JOURNEYMAN ELECTRICIAN THEORY PRACTICE TEST 2026 | COMPLETE
EXAM PREP QUESTIONS & ANSWERS | LATEST UPDATED STUDY GUIDE
WITH VERIFIED SOLUTIONS
A 240V, 24A, SINGLE-PHASE LOAD IS LOCATED 160 FT FROM THE PANELBOARD. THE LOAD IS
WIRED WITH 10 AWG CONDUCTORS. WHAT'S THE APPROXIMATE VOLTAGE DROP OF THE
BRANCH-CIRCUIT CONDUCTORS?
A. 3.2V
B. 4.25V
C. 5.9V
D. 9.5V
CORRECT ANS: D. 9.5V
VD = (2 X K X I X D)/CMIL
K = 12.90, COPPER
I = 24A
D = 160 FT
CMIL = 10,380
VD = (2 WIRES X 12.90 X 24A X 160 FT)/10,380 CMIL
VD = 9.50V
DURING NORMAL OPERATION OF A TYPICAL 120-VOLT APPLIANCE CIRCUIT, CURRENT FLOWS
THROUGH THE HOT, GROUNDING, AND NEUTRAL CONDUCTORS.
A. TRUE
B. FALSE
, CORRECT ANS: B. FALSE
AN RLC SERIES CIRCUIT HAS AN APPLIED VOLTAGE OF 240 VOLTS. R = 48 Ω, XL = 100 Ω, XC = 36
Ω, AND Z = 80 Ω. WHAT IS THE TOTAL CURRENT?
A. 1 A
B. 2 A
C. 3 A
D. 4 A
CORRECT ANS: C. 3 A
240/80 = 3
WHAT'S THE DIRECT-CURRENT RESISTANCE OF A 6 AWG COPPER CONDUCTOR THAT'S 400 FT
LONG?
A. 0.20 OHMS
B. 0.30 OHMS
C. 0.40 OHMS
D. 0.50 OHMS
CORRECT ANS: A. 0.20 OHMS
6 AWG RESISTANCE = 0.491 OHMS/1,000 FT [CHAPTER 9, TABLE 8]
(0.491 OHMS/1,000 FT) X 400 FT = 0.1964 OHMS
EXAM PREP QUESTIONS & ANSWERS | LATEST UPDATED STUDY GUIDE
WITH VERIFIED SOLUTIONS
A 240V, 24A, SINGLE-PHASE LOAD IS LOCATED 160 FT FROM THE PANELBOARD. THE LOAD IS
WIRED WITH 10 AWG CONDUCTORS. WHAT'S THE APPROXIMATE VOLTAGE DROP OF THE
BRANCH-CIRCUIT CONDUCTORS?
A. 3.2V
B. 4.25V
C. 5.9V
D. 9.5V
CORRECT ANS: D. 9.5V
VD = (2 X K X I X D)/CMIL
K = 12.90, COPPER
I = 24A
D = 160 FT
CMIL = 10,380
VD = (2 WIRES X 12.90 X 24A X 160 FT)/10,380 CMIL
VD = 9.50V
DURING NORMAL OPERATION OF A TYPICAL 120-VOLT APPLIANCE CIRCUIT, CURRENT FLOWS
THROUGH THE HOT, GROUNDING, AND NEUTRAL CONDUCTORS.
A. TRUE
B. FALSE
, CORRECT ANS: B. FALSE
AN RLC SERIES CIRCUIT HAS AN APPLIED VOLTAGE OF 240 VOLTS. R = 48 Ω, XL = 100 Ω, XC = 36
Ω, AND Z = 80 Ω. WHAT IS THE TOTAL CURRENT?
A. 1 A
B. 2 A
C. 3 A
D. 4 A
CORRECT ANS: C. 3 A
240/80 = 3
WHAT'S THE DIRECT-CURRENT RESISTANCE OF A 6 AWG COPPER CONDUCTOR THAT'S 400 FT
LONG?
A. 0.20 OHMS
B. 0.30 OHMS
C. 0.40 OHMS
D. 0.50 OHMS
CORRECT ANS: A. 0.20 OHMS
6 AWG RESISTANCE = 0.491 OHMS/1,000 FT [CHAPTER 9, TABLE 8]
(0.491 OHMS/1,000 FT) X 400 FT = 0.1964 OHMS
