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NSG5140 Week 5 Midterm Exam Due 30th September Complete Actual Exam Questions 1- 50 Screenshots NSG 5140 Advanced Pathophysiology NSG5140 Online Exam Requires Respondus Lockdown Browser + Webcam Exam Questions and Answers | 100% Pass Guaranteed

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Prepare for the NSG 5140 Week 5 Midterm with 50 practice questions and answers covering Advanced Pathophysiology concepts. Review key topics, test your knowledge, and strengthen weak areas with this focused exam-prep resource.

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NSG5140 Week 5 Midterm Exam Due 30th September
Complete Actual Exam Questions 1- 50 Screenshots
NSG 5140 Advanced Pathophysiology NSG5140 Online
Exam Requires Respondus Lockdown Browser +
Webcam Exam Questions and Answers | 100% Pass
Guaranteed | Graded A



PART 1 — QUESTIONS 1–50
Question 1. A patient with carbon monoxide poisoning develops cellular hypoxia
despite normal arterial oxygen tension. Which cellular mechanism best explains the
tissue injury?

A. Direct inhibition of mitochondrial DNA replication
B. CO binding to cytochrome c oxidase with higher affinity than oxygen, blocking
oxidative phosphorylation
C. Activation of anaerobic glycolysis pathways
D. Increased ATP production through substrate-level phosphorylation

Correct Answer: B

Rationale: Carbon monoxide binds to cytochrome c oxidase (Complex IV) with 240
times greater affinity than oxygen, disrupting the electron transport chain and halting
oxidative phosphorylation . This produces cellular energy failure, lactic acidosis, and
ultimately necrosis in oxygen-dependent tissues despite adequate oxygen delivery to
the bloodstream.




Question 2. A patient receiving radiation therapy develops DNA double-strand breaks
in rapidly dividing cells. Which cellular response pathway determines whether the cell
undergoes repair, senescence, or death?

,A. Insulin signaling cascade
B. ATM/ATR-mediated DNA damage response with p53 activation
C. Estrogen receptor signaling
D. Toll-like receptor activation

Correct Answer: B

Rationale: The DNA damage response is orchestrated by ATM and ATR kinases that
sense double-strand breaks and phosphorylate p53. p53 activation determines cell fate:
transient arrest for repair, permanent senescence via p21, or apoptosis via Bax/Bcl-2
modulation .




Question 3. A patient with ischemic stroke exhibits neuronal death in the penumbra
over 6–12 hours despite reperfusion. Which mechanism best explains this delayed cell
death?

A. Immediate coagulative necrosis from ATP depletion
B. Excitotoxicity with glutamate-mediated calcium influx, mitochondrial permeability
transition, and caspase activation
C. Pure apoptosis without necrotic features
D. Direct bacterial invasion

Correct Answer: B

Rationale: Ischemic penumbra injury involves glutamate excitotoxicity where energy
failure impairs glutamate reuptake, causing sustained NMDA receptor activation.
Excessive calcium influx triggers mitochondrial permeability transition pore opening,
generating ROS and releasing cytochrome c that activates caspase-9 and the apoptotic
cascade .




Question 4. A patient with chronic alcoholism develops hepatic steatosis. Which cellular
adaptation process is occurring?

A. Hypertrophy from increased functional demand
B. Accumulation of triglycerides within hepatocytes due to altered NADH/NAD⁺ ratio
and impaired beta-oxidation

,C. Hyperplasia from cellular proliferation
D. Metaplasia from chronic irritation

Correct Answer: B

Rationale: Alcohol metabolism generates excess NADH, shifting the redox state and
inhibiting fatty acid beta-oxidation while promoting lipogenesis. Triglyceride
accumulation within hepatocytes produces steatosis—a form of intracellular
accumulation rather than true adaptation .




Question 5. A patient with Barrett's esophagus demonstrates columnar epithelium
replacing squamous epithelium. This cellular adaptation is classified as:

A. Dysplasia
B. Metaplasia
C. Anaplasia
D. Neoplasia

Correct Answer: B

Rationale: Metaplasia is the reversible replacement of one differentiated cell type with
another better suited to withstand chronic irritation. In Barrett's esophagus, chronic acid
reflux causes squamous epithelium to transform into intestinal-type columnar
epithelium with goblet cells .




Question 6. A patient with emphysema has destruction of alveolar walls with loss of
elastic recoil. Which protease-antiprotease imbalance mechanism explains this injury?

A. Excessive alpha-1-antitrypsin production
B. Neutrophil and macrophage elastase overwhelming alpha-1-antitrypsin, destroying
elastin fibers
C. Collagen synthesis inhibition
D. Direct cigarette smoke toxicity to type I pneumocytes

Correct Answer: B

, Rationale: Emphysema results from an imbalance between proteases and antiproteases.
Neutrophil and macrophage elastase destroy elastin fibers when they overwhelm the
protective effects of alpha-1-antitrypsin .




Question 7. Which of the following is the primary mechanism of cellular injury in
hypoxic conditions?

A. DNA mutation
B. ATP depletion leading to loss of ion homeostasis
C. Free radical formation
D. Protein misfolding

Correct Answer: B

Rationale: Hypoxia limits oxidative phosphorylation, leading to decreased ATP
production. The Na⁺/K⁺ ATPase pump requires ATP to maintain ion gradients; failure of
this pump causes intracellular sodium accumulation, water influx, and cellular swelling—
the hallmark of hypoxic cellular injury .




Question 8. A patient with chronic hypertension develops left ventricular hypertrophy.
Which cellular adaptive change is most likely occurring?

A. Atrophy
B. Hyperplasia
C. Hypertrophy
D. Metaplasia

Correct Answer: C

Rationale: Cardiac myocytes are terminally differentiated and respond to increased
workload primarily through hypertrophy (an increase in individual cell size), not
hyperplasia (an increase in cell number). This adaptation compensates for increased
afterload from hypertension .

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Subido en
1 de septiembre de 2026
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