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TM111 TMA 02 MARKED ASSIGNMENT WITH TUTOR FEEDBACK | QUESTIONS AND ANSWERS | 2026 UPDATE | 100% CORRECT

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Your TM111 TMA 02 – Marked, Explained & Ready to Learn From! This is the actual TM111 TMA 01 assignment with real tutor feedback, correct answers, and detailed rationales. No guessing. No stress. Just exactly what you need to understand what your tutor is looking for. What's Inside: - All 47 TMA 01 questions – fully covered - Tutor feedback with detailed rationales – see why answers are correct - Correct answers verified – 100% reliable - Multiple-choice format with clear explanations for each option - Easy to read on your phone, tablet, or laptop - Perfect for understanding OU marking style and exam technique What You'll Actually Learn: - Binary arithmetic and two's complement representation - IEEE 754 floating-point representation - Data compression – lossless vs lossy, perceptual coding - Networking – ARP, UDP vs TCP, subnetting, broadcast addresses - Cryptography – asymmetric encryption, RSA, public/private keys - Web technologies – HTML5 semantics, CSS specificity, hex colors - Python programming – list comprehensions, mutable default arguments - Algorithm analysis – time complexity, Big-O notation - Computational thinking – abstraction, decomposition, pattern recognition - Relational databases – SQL queries, selection and projection - Hamming codes and error detection - Flowcharts and pseudocode - Digital logic – XOR gates - Accessibility – WCAG principles - Professional skills – phishing awareness, file management, APA citations, Gibbs' Reflective Cycle Real Questions You'll See: Question: In binary addition of two 4-bit signed integers using two's complement, the carry into the most significant bit is 1 and the carry out is 0. Which statement is true? ️ Answer: Overflow has occurred. (Carry-in differs from carry-out indicates overflow) Question: In IEEE 754 single-precision floating point, the exponent is stored with a bias of 127. If the stored exponent bits are , what is the actual exponent value? ️ Answer: 7 ( = 7) Question: A 7-bit Hamming code with parity bits at positions 1,2,4 is used for error detection. If the received codeword is 1011010, which bit (if any) is in error? ️ Answer: Bit 5 Who This Is For: - You, if you're studying TM111 with The Open University - You, if TMA 01 is coming up and you're stressed - You, if you want to see exactly how a marked assignment looks - You, if you want to boost your grade by learning from real tutor feedback - You, if you want to understand the *why* behind every answer Stop guessing. Start understanding. Download this now and walk into TMA 01 with confidence.

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TM111 TMA 02 Marked Assignment with Tutor Feedback |
Questions and Answers | 2026 Update | 100% Correct - The Open
University. - 77 Questions and Answers Already Graded A+
Premium Exam Tested And Verified


Subject Area TM111 TMA 02 Marked Assignment with Tutor Feedback | Questions and
Answers | 2026 Update | 100% Correct - The Open University.

Description Comprehensive examination on TM111 TMA 02 Marked Assignment with Tutor
Feedback | Questions and Answers | 2026 Update | 100% Correct - The Open
University..

Expected Grade A+

Total Questions 77

Duration 3 hours

Learning Outcomes 1. Demonstrate mastery of core concepts

Accreditation Aligned with US university standards.




Page 1

,Question 1 of 77
Convert the decimal number 23.375 to binary. Which of the following is its correct binary
representation?
A. 10111.011
B. 10111.101
C. 10011.011
D. 10111.110


The correct answer is:
Correct Action: 10111.011

Rationales
• 10111.011 (Correct):
This is the correct action. 23 in binary is 10111 (16+4+2+1). 0.375 in binary is 0.011 (0.5*0 + 0.25*1 + 0.125*1 = 0.375).
Combined: 10111.011. Option B has fraction 0.625, C has integer 19, D has fraction 0.75.
• 10111.101 (Incorrect):
This option is not appropriate. 0.375 in binary is 0
• 10011.011 (Incorrect):
This option is not appropriate. 0.375 in binary is 0
• 10111.110 (Incorrect):
This option is not appropriate. 0.375 in binary is 0




Page 2

,Question 2 of 77
A researcher wants to find documents that discuss either 'machine learning' or 'artificial
intelligence' but must also include 'ethics' and not include 'deep learning'. Which Boolean query
correctly represents this search?
A. (machine learning OR artificial intelligence) AND ethics NOT deep learning
B. (machine learning OR artificial intelligence) AND ethics AND NOT deep learning
C. (machine learning AND artificial intelligence) OR ethics NOT deep learning
D. machine learning OR artificial intelligence AND ethics NOT deep learning


The correct answer is:
Correct Action: (machine learning OR artificial intelligence) AND ethics AND NOT deep learning

Rationales
• (machine learning OR artificial intelligence) AND ethics AND NOT deep learning (Correct):
This is the correct action. Option B correctly uses parentheses for the OR group, then AND with ethics, and AND NOT to
exclude deep learning. Option A lacks an explicit AND before NOT, which may be ambiguous. Options C and D misgroup
terms, leading to incorrect results.
• (machine learning OR artificial intelligence) AND ethics NOT deep learning (Incorrect):
This option is not appropriate. Option A lacks an explicit AND before NOT, which may be ambiguous. Options C and D
misgroup terms, leading to incorrect results
• (machine learning AND artificial intelligence) OR ethics NOT deep learning (Incorrect):
This option is not appropriate. Option A lacks an explicit AND before NOT, which may be ambiguous. Options C and D
misgroup terms, leading to incorrect results
• machine learning OR artificial intelligence AND ethics NOT deep learning (Incorrect):
This option is not appropriate. Option A lacks an explicit AND before NOT, which may be ambiguous. Options C and D
misgroup terms, leading to incorrect results




Page 3

, Question 3 of 77
Consider the following recursive function f(n) where n is a non-negative integer. What is the output
of f(5)?
def f(n):
if n < 2:
return n
else:
return f(n-1) + f(n-2)
A. 5
B. 8
C. 13
D. 21


The correct answer is:
Correct Action: 5

Rationales
• 5 (Correct):
This is the correct action. This implements the Fibonacci sequence: f(0)=0, f(1)=1, f(2)=1, f(3)=2, f(4)=3, f(5)=5. Option A
is correct; B is f(6), C is f(7), D is f(8).
• 8 (Incorrect):
This option is not appropriate. Option A is correct; B is f(6), C is f(7), D is f(8).
• 13 (Incorrect):
This option is not appropriate. Option A is correct; B is f(6), C is f(7), D is f(8).
• 21 (Incorrect):
This option is not appropriate. Option A is correct; B is f(6), C is f(7), D is f(8).




Page 4

Información del documento

Subido en
1 de agosto de 2026
Número de páginas
78
Escrito en
2026/2027
Tipo
Examen
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Preguntas y respuestas
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