Portage Learning CHEM 103 chemistry EXAM A+ GRADE ASSURED COMPLETE SOLUTIONS AND VERIFIED ANSWERS LATEST UPDATE!!!!

PORTAGE LEARNING EXAM zm zm




Exam Solution
zm




Portage Learning Chemistry CHEM 103 Unit 4 2026 A+ zm zm zm zm zm zm zm zm zm




GRADE ASSURED COMPLETE SOLUTIONS AND VERIFIE zm zm zm zm zm




D ANSWERS (9D847)
zm zm




QUESTION 1 zm




19K = 1s2 2s2 2p6 3s2 3p6 4s1 35Br = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm




ANSWER

Write electron (subshell) configurations for the following atoms: 19K 35Br
zm zm zm zm zm zm zm zm zm




QUESTION 2 zm




15P = 1s22s22p63s23p3 ↑↓ ↑↓ ↑↓↑↓↑↓ ↑↓ ↑ ↑ ↑ 1s 2s 2p 3s 3p 28Ni = 1s22s22p63s23p6
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



4s23d8 ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ 1s 2s 2p 3s ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ ↑ ↑ 3p 4s 3d
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm




ANSWER

Write orbital diagrams for the following atoms: 15P 28Ni
zm zm zm zm zm zm zm zm




QUESTION 3 zm




A 4d8 electron is in the 4th shell so n = 4. Its "d" orbital has 2 nodal planes so l = 2.
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



The electron is in the 3rd of the orbitals of the d subshell so ml = 0. And since this is
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



the 2nd electron to occupy this "d" orbital, ms = -
zm zm zm zm zm zm zm zm zm zm



1/2. In summary, the values for the four quantum numbers for the 4d8 electron are:
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



n = 4, l = 2, ml = 0 and ms = -1/2.
zm zm zm zm zm zm zm zm zm zm zm zm




ANSWER

Write the values for the four quantum numbers for a 4d8 electron.
zm zm zm zm zm zm zm zm zm zm zm




QUESTION 4 zm

, The last electron to fill 28Ni is a 3d8 electron which is in the 3rd shell so n = 3. Its "d
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



" orbital has 2 nodal planes so l = 2. The electron is in the 3rd of the orbitals of the d
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



zmsubshell so ml = 0. And since this is the 2nd electron to occupy this "d" orbital, ms =
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



-
1/2. In summary, the values for the four quantum numbers for the 3d8 electron are:
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



n = 3, l = 2, ml = 0 and ms = -1/2.
zm zm zm zm zm zm zm zm zm zm zm zm




ANSWER

Write the values for the four quantum numbers for the last electron to fill 28Ni.
zm zm zm zm zm zm zm zm zm zm zm zm zm zm




QUESTION 5 zm




B has the highest ionization energy since it is farthest to right of these elements and i
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



onization energy increases as you go from left to right in a period.
zm zm zm zm zm zm zm zm zm zm zm zm




ANSWER

Choose the atom that matches the identified atomic property and explain your answer based on the
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



periodic trend and its position within a group or period in the periodic tableLinks to an external sit
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



e.. Highest Ionization Energy: Li, Be, B
zm zm zm zm zm zm




QUESTION 6 zm




Li has the lowest electronegativity since it is farthest to left of these elements and ele
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



ctronegativity increases as you go from left to right in a period.
zm zm zm zm zm zm zm zm zm zm zm




ANSWER

Choose the atom that matches the identified atomic property and explain your answer based on the
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



periodic trend and its position within a group or period in the periodic table. Lowest Electronegativi
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



ty: Li, Be, B
zm zm zm




QUESTION 7 zm




Li has the largest atomic size since it is farthest to left of these elements and atomic s
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



ize decreases as you go from left to right in a period.
zm zm zm zm zm zm zm zm zm zm zm




ANSWER

Choose the atom that matches the identified atomic property and explain your answer based on the
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



periodic trend and its position within a group or period in the periodic table. Largest Atomic Size: L
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm



i, Be, B
zm zm




QUESTION 8 zm




16S = 1s22s22p63s23p4 ↑↓ ↑↓ ↑↓↑↓↑↓ ↑↓ ↑↓ ↑ ↑ 1s 2s 2p 3s 3p . : S : .
zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm zm




ANSWER