NABCEP PV ASSOCIATE PRACTICE
SOLUTION TEST 2026 COMPLETE
QUESTIONS AND ANSWERS GRADED A+
●● 1. NEC section ________ shows the requirements for working
spaces around live electrical equipment?.
Answer: 110.26
●● 2. What is the maximum latitude at which the sun can achieve a 90º
altitude angle?.
Answer: 2. Answer: b. Approx. 23.45º north and south of the equator,
but like magnetic declination, the latitude of the Tropics varies over
time.
●● 3. If the open circuit voltage of a polycrystalline silicon PV module
is 37.0V, the module Vmp is 29.9V, the inverter max voltage is 600VDC
and its MPPT voltage range is 300 to 480VDC, and the minimum
temperature is -24°C. What is the maximum number of modules per
source circuit according to the NEC? List the NEC section where the
answer is found..
Answer: 3. Answer C: 37V x 1.20 = 44.4V
600V max ÷ 44.4V = 13.4 → 13 modules
NEC Table 690.7 - 1.20 correction factor
,●● 4. A PV array of Suniva 300 Watt modules consists of 3 rows and 10
columns of racked modules mounted in landscape and facing south at
latitude 30°. The modules are tilted at 20⁰. The mounting posts are
installed 3 ft. deep. How long must the posts be? Module dimensions are
77.6" x 38.7"..
Answer: Answer: C Sin(angle) = opposite ÷ hypotenuse
Sin(20⁰) = Height ÷ 38.7" x 3
Height = sin(20⁰) x 116.1"
Height = 0.342 x 116.1" = 39.7 "
39.7" + 36" = 75.7
●● An array located at 30⁰N latitude consists of two rows racked facing
south. Both rows are on a level surface and the height from the ground to
the highest point on the module is 39.7". Calculate the minimum
distance in feet needed between rows so the modules will not be shaded
at 9AM on December 21. Use the sun chart provided..
Answer: Answer: b Tan(angle) = opposite ÷ adjacent where opposite is
array height and adjacent is row-to-row spacing
Tan(21°) = 39.7" ÷ Row-to-row
Row-to-row = 39.7" ÷ 0.384
Row-to-row = 103.4" or 8.6
●● 6. At 43⁰ North latitude on the winter solstice, the solar altitude angle
at noon is____..
Answer: d. 23.55⁰
, 90° - 43° (latitude) + (-23.45°) = 23.55°
For the Summer Solstice, the third number is +23.45°C, resulting in
70.45°.
For either equinox, the last number is zero.
●● 7. An array is comprised of 22 modules. Each module is 64.5" x
38.7" and weighs 44.1 lbs. The site will experience 50 psf. of uplift
force. What is the approximate total uplift on the array?.
Answer: 7. Answer: a. 19,000 lbs.
64.5" x 38.7" ÷ 144 sq. in/sq. ft. = 17.33 sq. ft.
17.33 sq. ft. x 22 modules x 50 psf = 19063 lbs.
●● 8. What is the temperature correction factor if the module correction
factor is -0.335 %/⁰C and the cell temperature is 54⁰C?.
Answer: 8. Answer: a. 0.903
1 + (-0.00335 x (54 - 25)) = 0.903
●● 9. A module has dimensions of 64.5" x 38.7" and is in a landscape
orientation on a flat roof. The position of the sun at 9am on Dec 21 is
11° elevation and 130° azimuth. What is the maximum tilt angle the
modules can have so that there is no inter-row shading. A 2 foot
walkway is required between adjacent rows?.
Answer: 9. Answer: a. 10° is the closest to 10.8°
Module width x SIN(tilt angle) = module height
SOLUTION TEST 2026 COMPLETE
QUESTIONS AND ANSWERS GRADED A+
●● 1. NEC section ________ shows the requirements for working
spaces around live electrical equipment?.
Answer: 110.26
●● 2. What is the maximum latitude at which the sun can achieve a 90º
altitude angle?.
Answer: 2. Answer: b. Approx. 23.45º north and south of the equator,
but like magnetic declination, the latitude of the Tropics varies over
time.
●● 3. If the open circuit voltage of a polycrystalline silicon PV module
is 37.0V, the module Vmp is 29.9V, the inverter max voltage is 600VDC
and its MPPT voltage range is 300 to 480VDC, and the minimum
temperature is -24°C. What is the maximum number of modules per
source circuit according to the NEC? List the NEC section where the
answer is found..
Answer: 3. Answer C: 37V x 1.20 = 44.4V
600V max ÷ 44.4V = 13.4 → 13 modules
NEC Table 690.7 - 1.20 correction factor
,●● 4. A PV array of Suniva 300 Watt modules consists of 3 rows and 10
columns of racked modules mounted in landscape and facing south at
latitude 30°. The modules are tilted at 20⁰. The mounting posts are
installed 3 ft. deep. How long must the posts be? Module dimensions are
77.6" x 38.7"..
Answer: Answer: C Sin(angle) = opposite ÷ hypotenuse
Sin(20⁰) = Height ÷ 38.7" x 3
Height = sin(20⁰) x 116.1"
Height = 0.342 x 116.1" = 39.7 "
39.7" + 36" = 75.7
●● An array located at 30⁰N latitude consists of two rows racked facing
south. Both rows are on a level surface and the height from the ground to
the highest point on the module is 39.7". Calculate the minimum
distance in feet needed between rows so the modules will not be shaded
at 9AM on December 21. Use the sun chart provided..
Answer: Answer: b Tan(angle) = opposite ÷ adjacent where opposite is
array height and adjacent is row-to-row spacing
Tan(21°) = 39.7" ÷ Row-to-row
Row-to-row = 39.7" ÷ 0.384
Row-to-row = 103.4" or 8.6
●● 6. At 43⁰ North latitude on the winter solstice, the solar altitude angle
at noon is____..
Answer: d. 23.55⁰
, 90° - 43° (latitude) + (-23.45°) = 23.55°
For the Summer Solstice, the third number is +23.45°C, resulting in
70.45°.
For either equinox, the last number is zero.
●● 7. An array is comprised of 22 modules. Each module is 64.5" x
38.7" and weighs 44.1 lbs. The site will experience 50 psf. of uplift
force. What is the approximate total uplift on the array?.
Answer: 7. Answer: a. 19,000 lbs.
64.5" x 38.7" ÷ 144 sq. in/sq. ft. = 17.33 sq. ft.
17.33 sq. ft. x 22 modules x 50 psf = 19063 lbs.
●● 8. What is the temperature correction factor if the module correction
factor is -0.335 %/⁰C and the cell temperature is 54⁰C?.
Answer: 8. Answer: a. 0.903
1 + (-0.00335 x (54 - 25)) = 0.903
●● 9. A module has dimensions of 64.5" x 38.7" and is in a landscape
orientation on a flat roof. The position of the sun at 9am on Dec 21 is
11° elevation and 130° azimuth. What is the maximum tilt angle the
modules can have so that there is no inter-row shading. A 2 foot
walkway is required between adjacent rows?.
Answer: 9. Answer: a. 10° is the closest to 10.8°
Module width x SIN(tilt angle) = module height
