Continue Practice Exam Test Problem 55
Questions Part 2 of the Series
If p is an odd number and q is an even
Choose the letter of the best answer number, which of the following
in each questions. expressions must be even?
Problem 51 (ME Board) A. p + q
Change 0.222… common fraction. B. p – q
A. 2/10 C. pq
B. 2/9 D. p/q
C. 2/13 Problem 56 (ECE March 1996)
D. 2/7 MCMXCIV is a Roman Numeral equivalent
to:
Problem 52 (ME Board)
A. 2974
Change 0.2272722… to a common fraction.
B. 3974
A. 7/44
C. 2174
B. 5/48
D. 1994
C. 5/22
Problem 57 (ECE April 1998)
D. 9/34
What is the lowest common factor of 10
Problem 53 (ME Board) and 32?
What is the value of 7! or 7 factorial? A. 320
A. 5040 B. 2
B. 2540 C. 180
C. 5020 D. 90
D. 2520 Problem 58
Problem 54 (ME October 1994) 4xy – 4x2 –y2 is equal to:
The reciprocal of 20 is: A. (2x – y)2
A. 0.50 B. (-2x – y)2
B. 20 C. (-2x + y)2
C. 0.20 D. –(2x – y)2
D. 0.05 Problem 59
, Factor x4 – y2 + y – x2 as completely as A. 3x(x + 2)(x – 3)
possible.
B. 3x(x – 2)(x + 3)
A. (x2 + y)(x2 + y -1)
C. 3x(x – 3)(x + 6)
B. (x2 + y)(x2 – y -1)
D. (3x2 – 6x)(x – 1)
C. (x2 – y)(x2 – y -1)
Problem 64 (ME April 1998)
D. (x2 – y)(x2 + y -1)
Factor the expression 16 – 10x + x2.
Problem 60 (ME April 1996)
A. (x + 8)(x – 2)
Factor the expression x2 + 6x + 8 as
completely as possible. B. (x – 8)(x – 2)
A. (x + 8)(x – 2) C. (x – 8)(x + 2)
B. (x + 4)(x + 2) D. (x + 8)(x + 2)
C. (x + 4)(x – 2) Problem 65
D. (x – 8)(x – 2) Factor the expression x6 – 1 as completely
as possible.
Problem 61 (ME October 1997)
A. (x + 1)(x – 1)(x4 + x2 – 1)
Factor the expression x3 + 8.
B. (x + 1)(x – 1)(x4 + 2x2 + 1)
A. (x – 2)(x2 + 2x + 4)
C. (x + 1)(x – 1)(x4 – x2 + 1)
B. (x + 4)(x2 + 2x + 2)
D. (x + 1)(x – 1)(x4 + x2 + 1)
C. (-x + 2)(-x2 + 2x + 2)
Problem 66
D. (x + 2)(x2 – 2x + 4)
What are the roots of the equation (x –
Problem 62 (ME October 1997) 4)2(x + 2) = (x + 2)2(x – 4)?
Factor the expression (x4 – y4) as A. 4 and -2 only
completely as possible.
B. 1 only
A. (x + y)(x2 + 2xy + y)
C. -2 and 4 only
B. (x2 + y2)(x2 – y2)
D. 1, -2, and 4 only
C. (x2 + y2)(x + y)(x – y)
Problem 67
D. (1 + x2)(1 + y)(1 – y2)
If f(x) = x2 + x + 1, then f(x) – f(x-1) =
Problem 63 (ME October 1997)
A. 0
Factor the expression 3x3 + 3x2 – 18x as
completely as possible. B. x
Questions Part 2 of the Series
If p is an odd number and q is an even
Choose the letter of the best answer number, which of the following
in each questions. expressions must be even?
Problem 51 (ME Board) A. p + q
Change 0.222… common fraction. B. p – q
A. 2/10 C. pq
B. 2/9 D. p/q
C. 2/13 Problem 56 (ECE March 1996)
D. 2/7 MCMXCIV is a Roman Numeral equivalent
to:
Problem 52 (ME Board)
A. 2974
Change 0.2272722… to a common fraction.
B. 3974
A. 7/44
C. 2174
B. 5/48
D. 1994
C. 5/22
Problem 57 (ECE April 1998)
D. 9/34
What is the lowest common factor of 10
Problem 53 (ME Board) and 32?
What is the value of 7! or 7 factorial? A. 320
A. 5040 B. 2
B. 2540 C. 180
C. 5020 D. 90
D. 2520 Problem 58
Problem 54 (ME October 1994) 4xy – 4x2 –y2 is equal to:
The reciprocal of 20 is: A. (2x – y)2
A. 0.50 B. (-2x – y)2
B. 20 C. (-2x + y)2
C. 0.20 D. –(2x – y)2
D. 0.05 Problem 59
, Factor x4 – y2 + y – x2 as completely as A. 3x(x + 2)(x – 3)
possible.
B. 3x(x – 2)(x + 3)
A. (x2 + y)(x2 + y -1)
C. 3x(x – 3)(x + 6)
B. (x2 + y)(x2 – y -1)
D. (3x2 – 6x)(x – 1)
C. (x2 – y)(x2 – y -1)
Problem 64 (ME April 1998)
D. (x2 – y)(x2 + y -1)
Factor the expression 16 – 10x + x2.
Problem 60 (ME April 1996)
A. (x + 8)(x – 2)
Factor the expression x2 + 6x + 8 as
completely as possible. B. (x – 8)(x – 2)
A. (x + 8)(x – 2) C. (x – 8)(x + 2)
B. (x + 4)(x + 2) D. (x + 8)(x + 2)
C. (x + 4)(x – 2) Problem 65
D. (x – 8)(x – 2) Factor the expression x6 – 1 as completely
as possible.
Problem 61 (ME October 1997)
A. (x + 1)(x – 1)(x4 + x2 – 1)
Factor the expression x3 + 8.
B. (x + 1)(x – 1)(x4 + 2x2 + 1)
A. (x – 2)(x2 + 2x + 4)
C. (x + 1)(x – 1)(x4 – x2 + 1)
B. (x + 4)(x2 + 2x + 2)
D. (x + 1)(x – 1)(x4 + x2 + 1)
C. (-x + 2)(-x2 + 2x + 2)
Problem 66
D. (x + 2)(x2 – 2x + 4)
What are the roots of the equation (x –
Problem 62 (ME October 1997) 4)2(x + 2) = (x + 2)2(x – 4)?
Factor the expression (x4 – y4) as A. 4 and -2 only
completely as possible.
B. 1 only
A. (x + y)(x2 + 2xy + y)
C. -2 and 4 only
B. (x2 + y2)(x2 – y2)
D. 1, -2, and 4 only
C. (x2 + y2)(x + y)(x – y)
Problem 67
D. (1 + x2)(1 + y)(1 – y2)
If f(x) = x2 + x + 1, then f(x) – f(x-1) =
Problem 63 (ME October 1997)
A. 0
Factor the expression 3x3 + 3x2 – 18x as
completely as possible. B. x
