100%
Feedback:
We are given the cost formula for a phone plan, C = 30 + 0.40 (x − 60) . We need to find the
maximum minutes, x , if C ≤ 50.
Express the cost as an inequality, and solve for x .
C ≤ 50
30 + 0.40 (x − 60) ≤ 50
30 + 0.40x − 24 ≤ 50
0.40x ≤ 44
x ≤ 110
Therefore, to keep the bill at $50 or lower, you can use a maximum of 110 minutes.
https://snhu.mobius.cloud/modules/gradeProctoredTest.Login 3/20
[PRINT]
MAT-136-T2129 20EW2 Intro to Quantitative Analysis, 3-3 Problem Set: Module Three
Angie Mann, 11/11/20 at 3:28:44 PM EST
Question1: Score 3/3
Solve the inequality.
3x − 6 ≤ 9
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U. For example, to enter (−∞, 100] , type (-infinity,
100].
Your response Correct response
(-infinity,5] (-infinity, 5]
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
3x − 6 ≤ 9
3x ≤ 15
(
1
)3x ≤ 15 (
1
) Multiply by 1
.
3 3 3
x ≤ 5
Express the inequality in interval notation.
(−∞, 5]
Question2: Score 3/3
https://snhu.mobius.cloud/modules/gradeProctoredTest.Login 1/20
,11/11/2020 Southern New Hampshire University - 3-3 Problem Set: Module Three
Solve the compound inequality.
3x + 2 > 2x − 3 > x − 13
Enter the exact answer in interval notation.
To enter ∞ , type infinity. To enter ∪ , type U. For example, to enter (−∞, 99) ∪ [101, ∞) , enter (-
infinity, 99) U ([101, infinity).
Your response Correct response
(-5,infinity) (-5, infinity)
Auto graded Grade: 1/1.0
Total grade: 1.0×1/1 = 100%
Feedback:
Write two inequalities:
3x + 2 > 2x − 3 and 2x − 3 > x − 13
x + 2 > −3 x − 3 > −13
x > −5 x > −10
Therefore, the solution set is x > −5 or in interval notation (−5, ∞).
Question3: Score 3/3
https://snhu.mobius.cloud/modules/gradeProctoredTest.Login 2/20
, 11/11/2020 Southern New Hampshire University - 3-3 Problem Set: Module Three
A basic cellular package costs $30/month for 60 minutes of calling with an additional charge of
$0.40 /minute beyond that time. The cost function C (x) for using x minutes would be
If you used 60 minutes or less, i.e. if if x ≤ 60, then C (x) = 30 (the base charge).
If you used more than 60 minutes, i.e. (x − 60) minutes more than the plan came with, you
would pay an additional $0.40 for each of those (x − 60) minutes. Your total bill would be
C (x) = 30 + 0.40 (x − 60) .
If you want to keep your bill at $50 or lower for the month, what is the maximum number of
calling minutes you can use?
The maximum calling minutes you can use is
Your response Correct response
110 110
Auto graded Grade: 1/1.0
minutes.
Total grade: 1.0×1/1 = 100%
Feedback:
We are given the cost formula for a phone plan, C = 30 + 0.40 (x − 60) . We need to find the
maximum minutes, x , if C ≤ 50.
Express the cost as an inequality, and solve for x .
C ≤ 50
30 + 0.40 (x − 60) ≤ 50
30 + 0.40x − 24 ≤ 50
0.40x ≤ 44
x ≤ 110
Therefore, to keep the bill at $50 or lower, you can use a maximum of 110 minutes.
https://snhu.mobius.cloud/modules/gradeProctoredTest.Login 3/20
