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WGU D027 Objective Assessment Final Exam 2026/2027 – Complete Questions with Correct Detailed Answers and Rationales (100% Guaranteed Pass)

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This document provides the complete set of verified exam questions with correct detailed answers and rationales for the WGU D027 Objective Assessment Final 2025/2026. It covers all essential subject areas tested in the course, offering in-depth explanations to reinforce understanding and strengthen critical thinking. Designed for accuracy and clarity, this resource equips students with reliable preparation material to ensure exam readiness and success.

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WGU D027




WGU D027 Objective Assessment Final Exam
2025/2026 – Complete Questions with Correct
Detailed Answers and Rationales (100%
Guaranteed Pass)




Cellular & Molecular Basis of Disease

1. A patient with chronic alcoholism develops megaloblastic anemia. Which cellular process is
most directly impaired?

• A) Iron incorporation into heme

• B) Globin chain synthesis

• C) Erythropoietin production

• D) DNA synthesis due to folate/B12 deficiency
Rationale: Chronic alcoholism impairs folate absorption and utilization. This leads to
defective DNA synthesis in red blood cell (RBC) precursors, causing megaloblastic anemia.
Iron incorporation issues describe iron deficiency anemia, and erythropoietin production is
related to renal function .

2. In Duchenne muscular dystrophy, the primary pathophysiological mechanism is:

• A) Autoimmune destruction of acetylcholine receptors

• B) Absence of dystrophin leading to sarcolemmal instability

• C) Mitochondrial DNA mutation in muscle cells

• D) Abnormal calcium channel function in sarcoplasmic reticulum
Rationale: Duchenne muscular dystrophy is caused by a deficiency of dystrophin, a protein
that stabilizes the muscle cell membrane (sarcolemma). Without it, the membrane becomes
fragile, leading to muscle fiber necrosis and replacement by fat and fibrous tissue .

3. A drug that inhibits caspase-3 activity would most directly prevent:

• A) Necrosis from hypoxia

• B) Apoptosis

• C) Autophagy

• D) Ferroptosis
Rationale: Caspase-3 is a key executioner caspase in the apoptotic pathway. Its activation

, WGU D027

leads to the cleavage of various cellular proteins, resulting in programmed cell death.
Inhibiting it would therefore directly prevent apoptosis .

4. A researcher is studying a drug that stabilizes hypoxia-inducible factor (HIF)-1α. This drug would
be expected to:

• A) Decrease erythropoietin production

• B) Increase VEGF expression and angiogenesis

• C) Block glycolysis in ischemic tissue

• D) Reduce tumor growth
Rationale: HIF-1α is a transcription factor that is stabilized under hypoxic conditions. It
promotes the expression of genes like VEGF (vascular endothelial growth factor) to stimulate
angiogenesis and erythropoietin (EPO) to increase red blood cell production .

5. Which cellular change is a characteristic sign of irreversible cell injury?

• A) Plasma membrane blebbing

• B) Nuclear pyknosis, karyorrhexis, and karyolysis

• C) Swelling of the endoplasmic reticulum

• D) Loss of microvilli
Rationale: While plasma membrane blebbing and ER swelling are signs of reversible injury,
irreversible injury is marked by nuclear changes, including pyknosis (nuclear shrinkage),
karyorrhexis (nuclear fragmentation), and karyolysis (nuclear dissolution) .

6. The NLRP3 inflammasome is a key mediator of inflammation. Its activation would be most
directly implicated in the pathophysiology of:

• A) Allergic rhinitis

• B) Gouty arthritis

• C) Type I diabetes

• D) Anaphylaxis
Rationale: The NLRP3 inflammasome is activated by various crystals, including monosodium
urate crystals that cause gout. Its activation leads to the release of IL-1β, a potent pro-
inflammatory cytokine .

7. The tumor suppressor gene p53 is often called the "guardian of the genome" because it can:

• A) Promote DNA repair or apoptosis in damaged cells

• B) Activate telomerase to prevent cellular senescence

• C) Inhibit angiogenesis

• D) Suppress immune checkpoints
Rationale: p53 responds to cellular stress and DNA damage by inducing cell cycle arrest (to
allow for DNA repair), or if the damage is irreparable, by initiating apoptosis. This prevents
the propagation of damaged cells that could become cancerous .

, WGU D027

8. A patient with hereditary hemochromatosis develops cirrhosis. The excess iron causes tissue
damage primarily via:

• A) The Fenton reaction generating hydroxyl radicals

• B) Direct activation of caspases

• C) Inhibition of mitochondrial complex IV

• D) Cross-linking of collagen fibers
Rationale: Iron catalyzes the Fenton reaction, producing highly reactive hydroxyl radicals
that cause lipid peroxidation and DNA damage. This oxidative stress leads to tissue injury
and fibrosis, resulting in cirrhosis .

9. A patient's tumor biopsy shows high PD-L1 expression. This finding indicates the tumor is
evading the immune system through:

• A) Increased antigen presentation

• B) T-cell inhibition

• C) High mutational burden

• D) Hormone receptor positivity
Rationale: Programmed death-ligand 1 (PD-L1) on tumor cells binds to the PD-1 receptor on
T-cells. This interaction sends an inhibitory signal, effectively "turning off" the T-cell and
allowing the tumor to escape immune destruction .

10. In celiac disease, ingestion of gluten triggers an immune response that is primarily:

• A) IgE and mast cell mediated (Type I)

• B) IgA antibody mediated against tissue transglutaminase (Type II)

• C) CD8+ T-cell mediated attacking enterocytes (Type II)

• D) Type IV delayed hypersensitivity mediated by CD4+ T cells
Rationale: Celiac disease is a Type IV hypersensitivity reaction. Gluten peptides are
presented by HLA-DQ2/D8 molecules on antigen-presenting cells, which activate CD4+ T-
cells. This leads to an inflammatory response causing damage to the intestinal mucosa .

Genetics & Inheritance

11. A 6-month-old female infant with failure to thrive has facial deformities and is jaundiced. A
CBC reveals anemia, and blood smear shows small, abnormally shaped RBCs. If both parents are
carriers for alpha thalassemia, what is the chance their future child will also be affected?

• A) 0%

• B) 25%

• C) 50%

• D) 100%
Rationale: Alpha thalassemia is an autosomal recessive disorder. When both parents are
carriers (heterozygous), each child has a 25% chance of inheriting two mutated genes and
being affected, a 50% chance of being a carrier, and a 25% chance of being unaffected .

Información del documento

Subido en
8 de agosto de 2026
Número de páginas
25
Escrito en
2026/2027
Tipo
Examen
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