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Cse/Eee 120 Labs 1–4 Comprehensive Examination Review: Study Guide | Latest Update 2026/2027 | Practice Questions And Answers | Exam Review.

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This comprehensive examination preparation document is designed for candidates preparing for the CSE/EEE 120 Digital Design Fundamentals Labs 1–4 examination review at Arizona State University. The examination assesses mastery of the practical digital design concepts covered in the laboratory sequence, including combinational logic circuits, adders, multiplexers, decoders, arithmetic logic units, and elementary microprocessor design. Questions are calibrated to the rigor of the 2026 lab practical and written examination blueprint, emphasizing circuit analysis, truth tables, Boolean algebra, binary arithmetic, and digital system debugging. Candidates will encounter scenarios drawn from the laboratory environment, including Quartus and Digital simulation tools, waveform verification, circuit construction constraints, and microprocessor fetch-execute cycle analysis. The content reflects the most current laboratory objectives, including half adder and full adder design, 4-bit incrementer implementation, multiplexer and decoder synthesis, ALU operation, and the complete Brainless microprocessor design with instruction PROM programming and memory execution.

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CSE/EEE 120 LABS 1–4 COMPREHENSIVE
EXAMINATION REVIEW: STUDY GUIDE |
LATEST UPDATE 2026/2027 | PRACTICE
QUESTIONS AND ANSWERS | EXAM REVIEW.




TABLE OF CONTENTS

I. Lab 1: Half Adder, Full Adder, 4-bit Incrementer and Adder
II. Lab 2: Multiplexers, Decoders and the Arithmetic Logic Unit
III. Lab 3: Advanced ALU Operations and Circuit Testing
IV. Lab 4: The Complete Microprocessor
V. Digital Logic Fundamentals and Circuit Constraints
VI. Binary Number Systems, Arithmetic, and Codes

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question 1: What is the primary function of a half adder?

Correct Answer: To add two single-bit binary numbers and produce a sum and a carry
output.

A half adder is the fundamental building block for binary addition. It has two inputs (A and
B) and two outputs: Sum (A XOR B) and Carry (A AND B). It cannot handle a carry input,
which is why a full adder is needed for multi-bit addition.

question 2: What is the Boolean expression for the Sum output of a half adder?

Correct Answer: Sum = A ⊕ B

The Sum output is the XOR of the two inputs. This is because the sum is 1 only when exactly
one of the inputs is 1. The Carry output is A AND B, which is 1 only when both inputs are 1.

question 3: What is the Boolean expression for the Carry output of a half adder?

Correct Answer: Carry = A · B

The Carry output is the AND of the two inputs. A carry is generated only when both input bits
are 1. This represents the overflow into the next bit position in binary addition.

question 4: How many input combinations does a half adder truth table have?

Correct Answer: 4

A half adder has two inputs, so the truth table has 2² = 4 rows. The combinations are 00, 01,
10, and 11. For each combination, the Sum and Carry outputs are specified.

question 5: What is the output of a half adder when both inputs are 1?

Correct Answer: Sum = 0, Carry = 1

When both inputs are 1, the sum of 1 + 1 = 10 in binary. The Sum bit is 0 and the Carry bit is
1. This is the only combination that produces a carry output in a half adder.

question 6: What is the primary function of a full adder?

Correct Answer: To add three single-bit binary numbers (two data bits and a carry-in)
and produce a sum and a carry-out.

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A full adder extends the half adder by including a carry-in input. This allows multiple full
adders to be cascaded to add multi-bit numbers. The full adder has three inputs (A, B, Cin)
and two outputs (Sum, Cout).

question 7: What is the Boolean expression for the Sum output of a full adder?

Correct Answer: Sum = A ⊕ B ⊕ Cin

The Sum output is the XOR of all three inputs. This produces a 1 when an odd number of
inputs are 1. This is the fundamental property of binary addition with carry propagation.

question 8: What is the Boolean expression for the Carry-out of a full adder?

Correct Answer: Cout = (A · B) + (Cin · (A ⊕ B))

The Carry-out is 1 when at least two of the three inputs are 1. This can be expressed as the
majority function. An alternative form is Cout = (A · B) + (B · Cin) + (A · Cin).

question 9: How many input combinations does a full adder truth table have?

Correct Answer: 8

A full adder has three inputs, so the truth table has 2³ = 8 rows. The combinations range from
000 to 111. For each combination, the Sum and Carry-out outputs are specified.

question 10: What is the output of a full adder when A = 1, B = 1, and Cin = 1?

Correct Answer: Sum = 1, Cout = 1

When all three inputs are 1, the sum is 1 + 1 + 1 = 11 in binary. The Sum bit is 1 and the
Carry-out bit is 1. This represents the maximum output of a full adder.

question 11: How can a full adder be constructed from two half adders?

Correct Answer: Connect the Sum of the first half adder to one input of the second half
adder, with Cin as the other input; the final Sum is the Sum of the second half adder,
and Cout is the OR of the two carry outputs.

The first half adder adds A and B, producing an intermediate sum and carry. The second half
adder adds the intermediate sum with Cin. The final carry-out is the OR of the two carry
outputs because a carry is generated if either stage produces one.

question 12: What is a 4-bit ripple-carry adder?

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Subido en
30 de septiembre de 2026
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