EDEXCEL MATHS A LEVEL PURE MATHS 1
COMPETENCY REVIEW 2026 MOCK TEST
COMPLETE KEY INSIGHTS
◉ Volume of a cone.
Answer: V=1/3πr²h
◉ Surface area of a cone.
Answer: SA=πrl+πr²
(l=slant height)
◉ Volume of a sphere.
Answer: V=4/3πr³
◉ Surface area of a sphere.
Answer: SA=4πr²
◉ Volume of a cyclinder.
Answer: V=πr²h
◉ Surface area of a cyclinder.
,Answer: SA = 2 π r^2 (circles) + 2 π r h (rectangle)
◉ Area of a trapezium.
Answer: 1/2(a+b)h
◉ Area of a right angle triangle.
Answer: A= 1/2 bh
◉ Area of any triangle.
Answer: 1/2absinC
◉ Area of a circle.
Answer: A=πr²
◉ Circumference of a circle.
Answer: C=2πr or C=πd
◉ 1 Radian.
Answer: 180/π
◉ 2π in degrees.
Answer: 360
, ◉ Arc Length.
Answer: r x θ - where r is radius and θ is the angle in radians
◉ Area of a Sector.
Answer: 1/2 x θ x r²
◉ Area of a Segment.
Answer: ½r²(θ - sinθ)
◉ when θ is small sinθ.
Answer: sinθ = θ
◉ when θ is small cosθ.
Answer: cosθ = 1 - θ²/2
◉ when θ is small tanθ.
Answer: tanθ = θ
◉ y = secx graph.
Answer: range y ≥ 1 or y ≤ -1
COMPETENCY REVIEW 2026 MOCK TEST
COMPLETE KEY INSIGHTS
◉ Volume of a cone.
Answer: V=1/3πr²h
◉ Surface area of a cone.
Answer: SA=πrl+πr²
(l=slant height)
◉ Volume of a sphere.
Answer: V=4/3πr³
◉ Surface area of a sphere.
Answer: SA=4πr²
◉ Volume of a cyclinder.
Answer: V=πr²h
◉ Surface area of a cyclinder.
,Answer: SA = 2 π r^2 (circles) + 2 π r h (rectangle)
◉ Area of a trapezium.
Answer: 1/2(a+b)h
◉ Area of a right angle triangle.
Answer: A= 1/2 bh
◉ Area of any triangle.
Answer: 1/2absinC
◉ Area of a circle.
Answer: A=πr²
◉ Circumference of a circle.
Answer: C=2πr or C=πd
◉ 1 Radian.
Answer: 180/π
◉ 2π in degrees.
Answer: 360
, ◉ Arc Length.
Answer: r x θ - where r is radius and θ is the angle in radians
◉ Area of a Sector.
Answer: 1/2 x θ x r²
◉ Area of a Segment.
Answer: ½r²(θ - sinθ)
◉ when θ is small sinθ.
Answer: sinθ = θ
◉ when θ is small cosθ.
Answer: cosθ = 1 - θ²/2
◉ when θ is small tanθ.
Answer: tanθ = θ
◉ y = secx graph.
Answer: range y ≥ 1 or y ≤ -1
