Bch361 Exam 1 (Chapters 1-6) Updated Questions And Correct Answers

BCH361 EXAM 1 (CHAPTERS 1-6) UPDATED QUESTIONS
AND CORRECT ANSWERS
Question:
1. a) A, B
b) A and C, B and C
c) -30.5 + 16.3 = -14.2 or
-30.5 + 13.8 = -16.7
Answer:
(CH4)
c) ∆G=?
(if you selected more than one pair of reactions in part (b), enter the net change for any one of your
selected sets)




Question:
2. Reactions B and F
Answer:
(CH4)




Question:
3. B, D, and E
Answer:
(CH4)




Question:
4. Energy: ATP in muscles
Answer:
(CH4)

Question:
5. Work: the paddle hits the ball, muscle contraction
Answer:

Question:
6. ∆G=∆G°'+RT ln([C][D]/[A][B]) =7.53kJ/mol+(8.315x10⁻³)*298K*ln(0.003/0.1) =-1.16

, Answer:
(CH4)

Question:
7. Decreases ∆G:
coupling with ATP hydrolysis, Increasing[A] and [B]
Answer:
(CH4)

Question:
8. Increases ∆G:
Increasing [C] and [D]
Answer:

Question:
9. no effect:
adding a catalyst
Answer:

Question:
10. The change in free energy (ΔG) is given by:
∆G=∆G°'+RT ln([C][D]/[A][B]) where ΔG°\' is the standard free energy change, R is the gas
constant, and T is the temperature, [A], [B], [C], and [D] are the molar concentrations of the reactants,
[A] and [B], and products, [C] and [D].
Reactions that cannot occur spontaneously have a positive value for free energy change ( ΔG).
Altering the conditions of a reaction can make a reaction more favorable by decreasing ΔG. Coupling
the reaction with ATP hydrolysis will decrease ΔG.
Coupling a reaction with the hydrolysis of ATP allows an unfavorable reaction to proceed.
Decreasing the molar concentrations of the products or increasing the molar concentrations of the
reactants will decrease ΔG : If the ratio decreases, the natural log decreases and ΔG decreases, and
vice versa. To increase ΔG, the molar concentrations of the products can be increased or the molar
concentrations of the reactants can be decreased. Both changes will increase ΔG. The addition of a
catalyst will not affect ΔG. Catalysts help a reaction to reach equilibrium more quickly by lowering
the activation energy, not ΔG.
Answer:

Question:
11. ATP+H₂O→ADP+Pi ADP+H₂O→AMP+Pi
Answer:
(CH4)

Question:
12. The bond between the first P and the second O atoms is broken.
Answer:
(CH4)

Question:
13. The P-O

, Answer:

Question:
14. The terminal phosphoryl group is removed (PO₃²⁻) the phosphorus and its 3 oxygen atoms)
Answer:
(CH4)

Question:
15. The ∆G for the reaction is -7.3kcal/mol or -30.5kJ/mol (as per text).
Answer:

Question:
16. a) myosin action during muscle contraction, membrane transport that maintains Na⁺ levels in
cells, & de novo (from scratch) anabolism of nucleotides
Answer:
(CH4)

Question:
17. b) resonance stabilization of free phosphate and electrostatic repulsion in ATP
Answer:

Question:
18. glucose→glucose-1-phosphate ∆G°'=20.9kJ/mol
Answer:
(CH4)

Question:
19. ATP→ADP ∆G⁰'=-30kJ/mol
Answer:

Question:
20. -30.5+20.9=-9.5 reaction a proceeds to the right.
Answer:

Question:
21. b) -30.5+49.3=18.8 ←
c) -30.5+43.0=12.5 ←
Answer:

Question:
22. What is the direction of the overall reaction? Recall that standard free energy changes are
additive. Recall that if ΔG°\' for the overall, coupled reaction is negative, the reaction proceeds to the
right; if ΔG°\' is positive, the reaction proceeds in reverse. Be careful when changing the sign of
ΔG°\'; check that you change the sign for the correct reaction.
Answer: