www.PlusBay.Plus
,www.PlusBay.Plus
,Chapter 1: Arithmetic Needed for Dosage
sl sl sl sl sl
MULTIPLE CHOICE s l
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
able to drink 1 5 oz. What portion of the water remained?
s l sl s l s l s l s l s l s l s l s l s l
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A
Feedback: Subtract the quantity of water the client drank (15 oz) from the total
s l s l s l s l s l s l s l s l s l s l s l s l s l s l
available quantity (25 oz): 10 oz remain. To determine the portion of the water that remain
sl s l s l s l s l s l s l sl s l s l s l s l s l s l s l
s, create a fr action by divi ding 10 oz (remaining portion) by 25 oz (total portion).
s l s l sl sl s l s l s l s l s l s l s l s l s l s l s l s l s l
Therefore, 10 divid ed by 25 = 10/25. To reduce fractions, find the largest number
s l s l sl s l s l s l s l s l sl s l s l s l s l s l s l
that can be divided evenly into the numerator and the de nominator
s l s l s l s l sl s l s l s l s l s l sl
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its l
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
owest terms of 2/5. sl s l sl
Format: Multiple Choice Chapt sl sl s l sl
er: 1 sl
Client Needs: Physiological Integrity: Basic Care and Comfort Cogn
sl sl sl sl sl sl sl sl
itive Level: Apply sl sl
Difficulty: Moderate sl
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte gr
sl sl sl sl sl sl sl sl sl sl
ated Process: Teaching/Learning sl sl
Objective: 1, 2 s l s l
2. A patient/client was prescribed 2 4 0 WmWL Wo f. ETnB
sl suSreMb.yWmSouth as a supplement but consumed onl s l sl sl x sl s l sl sl sl sl sl sl
y 100 mL. What portion of the Ensure remained?
sl sl sl sl sl sl sl sl
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the
s l s l s l s l s l s l s l s l s l s l s l s l s l
total available quantity (240 mL): 140 mL remain. To determine the portion of the
sl s l s l s l s l s l s l s l s l s l s l s l s l s l
Ensure that remains, create a fraction by dividing 140 mL (remaining portion) by 240 mL
s l sl s l s l s l s l s l s l s l s l s l s l s l s l s l
(total portion). Therefore, 140 divided by 240 = 7/12. To reduce fractions, find the larg
s l sl s l s l s l s l s l s l s l s l s l s l s l s l
est number that can be divided evenly into the nu merator and the denominator (20);
s l s l s l sl s l s l s l s l s l s l s l s l s l s l s
140 divided by 20 (140/2 0) = 7; 240/20 = 12. The fraction 140
l s l s l s l s l sl s l s l s l s l s l s l s l s l
/240 can be reduced to its lowest terms of 7/12.
s l s l s l s l s l s l s l s l s l
Format: Multiple Choice Chapt sl sl s l sl
er: 1 sl
Client Needs: Physiological Integrity: Basic Care and Comfort Cogn
sl sl sl sl sl sl sl sl
itive Level: Apply sl sl
Difficulty: Moderate sl
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte gr
sl sl sl sl sl sl sl sl sl sl
ated Process: Teaching/Learning sl sl
Objective: 1, 2 s l s l
1
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sl sl s l s l s l
, 3. A patient/client consumed
s l oz. of coffee, 2/3 oz. of ice cream, and s l s l s l s l s l s l s l s l s l
oz. of beef broth. What is the total number of ounces consumed that should be do
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
cument ed for t he patient/client? sl s l s l sl sl
a. 3 3/4 s l
b. 4 5/12 s l
c. 4 2/3 s l
d. 4 4/9 s l
ANS: B s l s l
Feedback: Add the amount of ounces consumed. First, change any mixed number t s l s l s l s l s l s l s l s l s l s l s l s l
o a fra ction by multiplying the whole number by the denominator and then adding that total t
s l s l sl s l sl sl s l s l s l sl s l s l sl s l s l s l s l
o the n umerator. For t he coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2
sl s l sl s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s
l 1 s l
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denomi
s l s l s l s l s l s l s l s l s l s l sl s l s l s l sl s l s l s l s l sl
nators, find the least common denominator (LCD). For 2, 3, and 4, the LCD =
s l s l s l s l s l s l s l s l s l s l s l s l s l s l
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fracti
s l s l s l sl sl s l s l s l s l s l s l s l s l s l s l
on a nd t hen multiply that result by the numerator of the fraction. The new fractio
s l sl s l s l s l s l s l s l s l s l s l s l s l s l s l s l
ns to be ad ded are 27/12 (coffee), 8/12 (ice cream), and 18/12 (beef broth). After conversi
s l s l s l sl s l s l sl s l s l s l s l s l s l s l s l s l
on of the fra ctions, the numerators are added together and the fraction is reduced to
s l s l s l sl s l s l s l s l s l s l s l s l s l s l s l
s the lowest terms.
l s l s l
Format: Multiple Choice Chapt sl sl s l sl
er: 1 sl
Client Needs: Physiological Integrity: Basic Care and Comfort Cogn
sl sl sl sl sl sl sl sl
itive Level: Analyze sl sl
Difficulty: Difficult s l
Page and Header: 2, Multiplying Whole Numbers; 3, Fraction
s l s l s l s l s l s l s l s l
s I ntegrated Process: Communication and Documentation Object i
sl sl sl sl sl sl sl sl
v e: 1, 2
sl sl sl
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many millilit
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
ers would sl
the nurse document as consu
s l s l s l s l
WWW.TBSM.WS
m ed sl
?
a. 360
b. 420
c. 510
d. 600
ANS: B
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the tot s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
al nu mber of milliliters consumed, multiply 180 7/3 (
s l sl s l s l s l sl sl sl s l sl
). When a mixed number is present, change it to an improper fraction by multiplying t
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
he who le nu s l sl s l
mber by the denominator and then adding that total to
s l s l s l s l s l s l s l s l s l
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
s = 60 ×
l s l s l
7 = 420). s l s l
Format: Multiple Choice Chapt sl sl s l sl
er: 1 sl
Client Needs: Physiological Integrity: Basic Care and Comfort Cogn
sl sl sl sl sl sl sl sl
itive Level: Analyze sl sl
Difficulty: Difficult s l
Page and Header: 2, Multiplying Whole Numbers; 3, Fraction
s l s l s l s l s l s l s l s l
s I ntegrated Process: Communication and Documentation Object i
sl sl sl sl sl sl sl sl
2
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sl sl s l s l s l
,www.PlusBay.Plus
,Chapter 1: Arithmetic Needed for Dosage
sl sl sl sl sl
MULTIPLE CHOICE s l
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
able to drink 1 5 oz. What portion of the water remained?
s l sl s l s l s l s l s l s l s l s l s l
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A
Feedback: Subtract the quantity of water the client drank (15 oz) from the total
s l s l s l s l s l s l s l s l s l s l s l s l s l s l
available quantity (25 oz): 10 oz remain. To determine the portion of the water that remain
sl s l s l s l s l s l s l sl s l s l s l s l s l s l s l
s, create a fr action by divi ding 10 oz (remaining portion) by 25 oz (total portion).
s l s l sl sl s l s l s l s l s l s l s l s l s l s l s l s l s l
Therefore, 10 divid ed by 25 = 10/25. To reduce fractions, find the largest number
s l s l sl s l s l s l s l s l sl s l s l s l s l s l s l
that can be divided evenly into the numerator and the de nominator
s l s l s l s l sl s l s l s l s l s l sl
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its l
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
owest terms of 2/5. sl s l sl
Format: Multiple Choice Chapt sl sl s l sl
er: 1 sl
Client Needs: Physiological Integrity: Basic Care and Comfort Cogn
sl sl sl sl sl sl sl sl
itive Level: Apply sl sl
Difficulty: Moderate sl
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte gr
sl sl sl sl sl sl sl sl sl sl
ated Process: Teaching/Learning sl sl
Objective: 1, 2 s l s l
2. A patient/client was prescribed 2 4 0 WmWL Wo f. ETnB
sl suSreMb.yWmSouth as a supplement but consumed onl s l sl sl x sl s l sl sl sl sl sl sl
y 100 mL. What portion of the Ensure remained?
sl sl sl sl sl sl sl sl
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the
s l s l s l s l s l s l s l s l s l s l s l s l s l
total available quantity (240 mL): 140 mL remain. To determine the portion of the
sl s l s l s l s l s l s l s l s l s l s l s l s l s l
Ensure that remains, create a fraction by dividing 140 mL (remaining portion) by 240 mL
s l sl s l s l s l s l s l s l s l s l s l s l s l s l s l
(total portion). Therefore, 140 divided by 240 = 7/12. To reduce fractions, find the larg
s l sl s l s l s l s l s l s l s l s l s l s l s l s l
est number that can be divided evenly into the nu merator and the denominator (20);
s l s l s l sl s l s l s l s l s l s l s l s l s l s l s
140 divided by 20 (140/2 0) = 7; 240/20 = 12. The fraction 140
l s l s l s l s l sl s l s l s l s l s l s l s l s l
/240 can be reduced to its lowest terms of 7/12.
s l s l s l s l s l s l s l s l s l
Format: Multiple Choice Chapt sl sl s l sl
er: 1 sl
Client Needs: Physiological Integrity: Basic Care and Comfort Cogn
sl sl sl sl sl sl sl sl
itive Level: Apply sl sl
Difficulty: Moderate sl
Page and Header: 2, Dividing Whole Numbers; 3, Fractions Inte gr
sl sl sl sl sl sl sl sl sl sl
ated Process: Teaching/Learning sl sl
Objective: 1, 2 s l s l
1
www.PlusBay.Plus | P a g e
sl sl s l s l s l
, 3. A patient/client consumed
s l oz. of coffee, 2/3 oz. of ice cream, and s l s l s l s l s l s l s l s l s l
oz. of beef broth. What is the total number of ounces consumed that should be do
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
cument ed for t he patient/client? sl s l s l sl sl
a. 3 3/4 s l
b. 4 5/12 s l
c. 4 2/3 s l
d. 4 4/9 s l
ANS: B s l s l
Feedback: Add the amount of ounces consumed. First, change any mixed number t s l s l s l s l s l s l s l s l s l s l s l s l
o a fra ction by multiplying the whole number by the denominator and then adding that total t
s l s l sl s l sl sl s l s l s l sl s l s l sl s l s l s l s l
o the n umerator. For t he coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2
sl s l sl s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s
l 1 s l
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denomi
s l s l s l s l s l s l s l s l s l s l sl s l s l s l sl s l s l s l s l sl
nators, find the least common denominator (LCD). For 2, 3, and 4, the LCD =
s l s l s l s l s l s l s l s l s l s l s l s l s l s l
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fracti
s l s l s l sl sl s l s l s l s l s l s l s l s l s l s l
on a nd t hen multiply that result by the numerator of the fraction. The new fractio
s l sl s l s l s l s l s l s l s l s l s l s l s l s l s l s l
ns to be ad ded are 27/12 (coffee), 8/12 (ice cream), and 18/12 (beef broth). After conversi
s l s l s l sl s l s l sl s l s l s l s l s l s l s l s l s l
on of the fra ctions, the numerators are added together and the fraction is reduced to
s l s l s l sl s l s l s l s l s l s l s l s l s l s l s l
s the lowest terms.
l s l s l
Format: Multiple Choice Chapt sl sl s l sl
er: 1 sl
Client Needs: Physiological Integrity: Basic Care and Comfort Cogn
sl sl sl sl sl sl sl sl
itive Level: Analyze sl sl
Difficulty: Difficult s l
Page and Header: 2, Multiplying Whole Numbers; 3, Fraction
s l s l s l s l s l s l s l s l
s I ntegrated Process: Communication and Documentation Object i
sl sl sl sl sl sl sl sl
v e: 1, 2
sl sl sl
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many millilit
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
ers would sl
the nurse document as consu
s l s l s l s l
WWW.TBSM.WS
m ed sl
?
a. 360
b. 420
c. 510
d. 600
ANS: B
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the tot s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
al nu mber of milliliters consumed, multiply 180 7/3 (
s l sl s l s l s l sl sl sl s l sl
). When a mixed number is present, change it to an improper fraction by multiplying t
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
he who le nu s l sl s l
mber by the denominator and then adding that total to
s l s l s l s l s l s l s l s l s l
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3
s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l s l
s = 60 ×
l s l s l
7 = 420). s l s l
Format: Multiple Choice Chapt sl sl s l sl
er: 1 sl
Client Needs: Physiological Integrity: Basic Care and Comfort Cogn
sl sl sl sl sl sl sl sl
itive Level: Analyze sl sl
Difficulty: Difficult s l
Page and Header: 2, Multiplying Whole Numbers; 3, Fraction
s l s l s l s l s l s l s l s l
s I ntegrated Process: Communication and Documentation Object i
sl sl sl sl sl sl sl sl
2
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sl sl s l s l s l
