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Examen

INTRODUCTION TO EVOLUTION BZ 220, EXAMS OF THEORY OF EVOLUTION FULL PACKAGE

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INTRODUCTION TO EVOLUTION BZ 220, EXAMS OF THEORY OF EVOLUTION FULL PACKAGE

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1


INTRODUCTION TO EVOLUTION BZ 220, EXAMS OF

THEORY OF EVOLUTION FULL PACKAGE QUESTIONS

ANSWERS AND RATIONALES 2026-27 LATEST UPDATED

VERSION

INSTANT DOWNLOAD PDF..!!

Introduction

Welcome to the premium practice question bank for Introduction to Evolution | BZ 220,
Exams of Theory of Evolution. This comprehensive diagnostic study package has been
explicitly engineered for university students, evolutionary biologists, and researchers seeking
absolute mastery over the core mechanics, historical foundations, and quantitative
methodologies of evolutionary biology. Modern evolutionary theory serves as the unifying
architecture of all biological sciences. Evaluation within this domain requires a sophisticated
grasp of diverse concepts, including the application of the Hardy-Weinberg equilibrium to
multi-allelic systems, the nuances of non-neutral molecular evolution, complex phylogenetic
character reconstruction, and the quantitative mechanics of phenotypic selection. This test
bank bridges fundamental conceptual frameworks with advanced analytical and
mathematical applications, preparing you thoroughly to pass your examination on the very
first attempt.

Core Domains Tested

1. History of Evolutionary Thought, Deep Time, and the Fossil Record

2. Population Genetics, Forces of Microevolution, and Quantitative Selection
Mechanics

3. Phylogenetics, Systematics, Molecular Evolution, and Tree Thinking

4. Macroevolution, Speciation Mechanisms, Adaptive Radiations, and Deep-Time
Trends

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1.

In a large, randomly mating population, the frequency of an
autosomal recessive disease is 1 in 2,500 (\(0.0004\)). Assuming the
population is in Hardy-Weinberg equilibrium, what is the expected
frequency of carriers (heterozygotes) in this population?

A.

0.02

B.

0.0392

C.

0.04

D.

0.9604

Show hint

First find \(q\) by taking the square root of the affected genotype
frequency (\(q^{2}\)). Then determine \(p\) and compute \(2pq\).

Next

Q1: In a population of diploid organisms, a single locus has two
alleles, A and a. If the fitness of genotype AA is 1.0, the fitness of

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Aa is 1.0, and the fitness of aa is 0.4, which selection model is
acting on this locus, and what will be the long-term equilibrium
frequency of allele A assuming no mutation or drift?

A) Directional selection against a dominant allele; frequency of A
approaches 0.
B) Directional selection against a recessive allele; frequency of A
approaches 1.0.
C) Overdominance; both alleles persist at equal equilibrium
frequencies.
D) Underdominance; the population reaches an unstable equilibrium
point at 0.6.
Rationale: Because both AA and Aa exhibit a fitness of 1.0, the a
allele is completely recessive. The selection coefficient (s) acts
exclusively against the aa homozygotes (s = 0.6). Under directional
selection targeting a harmful recessive allele, the dominant beneficial
allele A will increase in frequency over generations and
asymptotically approach fixation (1.0), although the rate of
elimination slows down as allele a becomes rare and hidden in
heterozygotes.

Q2: A researcher measures the phenotypic variance (\(V_{P}\)) of
tail length in a population of wild mice and finds it to be 40.0. If the
additive genetic variance (\(V_{A}\)) is 10.0, the dominance genetic

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variance (\(V_{D}\)) is 5.0, and the epistatic variance (\(V_{I}\)) is
5.0, what is the narrow-sense heritability (\(h^{2}\)) of this trait?

A) 0.50
B) 0.375
C) 0.25
D) 0.125
Rationale: Narrow-sense heritability (\(h^{2}\)) is explicitly defined as
the proportion of total phenotypic variance attributable to additive
genetic variance alone (\(h^2 = V_A / V_P\)). Placed into the
mathematical equation: \(h^2 = 10..0 = 0.25\). Broad-sense
heritability (\(H^{2}\)), by contrast, accounts for total genetic
variance (\(V_A + V_D + V_I = 20.0\)), which would equal 0.50.

Q3: Which of the following statements correctly differentiates the
biological species concept (BSC) from the phylogenetic species
concept (PSC)?

A) The BSC focuses on morphological diagnostic features, whereas
the PSC focuses strictly on ecological niches.
B) The BSC can be easily applied to asexual and fossil taxa, while the
PSC requires alive, obligate outcrossing organisms.
C) The BSC defines species based on reproductive isolation,
whereas the PSC identifies species as the smallest monophyletic
groups possessing shared derived traits.
D) The BSC requires complete genomic identity between individuals,

Información del documento

Subido en
5 de septiembre de 2026
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67
Escrito en
2026/2027
Tipo
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