SAN2602 Assignment 1 |COMPLETE SOLUTIONS| - DUE 25 MAY 2026

SAN2602
Assignment 1
DUE: 25 MAY 2026

, Assessment 1
Due Date: 25 May 2026
Time: 18:00



Question 1 [30 Marks]

1.1 Calculate the reactions at A and D [9 Marks]

The frame has a pin support at A (𝐴𝑥 , 𝐴𝑦 ) and a pin support at D (𝐷𝑥 , 𝐷𝑦 ). There is an internal
hinge at the beam-to-beam connection.

Total External Loads:

• Horizontal: 10 kN(→) + 25 kN(→) − 15 kN(←) = 20 kN(→).

• Vertical (UDL): 20 kN/m × (4 m + 2 m + 2 m) = 20 × 8 = 160 kN(↓).

Moment about A (∑𝑀𝐴 = 0): Using clockwise as positive:

(20 × 8) × 4 + (15 × 3.5) − (25 × 6) − (10 × 1) − (𝐷𝑦 × 6) − (𝐷𝑥 × 1) = 0

Note: 𝐷 is 1 m higher than 𝐴. Point 𝐶 is 5 m above 𝐷.

Use Hinge at mid-span to split the structure: Taking moments about the hinge for the right-
hand side (Hinge-C-E-D):

∑𝑀𝐻𝑖𝑛𝑔𝑒(𝑅𝑖𝑔ℎ𝑡) = 0

(20 × 4) × 2 + (15 × 2.5) − (𝐷𝑦 × 2) + (𝐷𝑥 × 5) = 0

Solving the simultaneous equations for reactions:

• 𝐴𝑥 = 10.83 kN(←)

• 𝐴𝑦 = 86.25 kN(↑)

• 𝐷𝑥 = 9.17 kN(←)

• 𝐷𝑦 = 73.75 kN(↑)